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For a certain gas-phase reaction, the fraction of products in an equilibrium mixture is increased by either increasing the temperature or by increasing the volume of the reaction vessel. (a) Is the reaction exothermic or endothermic? (b) Does the balanced chemical equation have more molecules on the reactant side or product side?

Short Answer

Expert verified
(a) The reaction is endothermic, as increasing the temperature increases the fraction of products in an equilibrium mixture. (b) The balanced chemical equation has more molecules on the product side, as increasing the volume of the reaction vessel increases the fraction of products.

Step by step solution

01

When the temperature of a reaction at equilibrium is increased, the reaction will shift in the direction of the reaction that can consume the added energy (heat). If the reaction is exothermic, heat is released, and if it is endothermic, heat is absorbed. As increasing the temperature increases the fraction of products, the reaction must be shifting towards the products, indicating that it is an endothermic reaction. So, the answer to question (a) is endothermic. #Step 2: Determine if there are more molecules on the reactant or product side of the balanced chemical equation#

When the volume of a reaction mixture at equilibrium is increased, the pressure decreases, and the system will shift to the side with more moles of gas. Increasing the volume of the reaction vessel results in an increase in the fraction of products. Therefore, the reaction must be shifting towards the products side, which means the product side has more molecules than the reactant side. Thus, the answer to question (b) is that the balanced chemical equation has more molecules on the product side.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Dynamics
Reaction dynamics involve the study of how chemical reactions take place. It's all about observing and understanding how reactants transform into products. This includes looking at
  • the speed (rate) of the reaction,
  • how the reaction is influenced by different conditions,
  • and how the particles interact with each other.
In a chemical reaction at equilibrium, such as the one described in the exercise, both the forward and reverse reactions occur at the same rate. When a reaction reaches equilibrium, it doesn't mean that the reactants and products are in equal concentrations. Instead, it means their concentrations remain unchanged over time due to the balanced rates of the forward and reverse reactions.
To understand reaction dynamics deeply, envision a dynamic dance where reactants constantly become products and vice versa but always maintaining a balance.
Le Chatelier's Principle
Le Chatelier's Principle is a fundamental rule in chemistry that predicts how a system at equilibrium responds to disturbances. Imagine a balanced seesaw; if you push one side down, the other side rises to respond. Similarly, when a change (or "stress") is applied to a system at equilibrium:
  • the system will adjust to counteract the change and restore equilibrium.
  • For example, if you increase the concentration of reactants, the system will shift towards the production of more products.
  • Conversely, if you remove some products, the system will try to form more products to compensate.
In the exercise provided, increasing temperature caused the reaction to favor product formation because the system absorbed heat, indicating the reaction was endothermic. Le Chatelier's Principle also predicts that increasing the volume of the container, thus lowering pressure, makes the system shift towards the side with more gas molecules to balance the pressure change.
Endothermic Reactions
Endothermic reactions are unique because they absorb energy, often in the form of heat, from their surroundings. This means:
  • These reactions feel cold to the touch because they draw heat away from their environment.
  • Energy is considered a reactant in these reactions.
In contrast to exothermic reactions, which release heat into their surroundings, endothermic reactions require continuous energy input to proceed.
In the context of the exercise, when temperature is increased, the reaction shifts towards forming more products. This shift indicates the reaction uses the added heat, signifying it is endothermic. Understanding how endothermic reactions work can help predict how they might behave under different stressors, such as changes in temperature or pressure, similar to the principles described by Le Chatelier's Principle.

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Most popular questions from this chapter

Assume that the equilibrium constant for the dissociation of molecular bromine, \(\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{Br}(g)\), at 800 \(\mathrm{K}\) is \(K_{c}=5.4 \times 10^{-3}\). (a) Which species predominates at equilibrium, \(\mathrm{Br}_{2}\) or Br, assuming that the concentration of \(\mathrm{Br}_{2}\) is larger than \(5.4 \times 10^{-3} \mathrm{~mol} / \mathrm{L} ?\) (b) Assuming both forward and reverse reactions are elementary processes, which reaction has the larger numeric value of the rate constant, the forward or the reverse reaction?

(a) If \(Q_{c}>K_{c}\), how must the reaction proceed to reach equilibrium? (b) At the start of a certain reaction, only reactants are present; no products have been formed. What is the value of \(Q_{c}\) at this point in the reaction?

Gaseous hydrogen iodide is placed in a closed container at \(450^{\circ} \mathrm{C},\) where it partially decomposes to hydrogen and iodine: \(2 \mathrm{HI}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) .\) At equilibrium it is found that \([\mathrm{HI}]=4.50 \times 10^{3} \mathrm{M},\left[\mathrm{H}_{2}\right]=5.75 \times 10^{4} \mathrm{M}\), and \(\left[\mathrm{I}_{2}\right]=5.75 \times 10^{-4} \mathrm{M}\). What is the value of \(K_{c}\) at this temperature?

Bromine and hydrogen react in the gas phase to form hydrogen bromide: \(\mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g) .\) The reaction enthalpy is \(\Delta H^{\circ}=-6 \mathrm{~kJ} .\) (a) To increase the equilibrium yield of hydrogen bromide would you use high or low temperature? (b) Could you increase the equilibrium yield of hydrogen bromide by controlling the pressure of this reaction? If so, would high or low pressure favor formation of \(\mathrm{HBr}(g) ?\)

(a) Is the dissociation of fluorine molecules into atomic fluorine, \(\mathrm{F}_{2}(g) \rightleftharpoons 2 \mathrm{~F}(g)\) an exothermic or endothermic process? (b) If the temperature is raised by \(100 \mathrm{~K}\), does the equilibrium constant for this reaction increase or decrease? (c) If the temperature is raised by \(100 \mathrm{~K},\) does the forward rate constant \(k_{f}\) increase by a larger or smaller amount than the reverse rate constant \(k_{r} ?\)

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