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Do the reactions involved in ozone depletion involve changes in oxidation state of the O atoms? Explain.

Short Answer

Expert verified
Yes, the reactions involved in ozone depletion involve changes in the oxidation state of Oxygen atoms. During the chlorine-catalyzed ozone depletion process, the oxidation state of one Oxygen atom changes from -1 to 0.

Step by step solution

01

Understand the ozone depletion process

Ozone depletion occurs when certain chemicals, such as chlorine-containing substances, destroy ozone molecules in the stratosphere, reducing the earth's protective ozone layer. The most common substances that cause ozone depletion are chlorofluorocarbons (CFCs) and other halogenated compounds.
02

Write down the chlorine-catalyzed ozone depletion reactions

The process of chlorine-catalyzed ozone depletion can be represented by the following two reactions: (1) Cl + O₃ → ClO + O₂ (2) ClO + O → Cl + O₂ The overall reaction is the sum of the two above: O₃ + O → 2O₂
03

Determine the oxidation states of Oxygen atoms

Oxidation state represents the number of electrons that an atom can gain or lose in a chemical reaction to form a bond with one or more atoms. Determine the oxidation states of Oxygen atoms in different molecules involved in the chlorine-catalyzed ozone depletion reactions, starting with ozone (O₃): - In O₃, the central Oxygen atom bonds with two external Oxygen atoms. The central Oxygen atom has an oxidation state of 0, while each external Oxygen atom has an oxidation state of -1. Now, let's look at the products after the first reaction: - In O₂, each Oxygen atom has an oxidation state of 0, as it forms a double bond with another Oxygen atom. - In ClO, the Chlorine atom has an oxidation state of +1, and the Oxygen atom has an oxidation state of -1. Looking at the products after the second reaction: - In O₂, each Oxygen atom has an oxidation state of 0. - In Cl, the Chlorine atom has an oxidation state of 0, and in O, the single Oxygen atom has an oxidation state of 0 as well.
04

Analyze the changes in oxidation states

Let's analyze the changes in the oxidation states for Oxygen atoms during the two reactions: - In reaction (1), the central Oxygen atom in O₃ (oxidation state 0) becomes part of an O₂ molecule (oxidation state 0), and one of the external Oxygen atoms in O₃ (oxidation state -1) becomes part of ClO (oxidation state -1). There are no changes in the oxidation state for the Oxygen atoms involved in this reaction. - In reaction (2), the Oxygen atom in ClO (oxidation state -1) becomes part of an O₂ molecule (oxidation state 0), and the single Oxygen atom involved in the reaction (oxidation state 0) also becomes part of an O₂ molecule (oxidation state 0). Only one Oxygen atom changes its oxidation state, from -1 to 0.
05

Answer the question

Do the reactions involved in ozone depletion involve changes in the oxidation state of the O atoms? Yes, during the chlorine-catalyzed ozone depletion process, the oxidation state of one Oxygen atom changes from -1 to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation State
Oxidation state is a useful concept in chemistry that helps us track the transfer of electrons in chemical reactions. It represents the theoretical charge on an atom if electrons were completely transferred between bonded atoms. In the context of ozone depletion reactions, the oxidation state of oxygen atoms is crucial. In ozone (\(O_3\)), oxygen atoms exhibit different oxidation states. The central oxygen atom, in particular, has an oxidation state of 0, while each of the two outer oxygen atoms has an oxidation state of -1. When these ozone molecules undergo reactions, the oxidation state of some oxygen atoms changes. For example, in the transition from a chlorinated oxide (\(ClO\)) back to oxygen gas (\(O_2\)), the oxygen involved shifts from an oxidation state of -1 to 0. This change highlights the dynamics within a chemical reaction that not immediately apparent just from looking at the substances involved.
Chlorofluorocarbons (CFCs)
Chlorofluorocarbons, commonly known as CFCs, are specific compounds containing chlorine, fluorine, and carbon. These compounds are notorious for their role in ozone layer depletion. CFCs are stable in the lower atmosphere but break down under ultraviolet light in the stratosphere, releasing chlorine atoms. Once free, these chlorine atoms become catalysts in the breakdown of ozone molecules. A single chlorine atom can destroy thousands of ozone molecules. This makes understanding and controlling CFC emissions critical for ozone layer preservation. Due to their harmful effects, CFCs have been largely phased out through international agreements such as the Montreal Protocol.
Chlorine-Catalyzed Reactions
The process of ozone depletion is heavily influenced by chlorine-catalyzed reactions. Chlorine atoms are introduced into the stratosphere through various compounds like CFCs. Here, they engage in a cycle of reactions starting with an essential interaction:
  • The chlorine atom reacts with ozone (\(O_3\)), forming chlorine monoxide (\(ClO\)) and oxygen gas (\(O_2\)).
  • Subsequently, the \(ClO\) reacts with a free oxygen atom, regenerating the chlorine atom and producing more \(O_2\).
This cycle can repeat, allowing a single chlorine atom to destroy many ozone molecules. The chlorine acts as a catalyst, meaning it facilitates the reaction without being consumed, perpetuating the breakdown process and illustrating its detrimental impact on the ozone layer.

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Most popular questions from this chapter

The main reason that distillation is a costly method for purifying water is the high energy required to heat and vaporize water. (a) Using the density, specific heat, and heat of vaporization of water from Appendix B, calculate the amount of energy required to vaporize \(1.00 \mathrm{~L}\) of water beginning with water at \(25^{\circ} \mathrm{C}\). (b) If the energy is provided by electricity costing \(\$ 0.085 / \mathrm{kWh},\) calculate its cost. \((\mathbf{c})\) If distilled water sells in a grocery store for \(\$ 0.49\) per \(L,\) what percentage of the sales price is represented by the cost of the energy?

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