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(a) Aluminum metal is used as a sacrificial anode to protect offshore pipelines in salt water from corrosion. Why is the aluminum referred to as a "sacrificial anode"? (b) Looking in Appendix E, suggest what metal the pipelines could be made from in order for aluminum to be successful as a sacrificial anode.

Short Answer

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(a) Aluminum is referred to as a "sacrificial anode" because it is more likely to corrode than the protected metal (the pipeline) and, in doing so, forms a continuous flow of metal ions that prevent the pipeline from corroding. (b) For aluminum to be successful as a sacrificial anode, the pipeline must be made from a metal with a higher reduction potential value. Possible metals include copper (\(Cu\)) with a reduction potential of +0.34 volts, iron (\(Fe\)) with a reduction potential of -0.44 volts, and nickel (\(Ni\)) with a reduction potential of -0.25 volts.

Step by step solution

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(a) Understanding sacrificial anodes

Sacrificial anodes are metals that are used to prevent a more valuable metal, like the material of a pipeline, from corroding. They are referred to as "sacrificial" because they are more likely to corrode than the protected metal. When the sacrificial anode corrodes, it forms a continuous flow of metal ions, which helps to prevent metal particles from breaking away and corroding the protected pipeline. In this case, aluminum is used as the sacrificial anode to protect offshore pipelines in salt water.
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(b) Suggesting a metal for the pipeline to be protected by aluminum

In order for aluminum to successfully protect the pipeline as a sacrificial anode, the pipeline needs to be made from a metal that is less likely to corrode than aluminum. In Appendix E, we can find the standard reduction potential values for various metals. Aluminum has a standard reduction potential value of -1.66 volts. A metal with a higher reduction potential value will be less likely to corrode. Some possible metals for the pipeline could be: 1. Copper (\(Cu\)) with a standard reduction potential of +0.34 volts 2. Iron (\(Fe\)) with a standard reduction potential of -0.44 volts 3. Nickel (\(Ni\)) with a standard reduction potential of -0.25 volts These metals have higher reduction potential values than aluminum, meaning that they are less likely to corrode when the aluminum sacrificial anode is in place.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Corrosion Protection
Corrosion protection is essential in preserving the integrity and longevity of metal structures, especially those exposed to harsh environmental conditions like salt water. Corrosion is the natural process where metals deteriorate due to reactions with environmental elements such as oxygen and moisture. This can lead to weakening and eventual failure of the metal structure, such as pipelines. One effective method of corrosion protection is the use of a sacrificial anode. A sacrificial anode is a more reactive metal that is intentionally allowed to corrode in place of the structure it protects. It acts as a "sacrifice," corroding instead of the metal it is protecting. This method is widely used in maritime environments where structures like ships, piers, or offshore pipelines are constantly exposed to corrosive salt water. By using a sacrificial anode, the more valuable metal structure remains intact while the anode gradually wears away.
Reduction Potential
Reduction potential is a crucial concept in understanding why some metals make better sacrificial anodes than others. It indicates a metal's tendency to gain electrons and thereby resist oxidation or corrosion. Metals with lower reduction potentials are more prone to losing electrons and will corrode more readily. In practical terms, a metal with a lower reduction potential than another will corrode first. This property makes certain metals ideal choices for sacrificial anodes. For instance, aluminum, with a reduction potential of -1.66 Volts, is more likely to corrode than metals with a higher reduction potential, such as copper or nickel. Therefore, it is used as a sacrificial anode when protecting metals having higher reduction potentials, ensuring they remain intact as aluminum corrodes instead.
Aluminum Anode
Aluminum anodes are widely used as sacrificial anodes due to their effective performance in salt water environments. They provide corrosion protection to various metal structures susceptible to erosion by seawater. Aluminum's relatively high capacity to corrode in place of the protected metal makes it an excellent choice. An aluminum anode works by slowly oxidizing, releasing metal ions into the electrolyte, which could be saltwater. These ions help prevent the oxidation of the protected metal structure. The sacrificial action of aluminum also makes it cost-effective since it prolongs the life of valuable infrastructures, reducing maintenance costs. Aluminum anodes are easy to replace once they have fully corroded, ensuring continuous protection.
Metals in Salt Water
Metals in salt water environments face increased risks of corrosion due to the presence of electrolytes which facilitate chemical reactions. Salt water, being an excellent conductor, accelerates the corrosion process. The choice of materials for construction and protection in such environments becomes crucial. Pipelines and metal structures exposed to salt water are typically made from materials with higher reduction potential, such as copper or nickel. These metals are less likely to corrode rapidly compared to those with lower reduction potentials. When combined with sacrificial anodes, such as aluminum, these setups provide an efficient method of corrosion protection. This approach ensures that the more valuable metals remain protected, while the sacrificial anode takes the brunt of the corrosion, maintaining the longevity of the infrastructure in corrosive salt water conditions.

