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(a) What is the difference between chlorofluorocarbons and hydrofluorocarbons? (b) Why are hydrofluorocarbons potentially less harmful to the ozone layer than CFCs?

Short Answer

Expert verified
(a) The difference between chlorofluorocarbons (CFCs) and hydrofluorocarbons (HFCs) is that CFCs contain chlorine, fluorine, and carbon, while HFCs contain hydrogen, fluorine, and carbon. CFCs have the formula C_xCl_yF_z, and HFCs have the formula C_xH_yF_z. (b) Hydrofluorocarbons are potentially less harmful to the ozone layer than CFCs because they do not contain chlorine atoms, which are responsible for ozone depletion. CFCs release chlorine molecules into the atmosphere that react with ozone and break it down, while HFCs do not participate in this ozone-destruction cycle.

Step by step solution

01

(1. Understand Chlorofluorocarbons (CFCs))

CFCs are a family of synthetic compounds containing chlorine, fluorine, and carbon. They have been widely used as propellants, refrigerants, and solvents. Their formula is generally written as C_xCl_yF_z. Some common examples include CFC-12 (CF2Cl2) and CFC-11 (CFCl3).
02

(2. Understand Hydrofluorocarbons (HFCs))

HFCs are a group of synthetic compounds containing hydrogen, fluorine, and carbon. They were introduced as alternatives to CFCs, in response to concerns about ozone depletion. Their formula is typically written as C_xH_yF_z. Some examples of HFCs include HFC-134a (CH2FCF3) and HFC-152a (CH3CHF2).
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(3. Identify the Difference between CFCs and HFCs)

The notable difference between CFCs and HFCs is the presence (or absence) of chlorine. CFCs contain chlorine, fluorine, and carbon, whereas HFCs contain hydrogen, fluorine, and carbon. To answer part (a) of the exercise, the difference between chlorofluorocarbons and hydrofluorocarbons is that CFCs contain chlorine in their composition, while HFCs do not.
04

(4. Discuss the Harmful Effects of CFCs on the Ozone Layer)

CFCs are known to contribute to the depletion of the ozone layer by releasing chlorine molecules through a series of photodissociation reactions. When the released chlorine reacts with ozone (O3) molecules in the stratosphere, it breaks them down into oxygen (O2) molecules and a chlorine-monoxide (ClO) molecule. This process reduces the overall concentration of ozone in the stratosphere, leading to the depletion of the ozone layer.
05

(5. Explain Why HFCs are Potentially Less Harmful to the Ozone Layer than CFCs)

Since HFCs do not contain chlorine in their composition, their potential for depleting the ozone layer is significantly reduced. Unlike CFCs, HFCs do not release chlorine molecules into the atmosphere, so they do not participate in the ozone-destruction cycle. Therefore, HFCs are regarded as more environmentally friendly alternatives to CFCs. To answer part (b) of the exercise, hydrofluorocarbons are potentially less harmful to the ozone layer than CFCs because they do not contain chlorine atoms, which are responsible for ozone depletion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chlorofluorocarbons (CFCs)
Chlorofluorocarbons, commonly abbreviated as CFCs, are man-made chemical compounds that contain chlorine, fluorine, and carbon. They were once widely used in various industries due to their stability and non-flammable nature.
These properties made them ideal for applications such as:
  • Refrigerants in air conditioners and refrigerators
  • Propellants in aerosol sprays
  • Solvents in the production of foam insulation
However, their stability also means they persist in the atmosphere, eventually reaching the stratosphere where they break down and release chlorine. This chlorine plays a significant role in depleting the ozone layer. The molecular structure of CFCs is commonly represented as \( ext{C}_x ext{Cl}_y ext{F}_z \), where the presence of chlorine is critical to their environmental impact.
Hydrofluorocarbons (HFCs)
Hydrofluorocarbons, or HFCs, are chemical compounds similar to CFCs, but with a crucial difference: they lack chlorine atoms. Instead, they consist of hydrogen, fluorine, and carbon, leading to a different formula \( ext{C}_x ext{H}_y ext{F}_z \). This alteration in composition means HFCs do not directly engage in chemical reactions that deplete the ozone layer.
HFCs were developed as an alternative to CFCs, aiming to provide:
  • Refrigeration and air conditioning solutions
  • Aerosol propellants
  • Foam blowing agents
Their main advantage is the absence of chlorine, which prevents them from participating in the ozone destruction cycle. As a result, although HFCs still have some environmental impacts such as being potent greenhouse gases, they are considered more ozone-friendly compared to CFCs.
Chlorine's Role in Ozone Depletion
The primary harmful effect of CFCs arises from the chlorine atoms they release in the stratosphere. This occurs when CFC molecules are broken down by ultraviolet (UV) radiation, a process known as photodissociation.
Once released, chlorine atoms can react with ozone molecules (\( ext{O}_3 \)), breaking them down into molecular oxygen (\( ext{O}_2 \)) and forming chlorine monoxide (\( ext{ClO} \)). The chlorine atom is then freed to repeat this destructive cycle, with one chlorine atom having the potential to destroy many thousands of ozone molecules.
Key steps in the process include:
  • CFC molecules reach the stratosphere
  • UV radiation breaks CFCs, releasing chlorine
  • Chlorine attacks ozone, forming \( ext{ClO} \) and \( ext{O}_2 \)
  • The chlorine atom is free to start the cycle over
This ongoing cycle poses a significant threat to the ozone layer, which acts as Earth's protective barrier against harmful UV radiation. Reducing the release of substances that emit chlorine is crucial for preserving this vital atmospheric layer.

