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An iron object is plated with a coating of tin (Sn) to protect against corrosion. Does the tin protect iron by cathodic protection?

Short Answer

Expert verified
Tin does not protect iron by cathodic protection, as its standard oxidation potential (-0.14V) is less negative than iron (-0.44V), making it less likely to oxidize and act as a sacrificial metal. However, tin can still protect iron from corrosion by forming a barrier between the iron and the environment, preventing oxygen and moisture from reaching the iron surface.

Step by step solution

01

Determine the standard oxidation potentials of iron and tin

We must first find the standard oxidation potentials of both iron and tin to determine the likelihood of each metal undergoing corrosion. The standard oxidation potential is a measure of the tendency of a metal to lose electrons and oxidize. Standard oxidation potentials for Iron (Fe) and Tin (Sn) are as follows: \[ E°_{Fe^{2+}/Fe} = -0.44V \] \[ E°_{Fe^{3+}/Fe} = +0.04V \] \[ E°_{Sn^{2+}/Sn} = -0.14V \]
02

Compare the standard oxidation potentials of iron and tin

Now we compare the standard oxidation potentials of iron and tin. The more negative the standard oxidation potential, the more likely the metal is to oxidize. In this case, iron has a more negative value (-0.44V) compared to tin (-0.14V).
03

Determine if tin provides cathodic protection to iron

Since tin has a less negative standard oxidation potential than iron, it is less likely to oxidize and therefore would not act as a sacrificial metal for iron. Hence, tin cannot provide cathodic protection to iron. However, tin can still protect iron from corrosion by creating a barrier between the iron and the environment, preventing oxygen and moisture from reaching the iron surface. In conclusion, tin does not protect iron by cathodic protection, but it can still serve as a barrier to protect the iron from environmental factors that cause corrosion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Oxidation Potential
The standard oxidation potential is crucial in evaluating how likely a metal will lose electrons, thereby corroding. Essentially, it measures the readiness of a metal to oxidize.
In electrochemistry, the more negative the standard oxidation potential of a metal, the higher its tendency to undergo oxidation. For example, in the given data:
  • The standard oxidation potential of iron (Fe) when it transitions from Fe²⁺ to its solid form is \( E^\circ_{Fe^{2+}/Fe} = -0.44V \).
  • Meanwhile, tin (Sn) goes from Sn²⁺ to Sn solid with a standard oxidation potential of \( E^\circ_{Sn^{2+}/Sn} = -0.14V \).
With iron's oxidation potential being more negative than tin's, iron oxidizes, or corrodes, more readily than tin.
This is a key consideration in corrosion studies and protective measures.
Corrosion Prevention
Corrosion prevention is a vital aspect in prolonging the life of metal objects. It involves protecting metals from adverse environmental conditions that lead to wear and degradation through rusting or oxidation.
When it comes to iron, one way to prevent corrosion is by coating it with another metal, like tin. Although tin doesn't protect iron through cathodic protection, it serves as a physical shielding layer.
Here's how tin acts:
  • It doesn't corrode as easily as iron because of its less negative standard oxidation potential.
  • The tin coating forms a barrier blocking moisture and oxygen, which are two primary causes of corrosion.
  • Even if there's a scratch on the tin layer, it tends to self-heal to continuously protect the underlying iron.
Nonetheless, regular maintenance and inspections are necessary to ensure the protective layer remains intact.
Electrochemistry
Electrochemistry plays a pivotal role in understanding metal corrosion and protection strategies. This scientific field deals with the movement of electrons and the electrical properties of chemicals.
A core component of electrochemistry is the electrochemical series, which ranks metals by their standard oxidation potentials.
  • The series helps predict and understand how different metals interact with each other when in contact.
  • It is instrumental in designing protection systems involving cathodic protection or protective coatings.
By studying electrochemical interactions, scientists can devise methods to prevent unnecessary metal wear, ensuring structures and components last longer.
In practical applications, tools like galvanic cells highlight how metal interactions can produce electrical energy, while underlying principles aid in innovative corrosion protection solutions.

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Most popular questions from this chapter

Hydrogen gas has the potential for use as a clean fuel in reaction with oxygen. The relevant reaction is $$ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) $$ Consider two possible ways of utilizing this reaction as an electrical energy source: (i) Hydrogen and oxygen gases are combusted and used to drive a generator, much as coal is currently used in the electric power industry; (ii) hydrogen and oxygen gases are used to generate electricity directly by using fuel cells that operate at \(85^{\circ} \mathrm{C} .\) (a) Use data in Appendix \(\mathrm{C}\) to calculate \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) for the reaction. We will assume that these values do not change appreciably with temperature. (b) Based on the values from part (a), what trend would you expect for the magnitude of \(\Delta G\) for the reaction as the temperature increases? (c) What is the significance of the change in the magnitude of \(\Delta G\) with temperature with respect to the utility of hydrogen as a fuel? (d) Based on the analysis here, would it be more efficient to use the combustion method or the fuel-cell method to generate electrical energy from hydrogen?

Consider the half-reaction \(\mathrm{Ag}^{+}(a q)+\mathrm{e}^{-} \longrightarrow \mathrm{Ag}(s)\) (a) Which of the lines in the following diagram indicates how the reduction potential varies with the concentration of \(\mathrm{Ag}^{+}(a q) ?(\mathbf{b})\) What is the value of \(E_{\text {red }}\) when \(\log \left[\mathrm{Ag}^{+}\right]=0 ?\)

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