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In chemical kinetics, the entropy of activation is the entropy change for the process in which the reactants reach the activated complex. Predict whether the entropy of activation for a bimolecular process is usually positive or negative.

Short Answer

Expert verified
The entropy of activation for a bimolecular process is usually negative, as the formation of the activated complex leads to a decrease in the system's entropy due to the reactants becoming more ordered in the transition state.

Step by step solution

01

Understanding entropy

Entropy is a thermodynamic property that measures the degree of disorder or randomness in a system. In a chemical reaction, it is generally observed that a higher entropy system (more disorder) is favored over a lower entropy system (more order). Hence, changes in entropy can indicate the direction of a reaction.
02

Comparing reactants and activated complex

In a bimolecular process, two reactant molecules come together to form an activated complex or transition state. The transition state represents the highest energy state of the system during the reaction and is the point at which the reaction can proceed either forward or backward. During the formation of the activated complex, the reactants come together and get organized into a more ordered structure compared to their initial state. This leads to a decrease in the entropy of the system.
03

Determining the sign of the entropy of activation

Since the entropy of the system decreases during the process of forming the activated complex in a bimolecular reaction, we can conclude that the entropy of activation for a bimolecular process is usually negative. The negative value indicates that the transition state of the system has a lower entropy than that of the separate reactants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy of Activation
The entropy of activation is a thermodynamic concept related to the formation of the activated complex in a chemical reaction. When molecules react, they must reach a temporary, high-energy state known as the transition state before converting into products. This change involves the formation of an activated complex. The entropy of activation measures the change in entropy as the reactants transform into this transition state.
The entropy change is crucial because it reflects how the disorder of the system alters during a reaction. In a bimolecular reaction, where two molecules come together to form the activated complex, this process usually results in a more ordered state compared to the initial reactants. Therefore, for most bimolecular reactions, the entropy of activation is negative, indicating a decrease in randomness or disorder.
Understanding entropy changes can help predict reaction feasibility and direction, shedding light on why some reactions are spontaneous while others are not.
Transition State Theory
Transition State Theory (TST) provides a framework for understanding chemical reactions in terms of energy changes and configurations of the reactants and products. This theory suggests that during a reaction, systems pass through a transition state, which is the highest energy point along the reaction path. Think of it like a mountain peak between the starting materials and products.
In reaching this transition state, reactants must overcome an energy barrier. This concept explains the rates of reactions and how altering conditions such as temperature or the presence of catalysts can influence this rate. The activated complex, a critical feature of TST, is a fleeting structure that sits at the energy peak and represents the configuration where bonds are partially formed and broken.
Once this state is surpassed, the reaction typically proceeds to form products, driven by the energy released as the system moves to a lower energy state. Transition State Theory thus helps us predict reaction speeds and understand the overall mechanistic pathway, acting as a cornerstone of chemical kinetics.
Bimolecular Reaction
A bimolecular reaction involves two reactant molecules coming together to form products. This type of reaction is common in chemical kinetics and often involves a collision between two distinct entities. The simplest bimolecular reactions are of the form A + B → products.
In these reactions, the reactant molecules collide with sufficient energy to overcome the activation energy barrier and form an activated complex. This step is crucial because the activated complex is a necessary configuration for the reaction to proceed.
These reactions usually occur in gaseous or liquid phases where molecular movement facilitates the collisions. The rate of a bimolecular reaction is often influenced by factors such as concentration and temperature. Higher concentrations result in more frequent collisions, thus potentially increasing the reaction rate. Understanding bimolecular reactions helps predict how modifications to conditions affect the rates of chemical processes.
Thermodynamic Properties
Thermodynamic properties are fundamental to understanding chemical reactions as they describe the energetics of the systems. Key properties include enthalpy, entropy, and Gibbs free energy. These concepts help explain how reactions occur, their feasibility, and their energy requirements.
Enthalpy refers to the heat content of a system, while entropy is the measure of disorder or randomness. Gibbs free energy combines both these properties to predict whether a reaction will occur spontaneously.
  • If Gibbs free energy is negative, the reaction is likely spontaneous and favorable
  • If positive, the reaction is non-spontaneous under those conditions
Another critical property is the activation energy, the minimum energy needed for a reaction to occur. Thermodynamic considerations tell us about the direction and feasibility of reactions, but they don't give details about how fast a reaction will happen—that's where kinetics and transition state theory come into play.
Thus, thermodynamic properties are crucial for understanding the potential of chemical reactions and guiding experimental approaches to manipulate them.