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Most popular questions from this chapter

A reaction that contributes to the depletion of ozone in the stratosphere is the direct reaction of oxygen atoms with ozone: $$ \mathrm{O}(g)+\mathrm{O}_{3}(g) \longrightarrow 2 \mathrm{O}_{2}(g) $$ At \(298 \mathrm{~K}\) the rate constant for this reaction is \(4.8 \times 10^{5}\) \(M^{-1} \mathrm{~s}^{-1}\). (a) Based on the units of the rate constant, write the likely rate law for this reaction. (b) Would you expect this reaction to occur via a single elementary process? Explain why or why not. (c) Use \(\Delta H_{f}^{\circ}\) values from Appendix \(\mathrm{C}\) to estimate the enthalpy change for this reaction. Would this reaction raise or lower the temperature of the stratosphere?

It was estimated that the eruption of the Mount Pinatubo volcano resulted in the injection of 20 million metric tons of \(\mathrm{SO}_{2}\) into the atmosphere. Most of this \(\mathrm{SO}_{2}\) underwent oxidation to \(\mathrm{SO}_{3},\) which reacts with atmospheric water to form an aerosol. (a) Write chemical equations for the processes leading to formation of the aerosol. (b) The aerosols caused a \(0.5-0.6^{\circ} \mathrm{C}\) drop in surface temperature in the northern hemisphere. What is the mechanism by which this occurs? (c) The sulfate aerosols, as they are called, also cause loss of ozone from the stratosphere. How might this occur?

An important reaction in the formation of photochemical smog is the photodissociation of \(\mathrm{NO}_{2}\) : $$ \mathrm{NO}_{2}+h \nu \longrightarrow \mathrm{NO}(g)+\mathrm{O}(g) $$ The maximum wavelength of light that can cause this reaction is \(420 \mathrm{nm} .\) (a) In what part of the electromagnetic spectrum is light with this wavelength found? (b) What is the maximum strength of a bond, in \(\mathrm{kJ} / \mathrm{mol}\), that can be broken by absorption of a photon of 420 -nm light? \(?\) (c) Write out the photodissociation reaction showing Lewis-dot structures.

(a) What are trihalomethanes (THMs)? (b) Draw the Lewis structures of two example THMs.

Alcohol-based fuels for automobiles lead to the production of formaldehyde \(\left(\mathrm{CH}_{2} \mathrm{O}\right)\) in exhaust gases. Formaldehyde undergoes photodissociation, which contributes to photochemical smog: $$ \mathrm{CH}_{2} \mathrm{O}+h \nu \longrightarrow \mathrm{CHO}+\mathrm{H} $$ The maximum wavelength of light that can cause this reaction is \(335 \mathrm{nm} .(\mathbf{a})\) In what part of the electromagnetic spectrum is light with this wavelength found? (b) What is the maximum strength of a bond, in \(\mathrm{kJ} / \mathrm{mol}\), that can be broken by absorption of a photon of 335 -nm light? (c) Compare your answer from part (b) to the appropriate value from Table 8.3 . What do you conclude about \(\mathrm{C}-\mathrm{H}\) bond energy in formaldehyde? (d) Write out the formaldehyde photodissociation reaction, showing Lewis-dot structures.

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