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Consider an octahedral complex, MA2 B4. How many geometric isomers are expected for this compound? Will any of the isomers be optically active? If so, which ones?

Short Answer

Expert verified
There are four geometric isomers for the octahedral complex MA2B4, with one cis and three trans configurations. Out of these, only one trans isomer (with one A ligand in an axial position and the other in an equatorial position) is optically active, as it lacks a plane of symmetry.

Step by step solution

01

Understanding the structure of an octahedral complex

An octahedral complex has a central metal atom (M) surrounded by six ligands. In this case, we have two ligands of type A and four ligands of type B. To determine the geometric isomers, we need to consider all the possible arrangements for the A and B ligands around the central metal atom.
02

Finding geometric isomers based on ligand positions

To find the geometric isomers, we will consider the following scenarios: 1. Both A ligands are next to each other (cis configuration). 2. Both A ligands are opposite to each other (trans configuration). Here are the possible geometric isomers: - Cis configuration: The two A ligands are adjacent, and the remaining four positions are occupied by B ligands. There is only one way to arrange the ligands in this configuration. - Trans configuration: The two A ligands are opposite each other, and the remaining four positions are occupied by B ligands. In this configuration, we have three possibilities (A ligands in axial position, A ligands in the equatorial position, A ligands in the axial and equatorial position). Hence, we have a total of 1+3=4 geometric isomers.
03

Identify optically active isomers

An optically active substance has the ability to rotate plane-polarized light. A molecule is optically active if it is not superimposable on its mirror image (i.e., it lacks a plane of symmetry). For the octahedral complex MA2B4: - Cis configuration: In this configuration, there is a plane of symmetry passing through the central metal atom and the two A ligands, making it optically inactive. Trans configuration: 1. Both A ligands are in axial positions: This configuration also has a plane of symmetry passing through the axial ligands and perpendicular to the equatorial plane, making this isomer optically inactive. 2. Both A ligands are opposite in the equatorial plane: This configuration has a plane of symmetry passing through the M atom and between A ligands; thus, this isomer is optically inactive. 3. A ligands are in one axial position and one equatorial position such that they are opposite: There is no plane of symmetry in this case, making this isomer optically active. In conclusion, there are four geometric isomers, and only one of them (one trans isomer with A ligands in one axial and one equatorial position) is optically active.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octahedral Complex
An octahedral complex is a fascinating structure in coordination chemistry. It involves a central metal atom surrounded by six ligands, which can be atoms, molecules, or ions. This six-ligand arrangement forms an octahedral shape, resembling two four-sided pyramids joined at their bases.

When considering the complex MA2 B4, it includes two ligands of type A and four ligands of type B. This set-up leads to the formation of different isomers based on the positioning of these ligands around the metal center.

  • **Cis Configuration**: Both A ligands are next to each other, with the remaining four positions filled by B ligands.
  • **Trans Configuration**: Both A ligands are opposite each other, resulting in three possible arrangements.
  • Axial positions for A ligands
  • Equatorial positions for A ligands
  • Combination of one axial and one equatorial position
Thus, this particular complex can produce four geometric isomers in total. Understanding the basic structure of octahedral complexes lays the foundation for further intriguing properties like optical activity.
Optical Activity
Optical activity is a property that occurs when a compound can rotate the plane of polarized light. This phenomenon arises due to molecular asymmetry, meaning the molecule cannot be superimposed on its mirror image, lacking a plane of symmetry.

In the world of chemistry, such molecules are chiral, which sources their unique optical properties. Not all isomers are optically active, but some can achieve this under specific arrangements. Optical activity is typically tested using polarimeters, devices designed to measure the degree of rotation of polarized light by optical isomers.

For the octahedral complex MA2B4, only one geometric isomer shows optical activity. This is the isomer where one A ligand occupies an axial and the other an equatorial position. This configuration lacks a reflective plane of symmetry, allowing it to rotate the plane of polarized light—evidence of its chiral nature.

Understanding which configurations are optically active helps in applications ranging from pharmaceuticals to materials science, where such properties are crucial.
Cis-Trans Isomerism
Cis-trans isomerism is a fascinating concept encountered in coordination chemistry, particularly when dealing with isomers in an octahedral complex. This type of isomerism depends on the angles and positioning of ligands around a central atom.

**Cis Isomers**: These occur when identical ligands are adjacent to each other. In the case of our complex MA2B4, this means the A ligands sit next to each other, sharing a bond angle.

**Trans Isomers**: These appear when identical ligands sit opposite each other. In the complex we're examining, trans configurations can yield three distinct isomers based on their position - all having unique spatial arrangements.

  • Cis isomer offers one configuration.
  • Trans isomer provides three configurations: axial, equatorial, and a mix of both.
These different configurations result in four possible geometric isomers. Among them, the trans isomer with one A ligand in an axial position and the other in an equatorial position does not have a plane of symmetry, rendering it optically active. Cis-trans isomerism offers fascinating insights into molecular architecture and is crucial for developing substances with specific properties.

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Most popular questions from this chapter

Crystals of hydrated chromium(III) chloride are green, have an empirical formula of CrCl36H2O, and are highly soluble, (a) Write the complex ion that exists in this compound. (b) If the complex is treated with excess AgNO3(aq), how many moles of AgCl will precipitate per mole of CrCl36H2O dissolved in solution? (c) Crystals of anhydrous chromium(III) chloride are violet and insoluble in aqueous solution. The coordination geometry of chromium in these crystals is octahedral, as is almost always the case for Cr3+. How can this be the case if the ratio of Cr to Cl is not 1:6?

A four-coordinate complex MA2 B2 is prepared and found to have two different isomers. Is it possible to determine from this information whether the complex is square planar or tetrahedral? If so, which is it?

Identify each of the following coordination complexes as either diamagnetic or paramagnetic: (a) [CoBr(NH3)5]2+ (b) [W(CN)6]3 (c) [VF6]3 (d) [Rh(ophen)3]3+

When Alfred Werner was developing the field of coordination chemistry, it was argued by some that the optical activity he observed in the chiral complexes he had prepared was due to the presence of carbon atoms in the molecule. To disprove this argument, Werner synthesized a chiral complex of cobalt that had no carbon atoms in it, and he was able to resolve it into its enantiomers. Design a cobalt(III) complex that would be chiral if it could be synthesized and that contains no carbon atoms. (It may not be possible to synthesize the complex you design, but we will not worry about that for now.)

For each of the following metals, write the electronic configuration of the atom and its 3+ ion: (a) Fe, (b) Mo, (c) Co. Draw the crystal-field energy-level diagram for the d orbitals of an octahedral complex, and show the placement of the d electrons for each 3+ ion, assuming a weak-field complex. How many unpaired electrons are there in each case?

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