Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Among the period 4 transition metals \((\mathrm{Sc}-\mathrm{Zn}),\) which elements do not form ions where there are partially filled \(3 d\) orbitals?

Short Answer

Expert verified
The period 4 transition metals that do not form ions with partially filled 3d orbitals are Scandium (Sc), Titanium (Ti), Vanadium (V), Copper (Cu), and Zinc (Zn).

Step by step solution

01

Write down the electron configurations of the period 4 transition metals

We can determine the electron configurations of the period 4 transition metals through the periodic table: 1. Scandium (Sc): [Ar] 4s² 3d¹ 2. Titanium (Ti): [Ar] 4s² 3d² 3. Vanadium (V): [Ar] 4s² 3d³ 4. Chromium (Cr): [Ar] 4s¹ 3d⁵ 5. Manganese (Mn): [Ar] 4s² 3d⁵ 6. Iron (Fe): [Ar] 4s² 3d⁶ 7. Cobalt (Co): [Ar] 4s² 3d⁷ 8. Nickel (Ni): [Ar] 4s² 3d⁸ 9. Copper (Cu): [Ar] 4s¹ 3d¹⁰ 10. Zinc (Zn): [Ar] 4s² 3d¹⁰
02

Identify the elements that form stable cations without partially filled 3d orbitals

Now, we need to determine which of these elements do not form ions with partially filled 3d orbitals. To do this, we'll examine their possible cations and the resulting electron configurations: 1. Scandium (Sc): Sc³⁺ has the electron configuration [Ar], with no remaining 3d electrons. 2. Titanium (Ti): Ti⁴⁺ has the electron configuration [Ar], with no remaining 3d electrons. 3. Vanadium (V): V⁵⁺ has the electron configuration [Ar], with no remaining 3d electrons. 4. Chromium (Cr): Cr²⁺ has the electron configuration [Ar] 3d⁴. 5. Manganese (Mn): Mn²⁺ has the electron configuration [Ar] 3d⁵. 6. Iron (Fe): Fe³⁺ has the electron configuration [Ar] 3d⁵. 7. Cobalt (Co): Co³⁺ has the electron configuration [Ar] 3d⁶. 8. Nickel (Ni): Ni²⁺ has the electron configuration [Ar] 3d⁸. 9. Copper (Cu): Cu⁺ has the electron configuration [Ar] 3d¹⁰. 10. Zinc (Zn): Zn²⁺ has the electron configuration [Ar] 3d¹⁰.
03

List the elements that do not form ions with partially filled 3d orbitals

From the information in Step 2, we can determine that Scandium (Sc), Titanium (Ti), Vanadium (V), Copper (Cu), and Zinc (Zn) are the period 4 transition metals that do not form ions with partially filled 3d orbitals.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Electron configuration refers to how electrons are distributed in different atomic orbitals. Understanding electron configuration is critical to comprehending chemical properties and behaviors. For atoms in their ground state, electrons are filled in such a way to achieve the lowest possible energy.
For the period 4 transition metals, electron configurations start with the noble gas configuration of Argon \(\text{[Ar]}\), followed by additional electrons in the 4s and 3d orbitals.
  • Scandium (Sc): \([\text{Ar}] \ 4s^2 \ 3d^1\)
  • Titanium (Ti): \([\text{Ar}] \ 4s^2 \ 3d^2\)
  • Vanadium (V): \([\text{Ar}] \ 4s^2 \ 3d^3\)
  • ... ending with Zinc (Zn): \([\text{Ar}] \ 4s^2 \ 3d^{10}\)
When filling the d shell, once the 4s orbital is filled, electrons begin populating the 3d orbitals. However, due to electron-electron interactions and energy considerations, there are exceptions like Chromium (Cr) and Copper (Cu), where an electron from the 4s is used to half fill or completely fill the 3d orbital for added stability.
Period 4 Elements
Period 4 elements on the periodic table are fascinating, particularly the transition metals from Scandium (Sc) to Zinc (Zn). These elements have electrons entering the 3d sublevel, setting them apart from other elements.
They are known for their unique chemical behaviors and variable oxidation states. In period 4, transition metals' noteworthy features include:
  • High melting points
  • Variable oxidation states
  • Formation of colored compounds
  • Magnetic properties, particularly among the first few elements
The filling of the 3d orbitals confers unique characteristics. For instance, the incomplete d orbitals allow transition metals to form various ions and exhibit distinct magnetic and hallucinogenic properties. Transition metals in period 4 also play crucial roles in biological systems and industrial processes, leveraging their ability to form stable complex ions.
Ion Formation
Ion formation in transition metals is an intriguing process due to their variable oxidation states. When transition metals form ions, they typically lose electrons from both the s and d orbitals. The number of electrons removed corresponds to their oxidation state.
For example:
  • Scandium (Sc) loses 3 electrons to form \(\text{Sc}^{3+}\), resulting in \(\text{[Ar]}\)
  • Titanium (Ti) can form \(\text{Ti}^{4+}\), emptying the 3d orbital
  • Copper (Cu) forms a stable \(\text{Cu}^+ \) ion with a full 3d orbital \(\text{[Ar] 3d}^{10}\)
Unlike main group metals that typically form one type of ion, transition metals can form numerous ions with different charges. The differing ion charges affect the color, magnetism, and reactivity of the transition compounds. A practical example is iron, which can exist as \(\text{Fe}^{2+}\) or \(\text{Fe}^{3+}\), contributing to its versatility in chemical reactions and forming diverse compounds, essential for various industrial applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The lanthanide contraction explains which of the following periodic trends? (a) The atomic radii of the transition metals first decrease and then increase when moving horizontally across each period. (b) When forming ions the period 4 transition metals lose their \(4 s\) electrons before their \(3 d\) electrons. (c) The radii of the period 5 transition metals (Y-Cd) are very similar to the radii of the period 6 transition metals (Lu-Hg).

Determine if each of the following metal complexes is chiral and therefore has an optical isomer: (a) square planar \(\left[\mathrm{Pd}(\mathrm{en})(\mathrm{CN})_{2}\right],(\mathbf{b})\) octahedral \(\left[\mathrm{Ni (\mathrm{en})\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+},\) (c) octahedral cis-[V(en) \(\left._{2} \mathrm{ClBr}\right]\).

The complex \(\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) contains five unpaired electrons. Sketch the energy-level diagram for the \(d\) orbitals, and indicate the placement of electrons for this complex ion. Is the ion a high-spin or a low-spin complex?

Carbon monoxide is toxic because it binds more strongly to the iron in hemoglobin (Hb) than does \(\mathrm{O}_{2}\), as indicated by these approximate standard free-energy changes in blood: $$ \begin{aligned} \mathrm{Hb}+\mathrm{O}_{2} & \longrightarrow \mathrm{HbO}_{2} & \Delta G^{\circ}=-70 \mathrm{~kJ} \\ \mathrm{Hb}+\mathrm{CO} & \longrightarrow \mathrm{HbCO} & \Delta G^{\circ}=-80 \mathrm{~kJ} \end{aligned} $$ Using these data, estimate the equilibrium constant at 298 K for the equilibrium $$ \mathrm{HbO}_{2}+\mathrm{CO} \rightleftharpoons \mathrm{HbCO}+\mathrm{O}_{2} $$

(a) If a complex absorbs light at \(610 \mathrm{nm},\) what color would you expect the complex to be? (b) What is the energy in joules of a photon with a wavelength of \(610 \mathrm{nm}\) ? (c) What is the energy of this absorption in \(\mathrm{kJ} / \mathrm{mol} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free