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If the lobes of a given \(d\) -orbital point directly at the ligands, will an electron in that orbital have a higher or lower energy than an electron in a \(d\) -orbital whose lobes do not point directly at the ligands?

Short Answer

Expert verified
An electron in a \(d\)-orbital whose lobes point directly at the ligands, such as the \(e_{g}\) set, will have a higher energy level due to stronger interactions with the ligands. On the other hand, an electron in a \(d\)-orbital whose lobes do not point directly at the ligands, like the \(t_{2g}\) set, will have a lower energy level due to weaker interactions with the ligands.

Step by step solution

01

Crystal Field Theory

To understand the effect of ligands on the energy levels of \(d\)-orbitals, we need to refer to the Crystal Field Theory (CFT). CFT explains the energy splitting of degenerate \(d\)-orbitals in transition metal complexes due to the interaction between the central metal ion and its surrounding ligands. When ligands approach the central metal ion, the electrostatic repulsion between the electrons in the \(d\)-orbitals and the negatively charged ligands causes a change in the energies of the \(d\)-orbitals.
02

Energy Splitting of \(d\)-Orbitals

In an octahedral complex, the five degenerate \(d\)-orbitals split into two energy levels: three orbitals (dxy, dyz, and dxz) at a lower energy level, called \(t_{2g}\) set, and two orbitals (dx2-y2 and dz2) at a higher energy level, called \(e_{g}\) set. The difference in energy between these sets is called the crystal field splitting energy, denoted as \(\Delta_{O}\). In the \(t_{2g}\) set, the orbital lobes lie between the ligands, resulting in less interaction with the ligands. On the other hand, in the \(e_{g}\) set, the lobes are pointing directly at the ligands, resulting in a stronger interaction leading to higher energy levels.
03

Comparing Energy Levels

Now, we can compare the energy levels of electrons in the two \(d\)-orbital types as asked in the exercise. An electron in a \(d\)-orbital that points directly at the ligands (such as the \(e_{g}\) set) will interact more strongly with the ligands and will thus have a higher energy. Conversely, an electron in a \(d\)-orbital whose lobes do not point directly at the ligands (such as the \(t_{2g}\) set) will have less interaction and therefore a lower energy level. In conclusion, an electron in a \(d\)-orbital whose lobes point directly at the ligands will have a higher energy than an electron in a \(d\)-orbital whose lobes do not point directly at the ligands.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Splitting of d-Orbitals
In transition metal complexes, the arrangement and energy of the five so-called "d-orbitals" can change based on ligand interactions, a concept known as the "energy splitting of d-orbitals." Ordinarily, these orbitals would have the same energy level, known as being "degenerate." However, when they face an environment full of ligands, as seen in transition metal complexes, this degeneracy is lost. The presence of ligands causes the electrostatic repulsion forces between them and electrons in the d orbitals to shift the energy levels.
The fascinating part is that not all d orbitals react to this ligand presence equally. Three d orbitals (dxy, dyz, dxz) end up at a lower energy level due to their lobes being positioned between the ligands. These are collectively known as the "t_{2g} set." In contrast, the other two orbitals (dx^2-y^2 and dz^2) align directly with the ligands, pushing them to a higher energy level. This configuration is what’s called the "e_{g} set." Understanding this concept is crucial for explaining the behavior and reactivity of transition metal complexes.
Octahedral Complexes
A vital structure in crystal field theory, octahedral complexes are named for their geometric shape. In these complexes, the central metal ion is surrounded by six ligands arranged in an octahedron. Think of it like a cube where the metal ion occupies the center and each ligand sits on a corner.
Such an arrangement dramatically impacts the interactions within the d orbitals. Splitting of the energy levels occurs because of the distinct way ligands approach each of the five d orbitals. In an octahedral field, it's again about which orbitals face the ligands directly. This leads to significant differences in energy distribution across the d orbitals—directly impacting the stability and the color properties of the complex.
Octahedral complexes are quite common due to their favorable geometry that leads to lower energy and higher stability, making them key to studying transition metal chemistry. It’s their unique set-up that allows the characteristic splitting of the d orbitals, subsequently leading to diverse physical and chemical properties.
Crystal Field Splitting Energy
Crystal field splitting energy, often represented by \( \Delta_{O} \), is at the heart of understanding the energetics of d orbitals in a ligand field. This term refers to the energy difference between the higher energy \( e_{g} \) orbitals and the lower energy \( t_{2g} \) orbitals as a result of ligand interaction.
The magnitude of \( \Delta_{O} \) depends on several factors:
  • The metal ion itself, as different metals will offer varying electron configurations.
  • The nature of ligands; stronger field ligands, those higher in the spectrochemical series, will increase \( \Delta_{O} \).
  • The overall geometry of the complex, as this can change the degree of interaction with the ligands.
A larger \( \Delta_{O} \) value implies a strong interaction between ligands and metal ion's d orbitals, leading to greater differences between the energy levels of the involved orbitals. These differences can dictate the electronic configuration and spin states of the metal, influencing both its magnetic properties and its color. Understanding \( \Delta_{O} \) is key when studying and predicting the behavior of transition metal complexes.

