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Predict whether the equivalence point of each of the following titrations is below, above, or at pH 7: (a) benzoic acid titrated with KOH, (b) ammonia titrated with iodic acid, (c) hydroxylamine with hydrochloric acid.

Short Answer

Expert verified
In summary, for the given titrations: (a) Benzoic acid (a weak acid) with KOH (a strong base) results in an equivalence point above pH 7. (b) Ammonia (a weak base) with iodic acid (a strong acid) results in an equivalence point below pH 7. (c) Hydroxylamine (a weak base) with hydrochloric acid (a strong acid) results in an equivalence point below pH 7.

Step by step solution

01

Titration (a) Benzoic acid with KOH

In this case, we have a weak acid (benzoic acid) titrated with a strong base (KOH). According to case 2 mentioned in the analysis, the equivalence point will be above pH 7.
02

Titration (b) Ammonia with iodic acid

Here, we have a weak base (ammonia) titrated with a strong acid (iodic acid). This corresponds to case 3 in the analysis, meaning the equivalence point will be below pH 7.
03

Titration (c) Hydroxylamine with hydrochloric acid

In this titration, we have a weak base (hydroxylamine) being titrated with a strong acid (hydrochloric acid). This is again in line with case 3 mentioned in the analysis, so the equivalence point will be below pH 7. In conclusion: - The equivalence point of titration (a) is above pH 7. - The equivalence point of titration (b) is below pH 7. - The equivalence point of titration (c) is below pH 7.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Titration
Titration is a laboratory technique utilized to determine the unknown concentration of a solution. It involves gradually adding a titrant, a solution of known concentration, to a known volume of a sample until the chemical reaction reaches its endpoint.
This carefully controlled addition helps identify the point where the reactants have reacted in stoichiometrically equivalent amounts, known as the equivalence point.

There are several indicators used to detect the endpoint, often involving a color change.
  • Equivalence Point: This is the stage in the titration where the amount of titrant added is just enough to completely react with the analyte.
  • Endpoint: The visible sign (such as a color change) signifying the point where the reaction appears complete.
Understanding these concepts is vital for accurately identifying the completion of titration, especially when predicting the pH at the equivalence point.
The nature of the acid and base involved in titration directly influences the pH at the equivalence point, which can be acidic, basic, or neutral.
Weak Acid-Strong Base
When a weak acid is titrated with a strong base, the solution at the equivalence point tends to be basic. This is because the strong base completely reacts with the weak acid forming its conjugate base, which can hydrolyze with water.
Let's dive deeper into this concept using benzoic acid and potassium hydroxide (KOH) as an example:
  • Benzoic Acid (C6H5COOH): A weak acid that doesn't fully dissociate in water.
  • KOH: A strong base that completely dissociates in solution.
During titration, KOH will neutralize the benzoic acid. At the equivalence point, excess benzoate ions (conjugate base) can react with H2O to produce OH-, resulting in a slightly basic solution.
This is why, for titrations involving a weak acid and strong base, the equivalence point pH is typically above 7.
Weak Base-Strong Acid
In the case of a weak base titrated with a strong acid, the situation is somewhat reversed. The equivalence point will be acidic due to the nature of the products in the reaction.
Consider ammonia and iodic acid as an illustrative example:
  • Ammonia (NH3): A weak base which accepts protons weakly.
  • Iodic Acid (HIO3): A strong acid that fully donates protons.
As the titration proceeds, the ammonia is protonated by the iodic acid, forming ammonium ions (NH4+). At the equivalence point, the ammonium (the conjugate acid) further reacts with water to produce H3O+, lowering the pH.
Thus, in weak base-strong acid titrations like with ammonia and iodic acid or hydroxylamine and hydrochloric acid, the equivalence point is usually below pH 7.

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Most popular questions from this chapter

(a) Will \(\mathrm{Ca}(\mathrm{OH})_{2}\) precipitate from solution if the \(\mathrm{pH}\) of a \(0.050 \mathrm{M}\) solution of \(\mathrm{CaCl}_{2}\) is adjusted to \(8.0 ?(\mathbf{b})\) Will \(\mathrm{Ag}_{2} \mathrm{SO}_{4}\) precipitate when \(100 \mathrm{~mL}\) of \(0.050 \mathrm{M} \mathrm{AgNO}_{3}\) is mixed with \(10 \mathrm{~mL}\) of \(5.0 \times 10^{-2} \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}\) solution?

Suggest how the cations in each of the following solution mixtures can be separated: (a) \(\mathrm{Na}^{+}\) and \(\mathrm{Cd}^{2+},(\mathbf{b}) \mathrm{Cu}^{2+}\) and \(\mathrm{Mg}^{2+},(\mathbf{c}) \mathrm{Pb}^{2+}\) and \(\mathrm{Al}^{3+},(\mathbf{d}) \mathrm{Ag}^{+}\) and \(\mathrm{Hg}^{2+} .\)

Calculate the \(\mathrm{pH}\) at the equivalence point for titrating \(0.200 \mathrm{M}\) solutions of each of the following bases with 0.200 \(M\) HBr: \((\mathbf{a})\) sodium hydroxide \((\mathrm{NaOH}),(\mathbf{b})\) hydroxylamine \(\left(\mathrm{NH}_{2} \mathrm{OH}\right),(\mathbf{c})\) aniline \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\right)\).

A 20.0-mL sample of \(0.150 \mathrm{MKOH}\) is titrated with \(0.125 \mathrm{M}\) \(\mathrm{HClO}_{4}\) solution. Calculate the pH after the following volumes of acid have been added: \((\mathbf{a}) 20.0 \mathrm{~mL},(\mathbf{b}) 23.0 \mathrm{~mL},\) (c) \(24.0 \mathrm{~mL}\) (d) \(25.0 \mathrm{~mL},\) (e) \(30.0 \mathrm{~mL}\).

Excess \(\mathrm{Ca}(\mathrm{OH})_{2}\) is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 -mL sample titrated with \(\mathrm{HCl}\) requires \(11.23 \mathrm{~mL}\) of \(0.0983 \mathrm{MHCl}\) to reach the end point. Calculate \(K_{s p}\) for \(\mathrm{Ca}(\mathrm{OH})_{2} .\) Compare your result with that in Appendix D. Suggest a reason for any differences you find between your value and the one in Appendix D.

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