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Which of the following statements are true and which are false? (a) For the reaction 2 A(g)+B(g)A2 B(g)Kc and Kp are numerically the same. (b) It is possible to distinguish Kc from Kp by comparing the units used to express the equilibrium constant. (c) For the equilibrium in (a), the value of Kc increases with increasing pressure.

Short Answer

Expert verified
Statement (a) is false, as Kc and Kp are not numerically the same for the given reaction since Δn0. Statement (b) is true, as Kc and Kp can be distinguished by their units. Statement (c) is false, as the value of Kc is not directly affected by changes in pressure but only by changes in temperature.

Step by step solution

01

a) Comparing Kc and Kp for the given reaction

For the given reaction, we have: 2A(g)+B(g)A2B(g) Kc and Kp are related by the following equation: Kp=Kc(RT)Δn where R is the gas constant, T is the temperature in Kelvin, and Δn is the change in the number of moles of gas in the balanced equation (products minus reactants). In this reaction, Δn=(1)(2+1)=2. Since Δn is not equal to 0, Kc and Kp will not be numerically the same. Therefore, statement (a) is false.
02

b) Distinguishing Kc and Kp by their units

Kc and Kp are equilibrium constants that have different units. Kc is generally expressed in terms of concentrations (moles per liter, M) while Kp is expressed in terms of partial pressures (atmospheres, atm). It is indeed possible to distinguish between Kc and Kp by comparing the units used to express the equilibrium constant. Statement (b) is true.
03

c) Effect of increasing pressure on the value of Kc

For the given reaction, the value of Kc is not directly affected by changes in pressure. Kc can only be affected by changes in temperature. The position of equilibrium, however, can be affected by changes in pressure due to Le Chatelier's principle. In the given reaction, increasing pressure would shift the equilibrium towards the side with fewer moles of gas (the right side) in order to alleviate the increased pressure. This means that the amount of A2B would increase, while the amount of A and B would decrease. This change affects the ratio of concentrations at equilibrium, but the constant Kc itself would remain unchanged. So, statement (c) is false.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant (Kc and Kp)
The equilibrium constant is a significant concept when studying reaction equilibrium. There are two types of equilibrium constants depending on how the equilibrium is expressed: Kc and Kp.

Kc is used when the equilibrium is expressed in terms of concentrations. It's calculated with concentration values, given in moles per liter (M).
On the other hand, Kp is applied when partial pressures are used, which are typically measured in atmospheres (atm).

Both Kc and Kp are related through the equation:
Kp=Kc(RT)Δn
Here, R is the ideal gas constant, T is the temperature in Kelvin, and Δn is the difference in moles of gas between products and reactants.

This relationship is crucial in determining whether Kc and Kp will have the same numerical value. If Δn=0, then Kc=Kp. However, if Δneq0, then they differ.

Understanding this helps clarify why, in some reactions, Kc and Kp are equivalent, and in others, they are not.
Le Chatelier's Principle
Le Chatelier's Principle is a foundational concept in understanding how equilibria respond to changes in their environment. It states that if a system at equilibrium is disturbed by an external change, such as pressure, temperature, or concentration, the system will adjust itself to partially counteract the effect of the change and attain a new equilibrium.

For example, consider a gaseous reaction where increasing the pressure would shift the equilibrium towards the side with fewer moles of gas. This shift happens because the system attempts to reduce the stress of increased pressure by favoring the formation of fewer gas molecules.
  • Higher pressure => shifts towards fewer moles of gas
  • Increased temperature => shifts depending on endothermic or exothermic nature of the reaction
  • Increased concentration of one species => shifts the equilibrium to consume the added species
Le Chatelier's Principle is handy for predicting how external changes will affect the direction of equilibrium shifts, but it should not be confused with changes in the equilibrium constant, Kc, which remains constant unless temperature is altered.
Reaction Stoichiometry
Reaction stoichiometry is crucial for understanding chemical reactions' balance and proportions. It focuses on the quantities of reactants and products in a chemical equation.

Using stoichiometry, we can determine how much of each substance is involved in a reaction. This involves using mole ratios derived from the balanced chemical equation, which provide insights into the quantitative relationship between reactants and products.

For example, in the reaction 2A(g)+B(g)A2B(g), stoichiometry lets us calculate the change in moles of each substance when the reaction reaches equilibrium. Here, the balanced equation shows that two moles of A and one mole of B react to form one mole of A2B.

This stoichiometric relationship helps in determining the equilibrium concentrations and is vital in calculating the equilibrium constant Kc or Kp, where the stoichiometric coefficients become the powers to which concentration or pressure terms are raised in the expression for the equilibrium constant.

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Most popular questions from this chapter

When 2.00 mol of SO2Cl2 is placed in a 5.00 -Lflaskat 310 K, 40% of the SO2Cl2 decomposes to SO2 and Cl2 : SO2Cl2(g)SO2(g)+Cl2(g) (a) Calculate Kc for this reaction at this temperature. (b) Calculate KP for this reaction at 310 K. (c) According to Le Châtelier's principle, would the percent of SO2Cl2 that decomposes increase, decrease or stay the same if the mixture was transferred to a 1.00 -L vessel? (d) Use the equilibrium constant you calculated above to determine the percentage of SO2Cl2 that decomposes when 2.00 mol of SO2Cl2 is placed in a 1.00L vessel at 310 K.

At 800 K, the equilibrium constant for the reaction A2(g)2 A(g) is Kc=3.1×104. (a) Assuming both forward and reverse reactions are elementary reactions, which rate constant do you expect to be larger, kf or kr? (b) If the value of kf=0.27 s1, what is the value of kr at 800 K? (c) Based on the nature of the reaction, do you expect the forward reaction to be endothermic or exothermic? (d) If the temperature is raised to 1000 K, will the reverse rate constant kr increase or decrease? Will the change in kr be larger or smaller than the change in kf ?

Which of the following reactions lies to the right, favoring the formation of products, and which lies to the left, favoring formation of reactants? (a) H2O(g)+CO(g)CO2(g)+H2(g) at 1300 KKc=0.57 (b) 2CO(g)CO2(g)+C(s) at 900 KKp=0.0572

For thereaction, at H2(g)+I2(g)2HI(g),Kc=55.3 at 700 K. In a 10.0-L flask containing an equilibrium mixture of the three gases, there are 1.30 gH2 and 21.0 gI2. What is the mass of HI in the flask?

In Section 11.5, we defined the vapor pressure of a liquid in terms of an equilibrium. (a) Write the equation representing the equilibrium between liquid water and water vapor and the corresponding expression for Kp(b) By using data in Appendix B, give the value of Kp for this reaction at 30C. (c) What is the value of Kp for any liquid in equilibrium with its vapor at the normal boiling point of the liquid?

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