Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) What is meant by the term oxidation? (b) On which side of an oxidation half-reaction do the electrons appear? (c) What is meant by the term oxidant? (d) What is meant by the term oxidizing agent?

Short Answer

Expert verified
(a) Oxidation refers to a chemical reaction in which an atom, ion, or molecule loses one or more electrons, leading to an increase in its oxidation state. (b) In an oxidation half-reaction, electrons appear on the right side or the product side of the equation. (c) An oxidant, or oxidizing agent, is a substance that accepts electrons in a chemical reaction, causing the oxidation of other species involved. (d) An oxidizing agent is a substance that promotes oxidation by accepting electrons in a chemical reaction, reducing its own oxidation state while causing the oxidation of another substance.

Step by step solution

01

Part (a): Definition of Oxidation

Oxidation is a chemical reaction in which an atom, ion, or molecule loses one or more electrons. This process leads to an increase in the oxidation state of the species involved. In simple terms, oxidation refers to the loss of electrons.
02

Part (b): Position of electrons in an oxidation half-reaction

In an oxidation half-reaction, the electrons appear on the right side or the product side of the equation. This is because the species involved is losing electrons to get oxidized, and those electrons are released as products in the reaction.
03

Part (c): Definition of Oxidant

An oxidant, also known as an oxidizing agent, is a substance that has the ability to accept electrons in a chemical reaction, leading to the oxidation of the other species involved in the reaction. In other words, it is a substance that causes or facilitates the oxidation of other species.
04

Part (d): Definition of Oxidizing Agent

An oxidizing agent, synonymous with oxidant, is a substance that promotes or drives oxidation by accepting one or more electrons during a chemical reaction. By gaining electrons, the oxidizing agent reduces its own oxidation state while causing the oxidation of another substance. Examples of oxidizing agents include oxygen, halogens, and potassium permanganate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation Reactions
Oxidation reactions are an essential part of chemistry and occur when an atom, ion, or molecule loses electrons. This loss results in an increase in the oxidation state of the entity. When a substance undergoes oxidation, it's said to be oxidized.
This can happen in various scenarios, such as rusting iron, burning wood, or metabolism in your body. Each involves the transfer of electrons.
If you're looking at a chemical equation showcasing an oxidation reaction, you'll typically see electrons appearing as products. For example, in the half-reaction of oxidation, these electrons are shown on the right side, indicating that they have been released.
Understanding oxidation reactions helps in grasping how batteries work, why some foods spoil, and how metallurgy processes are conducted. It's a fundamental concept useful in both everyday applications and advanced scientific research.
Oxidizing Agents
An oxidizing agent is a crucial player in redox reactions. While it sounds complicated, it is pretty straightforward - this is a substance that will take in or accept electrons from other substances.
When it does this, it facilitates the oxidation of the substance that loses electrons. Essentially, the oxidizing agent is being reduced because it's gaining electrons.
Oxidizing agents aren’t just found in labs. They are everywhere: in bleach for cleaning, in hydrogen peroxide for first aid, and even in food preservatives.
  • Common oxidizing agents include oxygen, chlorine, and potassium permanganate.
  • These agents play vital roles in processes like disinfection, combustion, and even cellular respiration.
By understanding how oxidizing agents work, you can appreciate their role in both controlling harmful bacteria and maintaining essential biological processes in our body.
Electrons in Reactions
Electrons are the currency of chemical reactions and play a profound role in how substances interact and change. In oxidation reactions, electrons are lost by one species and gained by another. This transfer is a fundamental principle of redox (reduction-oxidation) chemistry.
When considering an oxidation half-reaction, you should place electrons on the product side - the right side of the equation. This placement indicates that the electrons are a result of the reaction, having been released by the oxidized molecule or atom.
  • The movement of electrons from one substance to another is what makes batteries work, such as in your smartphone or car.
  • Electrons' transfer is also crucial in biological systems, like cellular respiration or photosynthesis.
Each electron movement contributes to the energy and transformation processes essential for both technical devices and living organisms. Understanding this concept helps you master the bigger picture of how energy flows through natural and industrial systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Which electrode of a voltaic cell, the cathode or the anode, corresponds to the higher potential energy for the electrons? (b) What are the units for electrical potential? How does this unit relate to energy expressed in joules?

A voltaic cell is constructed that is based on the following reaction: $$ \mathrm{Sn}^{2+}(a q)+\mathrm{Pb}(s) \longrightarrow \mathrm{Sn}(s)+\mathrm{Pb}^{2+}(a q) $$ (a) If the concentration of \(\mathrm{Sn}^{2+}\) in the cathode half-cell is \(1.00 M\) and the cell generates an emf of \(+0.22 \mathrm{~V},\) what is the concentration of \(\mathrm{Pb}^{2+}\) in the anode half-cell? \((\mathbf{b})\) If the anode half-cell contains \(\left[\mathrm{SO}_{4}^{2-}\right]=1.00 M\) in equilibrium with \(\mathrm{PbSO}_{4}(s),\) what is the \(K_{s p}\) of \(\mathrm{PbSO}_{4} ?\)

During a period of discharge of a lead-acid battery, \(300 \mathrm{~g}\) of \(\mathrm{PbO}_{2}(s)\) from the cathode is converted into \(\mathrm{PbSO}_{4}(s)\). (a) What mass of \(\mathrm{Pb}(s)\) is oxidized at the anode during this same period? (b) How many coulombs of electrical charge are transferred from \(\mathrm{Pb}\) to \(\mathrm{PbO}_{2}\) ?

Hydrogen gas has the potential for use as a clean fuel in reaction with oxygen. The relevant reaction is $$ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l) $$ Consider two possible ways of utilizing this reaction as an electrical energy source: (i) Hydrogen and oxygen gases are combusted and used to drive a generator, much as coal is currently used in the electric power industry; (ii) hydrogen and oxygen gases are used to generate electricity directly by using fuel cells that operate at \(85^{\circ} \mathrm{C} .\) (a) Use data in Appendix \(\mathrm{C}\) to calculate \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) for the reaction. We will assume that these values do not change appreciably with temperature. (b) Based on the values from part (a), what trend would you expect for the magnitude of \(\Delta G\) for the reaction as the temperature increases? (c) What is the significance of the change in the magnitude of \(\Delta G\) with temperature with respect to the utility of hydrogen as a fuel? (d) Based on the analysis here, would it be more efficient to use the combustion method or the fuel-cell method to generate electrical energy from hydrogen?

Hydrazine \(\left(\mathrm{N}_{2} \mathrm{H}_{4}\right)\) and dinitrogen tetroxide \(\left(\mathrm{N}_{2} \mathrm{O}_{4}\right)\) form a self-igniting mixture that has been used as a rocket propellant. The reaction products are \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\). (a) Write a balanced chemical equation for this reaction. (b) What is being oxidized, and what is being reduced? (c) Which substance serves as the reducing agent and which as the oxidizing agent?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free