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Most popular questions from this chapter

The value of \(K_{a}\) for nitrous acid \(\left(\mathrm{HNO}_{2}\right)\) at \(25^{\circ} \mathrm{C}\) is given in Appendix D. (a) Write the chemical equation for the equilibrium that corresponds to \(K_{a}\). (b) By using the value of \(K_{a}\) calculate \(\Delta G^{\circ}\) for the dissociation of nitrous acid in aqueous solution. (c) What is the value of \(\Delta G\) at equilibrium? (d) What is the value of \(\Delta G\) when \(\left[\mathrm{H}^{+}\right]=5.0 \times 10^{-2} \mathrm{M}\), \(\left[\mathrm{NO}_{2}^{-}\right]=6.0 \times 10^{-4} \mathrm{M},\) and \(\left[\mathrm{HNO}_{2}\right]=0.20 \mathrm{M} ?\)

A standard air conditioner involves a \(r\) frigerant that is typically now a fluorinated hydrocarbon, such as \(\mathrm{CH}_{2} \mathrm{~F}_{2}\). An air- conditioner refrigerant has the property that it readily vaporizes at atmospheric pressure and is easily compressed to its liquid phase under increased pressure. The operation of an air conditioner can be thought of as a closed system made up of the refrigerant going through the two stages shown here (the air circulation is not shown in this diagram). During expansion, the liquid refrigerant is released into an expansion chamber at low pressure, where it vaporizes. The vapor then undergoes compression at high pressure back to its liquid phase in a compression chamber. (a) What is the sign of \(q\) for the expansion? (b) What is the sign of \(q\) for the compression? (c) In a central air-conditioning system, one chamber is inside the home and the other is outside. Which chamber is where, and why? (d) Imagine that a sample of liquid refrigerant undergoes expansion followed by compression, so that it is back to its original state. Would you expect that to be a reversible process? (e) Suppose that a house and its exterior are both initially at \(31^{\circ} \mathrm{C}\). Some time after the air conditioner is turned on, the house is cooled to \(24^{\circ} \mathrm{C}\). Is this process spontaneous of nonspontaneous?

Consider the following reaction between oxides of nitrogen: $$ \mathrm{NO}_{2}(g)+\mathrm{N}_{2} \mathrm{O}(g) \longrightarrow 3 \mathrm{NO}(g) $$ (a) Use data in Appendix \(C\) to predict how \(\Delta G\) for the reaction varies with increasing temperature. (b) Calculate \(\Delta G\) at \(800 \mathrm{~K}\), assuming that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not change with temperature. Under standard conditions is the reaction spontaneous at \(800 \mathrm{~K} ?\) (c) Calculate \(\Delta G\) at \(1000 \mathrm{~K}\). Is the reaction spontaneous under standard conditions at this temperature?

The reaction \(2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{MgO}(s)\) is highly spontaneous. A classmate calculates the entropy change for this reaction and obtains a large negative value for \(\Delta S^{\circ}\). Did your classmate make a mistake in the calculation? Explain.

Sulfur dioxide reacts with strontium oxide as follows: $$ \mathrm{SO}_{2}(g)+\mathrm{SrO}(g) \longrightarrow \mathrm{SrSO}_{3}(s) $$ (a) Without using thermochemical data, predict whether \(\Delta G^{\circ}\) for this reaction is more negative or less negative than \(\Delta H^{\circ} .\) (b) If you had only standard enthalpy data for this reaction, how would you estimate the value of \(\Delta G^{\circ}\) at \(298 \mathrm{~K},\) using data from Appendix \(\mathrm{C}\) on other substances.

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