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A four-coordinate complex \(\mathrm{MA}_{2} \mathrm{~B}_{2}\) is prepared and found to have two different isomers. Is it possible to determine from this information whether the complex is square planar or tetrahedral? If so, which is it?

Short Answer

Expert verified
From the given information that the complex MA₂B₂ has two different isomers, we can determine that the complex is square planar. This is because, in a square planar geometry, there can be two isomers - cis (A and B ligands are adjacent) and trans (A and B ligands are opposite). In contrast, a tetrahedral complex would have only one isomer with no distinction between cis or trans.

Step by step solution

01

Analyze the isomers in both geometries

Let's first analyze the possible isomers for both square planar and tetrahedral geometries. Square planar: - Cis: A and B ligands are adjacent to each other - Trans: A and B ligands are opposite each other Tetrahedral: - There are no separate cis or trans isomers, as all ligand positions are equivalent.
02

Compare the isomer possibilities to the given information

We have determined the possible isomers for both square planar and tetrahedral complexes. We are given that the complex has two different isomers. By comparing this information to our analysis, we can draw the following conclusions: - If the complex is square planar, it can have two isomers: cis and trans. - If the complex is tetrahedral, it has only one isomer, and no distinction between cis or trans.
03

Conclude the geometry

Since the given complex has two different isomers, it must be square planar, as the tetrahedral complex only has one isomer. Thus, the complex is square planar.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isomerism
Isomerism in coordination chemistry refers to the ability of a compound to exist in different forms, while having the same chemical formula. This is important because it affects the properties and reactivity of the compound. In the case of coordination complexes, isomers can arise from different arrangements of ligands around the central metal atom.

There are several types of isomerism in coordination compounds, but for four-coordinate complexes like \(\mathrm{MA}_2\mathrm{B}_2\), geometrical isomerism is key. Geometrical isomers, such as "cis" and "trans" forms, differ in the spatial arrangement of ligands. Understanding the type of isomerism can help us deduce the complex's geometry, which affects its potential uses in fields such as catalysis, and material science.
Square Planar Complex
Square planar complexes have a distinct geometry where four ligands form a plane around the central metal atom, positioned at the corners of a square. This type of geometry is common in some transition metal complexes, particularly for metals with a \(\mathrm{d}^8\) electronic configuration.

In a square planar arrangement, it’s possible to have "cis" and "trans" isomers:
  • Cis Isomer: Ligands of the same type are adjacent.
  • Trans Isomer: Ligands of the same type are opposite each other.
These arrangements affect the compound's properties significantly. For instance, they can influence solubility and color, which are crucial in applications like dye production and chemical sensors.

The presence of two distinct isomers, as in this problem, suggests a square planar structure, distinguishing it from other geometrical arrangements like tetrahedral.
Tetrahedral Complex
Tetrahedral complexes are another common coordination structure where four ligands are symmetrically arranged around the central metal atom, forming the vertices of a tetrahedron. This geometry is typical for ions such as \(\mathrm{Zn}^{2+}\) or \(\mathrm{Be}^{2+}\).

In tetrahedral complexes, all ligand positions are equivalent, which means there are no geometrical isomers like cis or trans. Each ligand is uniformly spaced, leading to a single possible isomer. This uniformity can impact the magnetic properties and reactivity of the complex, often leading to high-spin arrangements.

When asked about two different isomers, we can conclude that a tetrahedral geometry is not possible since it doesn't support isomerism in four-coordinate complexes like \(\mathrm{MA}_2\mathrm{B}_2\).
Ligand Arrangement
The arrangement of ligands around a central metal atom is pivotal in determining the complex's geometry and behavior. Ligands can be atoms, ions, or molecules, and their spatial distribution dictates the type of isomerism possible in a complex.

In four-coordinate complexes, the way these ligands are arranged results in different geometrical shapes: square planar or tetrahedral.
  • For a square planar complex, ligands align in a flat plane, allowing distinct cis and trans arrangements.
  • In a tetrahedral complex, ligands are spread equally in a three-dimensional space, making all positions equivalent.
Understanding ligand arrangement helps chemists predict the chemical and physical properties of the complex, such as its reactivity, catalytic abilities, and interactions with light. Such insights are crucial when designing compounds for specific functions in materials science, medicine, and industrial applications.

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Most popular questions from this chapter

Indicate the coordination number and the oxidation number of the metal for each of the following complexes: (a) \(\mathrm{K}_{2} \mathrm{PtCl}_{4}\) (b) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right] \mathrm{Br}_{2}\) (c) \(\mathrm{OsO}_{4}\) (d) \(\left[\mathrm{Mn}(\mathrm{en})_{3}\right]\left(\mathrm{NO}_{3}\right)_{2}\) (e) \(\left[\mathrm{Cr}(\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{3}\) (f) \(\left[\mathrm{Zn}(\mathrm{bipy})_{2}\right]\left(\mathrm{ClO}_{4}\right)_{2}\)

Four-coordinate metals can have either a tetrahedral or a square-planar geometry; both possibilities are shown here for \(\left[\mathrm{Pt} \mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{2}\right] .(\mathbf{a})\) What is the name of this molecule? (b) Would the tetrahedral molecule have a geometric isomer? (c) Would the tetrahedral molecule be diamagnetic or paramagnetic? (d) Would the square- planar molecule have a geometric isomer? (e) Would the square-planar molecule be diamagnetic or paramagnetic? (f) Would determining the number of geometric isomers help you distinguish between the tetrahedral and square-planar geometries? (g) Would measuring the molecule's response to a magnetic field help you distinguish between the two geometries? [Sections \(23.4-23.6]\)

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaammineiron(II) nitrate (b) tetraaquadibromochromium(III) perchlorate (c) ammonium hexachloropalladate(IV) (d) diammineoxolatonickel(II) (e) Hexaamminemolybdenum(III) tetrachlorocuprate(II)

Consider the following three complexes: \(\left(\right.\) Complex 1) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Br}_{2}\right] \mathrm{Cl}\) 2) \(\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{ONO})_{2}\right]\) (Complex (Complex 3) \(\left[\mathrm{V}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+},\) Which of the three complexes can have (a) geometric isomers, (b) linkage isomers, (c) optical isomers, (d) coordinationsphere isomers?

For each of the following metals, write the electronic configuration of the atom and its \(2+\) ion: \((\mathbf{a}) \mathrm{Mn},(\mathbf{b}) \mathrm{Ru},(\mathbf{c}) \mathrm{Rh} .\) Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(2+\) ion, assuming a strong-field complex. How many unpaired electrons are there in each case?

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