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Most popular questions from this chapter

The purification process of silicon involves the reaction of silicon tetrachloride vapor \(\left(\mathrm{SiCl}_{4}(g)\right)\) with hydrogen to \(1250^{\circ} \mathrm{C}\) to form solid silicon and hydrogen chloride. \((\mathbf{a})\) Write a balanced equation for this reaction. (b) What is being oxidized, and what is being reduced? (c) Which substance is the reductant, and which is the oxidant?

Cytochrome, a complicated molecule that we will represent as \(\mathrm{CyFe}^{2+}\), reacts with the air we breathe to supply energy required to synthesize adenosine triphosphate (ATP). The body uses ATP as an energy source to drive other reactions (Section 19.7). At \(\mathrm{pH} 7.0\) the following reduction potentials pertain to this oxidation of \(\mathrm{CyFe}^{2+}\) $$ \begin{aligned} \mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q)+4 \mathrm{e}^{-} & \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) & & E_{\mathrm{red}}^{\circ}=+0.82 \mathrm{~V} \\\ \mathrm{CyFe}^{3+}(a q)+\mathrm{e}^{-} & \longrightarrow \mathrm{CyFe}^{2+}(a q) & E_{\mathrm{red}}^{\circ} &=+0.22 \mathrm{~V} \end{aligned} $$ (a) What is \(\Delta G\) for the oxidation of \(\mathrm{CyFe}^{2+}\) by air? \((\mathbf{b})\) If the synthesis of \(1.00 \mathrm{~mol}\) of ATP from adenosine diphosphate (ADP) requires a \(\Delta G\) of \(37.7 \mathrm{~kJ},\) how many moles of ATP are synthesized per mole of \(\mathrm{O}_{2} ?\)

Aqueous solutions of ammonia \(\left(\mathrm{NH}_{3}\right)\) and bleach (active ingredient \(\mathrm{NaOCl}\) ) are sold as cleaning fluids, but bottles of both of them warn: "Never mix ammonia and bleach, as toxic gases may be produced." One of the toxic gases that can be produced is chloroamine, \(\mathrm{NH}_{2} \mathrm{Cl}\). (a) What is the oxidation number of chlorine in bleach? (b) What is the oxidation number of chlorine in chloramine? (c) Is Cl oxidized, reduced, or neither, upon the conversion of bleach to chloramine? (d) Another toxic gas that can be produced is nitrogen trichloride, \(\mathrm{NCl}_{3}\). What is the oxidation number of \(\mathrm{N}\) in nitrogen trichloride? \((\mathbf{e})\) Is \(\mathrm{N}\) oxidized, reduced, or neither, upon the conversion of ammonia to nitrogen trichloride?

Metallic magnesium can be made by the electrolysis of molten \(\mathrm{MgCl}_{2}\) (a) What mass of \(\mathrm{Mg}\) is formed by passing a current of 4.55 A through molten \(\mathrm{MgCl}_{2}\), for 4.50 days? (b) How many minutes are needed to plate out \(25.00 \mathrm{~g} \mathrm{Mg}\) from molten \(\mathrm{MgCl}_{2}\) using \(3.50 \mathrm{~A}\) of current?

If the equilibrium constant for a one-electron redox reaction at \(298 \mathrm{~K}\) is \(2.2 \times 10^{-5},\) calculate the corresponding \(\Delta G^{\circ}\) and \(E^{\circ}\).

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