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Most popular questions from this chapter

A classmate says, “A weak-field ligand usually means the complex is high spin." Is your classmate correct? Explain.

Sketch the structure of the complex in each of the following compounds and give the full compound name: (a) \(c i s-\left[\operatorname{PtBr} \mathrm{Cl}\left(\mathrm{NO}_{2}\right)_{2}\right]^{2-}\) (b) \(\left[\mathrm{Mn}(\mathrm{CO})_{3}\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\right]^{+}\) (c) \(\left.c i s-\left[\mathrm{Cr} \mathrm{Cl}_{4}\right)\left(\mathrm{OH}_{2}\right)_{2}\right]^{-}\) (d) trans-[Co(OH)(en) \(\left._{2} \mathrm{Cl}\right]^{+}\)

A Zn electrode is immersed in a solution that is \(1.00 \mathrm{M}\) in \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) and \(1.00 \mathrm{M}\) in \(\mathrm{NH}_{3}\). When the cathode is a standard hydrogen electrode, the emf of the cell is found to be \(+1.04 \mathrm{~V}\). What is the formation constant for \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+} ?\)

Consider the tetrahedral anions \(\mathrm{VO}_{4}^{3-}\) (orthovanadate ion), \(\mathrm{CrO}_{4}^{2-}\) (chromate ion), and \(\mathrm{MnO}_{4}^{-}\) (permanganate ion). (a) These anions are isoelectronic. What does this statement mean? (b) Would you expect these anions to exhibit d-d transitions? Explain. (c) As mentioned in "A Closer Look" on charge-transfer color, the violet color of \(\mathrm{MnO}_{4}\) is due to a ligand-to-metal charge transfer (LMCT) transition. What is meant by this term? (d) The LMCT transition in \(\mathrm{MnO}_{4}^{-}\) occurs at a wavelength of \(565 \mathrm{nm}\). The \(\mathrm{CrO}_{4}^{2-}\) ion is yellow. Is the wavelength of the LMCT transition for chromate larger or smaller than that for \(\mathrm{MnO}_{4}^{-}\) ? Explain. (e) The \(\mathrm{VO}_{4}^{3-}\) ion is colorless. Do you expect the light absorbed by the LMCT to fall in the UV or the IR region of the electromagnetic spectrum? Explain your reasoning.

Metallic elements are essential components of many important enzymes operating within our bodies. Carbonic anhydrase, which contains \(\mathrm{Zn}^{2+}\) in its active site, is responsible for rapidly interconverting dissolved \(\mathrm{CO}_{2}\) and bicarbonate ion, \(\mathrm{HCO}_{3}^{-}\). The zinc in carbonic anhydrase is tetrahedrally coordinated by three neutral nitrogencontaining groups and a water molecule. The coordinated water molecule has a \(\mathrm{p} K_{a}\) of \(7.5,\) which is crucial for the enzyme's activity. (a) Draw the active site geometry for the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase, just writing "N" for the three neutral nitrogen ligands from the protein. (b) Compare the \(\mathrm{p} K_{a}\) of carbonic anhydrase's active site with that of pure water; which species is more acidic? (c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the \(\mathrm{Zn}(\mathrm{II})\) center? Assume the three nitrogen ligands are unaffected. \((\mathbf{d})\) The \(\mathrm{p} K_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is \(10 .\) Suggest an explanation for the difference between this \(\mathrm{p} K_{a}\) and that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a deep color, like hemoglobin and other metal-ion-containing proteins do? Explain.

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