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The addition of NO accelerates the decomposition of \(\mathrm{N}_{2} \mathrm{O}\), possibly by the following mechanism: $$ \begin{aligned} \mathrm{NO}(g)+\mathrm{N}_{2} \mathrm{O}(g) & \longrightarrow \mathrm{N}_{2}(g)+\mathrm{NO}_{2}(g) \\ 2 \mathrm{NO}_{2}(g) & \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \end{aligned} $$ (a) What is the chemical equation for the overall reaction? Show how the two steps can be added to give the overall equation. (b) Is NO serving as a catalyst or an intermediate in this reaction? (c) If experiments show that during the decomposition of \(\mathrm{N}_{2} \mathrm{O}, \mathrm{NO}_{2}\) does not accumulate in measurable quantities, does this rule out the proposed mechanism?

Short Answer

Expert verified
(a) The overall chemical equation for the reaction is: \(\mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g) + \mathrm{O}_{2}(g)\) (b) NO is serving as a catalyst in this reaction. (c) The absence of measurable NO₂ accumulation does not rule out the proposed mechanism, as it might suggest that the second step of the mechanism is much faster than the first step.

Step by step solution

01

Find the overall reaction equation

To determine the overall chemical equation, we will add the two steps of the reaction mechanism: \[ \begin{aligned} \mathrm{NO}(g)+\mathrm{N}_{2} \mathrm{O}(g) & \longrightarrow \mathrm{N}_{2}(g)+\mathrm{NO}_{2}(g) \\ 2 \mathrm{NO}_{2}(g) & \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \end{aligned} \] Add both equations together and cancel any species that appear on both sides of the equation (in this case, NO and NO₂): \[ \begin{aligned} \cancel{\mathrm{NO}(g)}+\cancel{\mathrm{N}_{2} \mathrm{O}(g)} + 2 \cancel{\mathrm{NO}_{2}(g)} & \longleftrightarrow \mathrm{N}_{2}(g)+\cancel{\mathrm{NO}_{2}(g)} + 2 \cancel{\mathrm{NO}(g)}+\mathrm{O}_{2}(g) \end{aligned} \] This simplifies to: \[ \mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g) + \mathrm{O}_{2}(g) \]
02

Determine the role of NO

To understand whether NO is serving as a catalyst or an intermediate, we should analyze how it behaves in the reaction mechanism. A catalyst speeds up the reaction by participating in the reaction steps but is not consumed in the overall reaction. An intermediate is formed and consumed during the reaction steps. In the mechanism, NO is consumed in the first step and then regenerated in the second step. Since it is not consumed in the overall reaction, NO is acting as a catalyst.
03

Discuss the effect of non-accumulating NO₂ on the proposed mechanism

The fact that experiments do not show measurable accumulation of NO₂ during the decomposition of N₂O does not necessarily rule out the proposed mechanism. It might indicate that the second step of the reaction mechanism (the decomposition of NO₂) is much faster than the first step (the reaction between NO and N₂O). In this case, the intermediate NO₂ would be rapidly consumed as soon as it is produced, making it difficult to detect its accumulation experimentally. In conclusion: (a) The overall chemical equation for the reaction is: \(\mathrm{N}_{2} \mathrm{O}(g) \longrightarrow \mathrm{N}_{2}(g) + \mathrm{O}_{2}(g)\) (b) NO is serving as a catalyst in this reaction. (c) The absence of measurable NO₂ accumulation does not rule out the proposed mechanism, as it might suggest that the second step of the mechanism is much faster than the first step.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catalyst
In chemical reactions, a catalyst is a substance that increases the reaction rate without being consumed in the process. In the decomposition of \(\mathrm{N}_2\mathrm{O}\), NO acts as a catalyst. This means it participates in the reaction steps but emerges unchanged at the end of the overall process.
A catalyst works by providing an alternative reaction pathway with a lower activation energy. This allows more reactant particles to collide effectively, speeding up the reaction.
  • Catalysts can be homogeneous (in the same phase as the reactants) or heterogeneous (in a different phase).
  • They are vital in many industrial processes, making reactions more efficient and economical.
  • Importantly, because NO is regenerated in the process, it is not present in the overall reaction equation.
Intermediate
Reaction intermediates are species that are formed during a reaction mechanism but do not appear in the overall balanced equation. In the mechanism for the \(\mathrm{N}_2\mathrm{O}\) decomposition, \(\mathrm{NO}_2\) is identified as an intermediate.
Intermediates are crucial because they help bridge the gap between reactants and products by forming transient species that facilitate the reaction pathway.
  • They are typically unstable and short-lived.
  • Evidence of intermediates often involves detecting them during the course of the reaction, although they might not accumulate if their consumption rate is high.
  • Intermediates are important for understanding reaction kinetics and helping chemists design better catalysts.
Reaction Rate
The reaction rate is a measure of how quickly reactants are converted into products in a chemical reaction. In this context, the presence of NO as a catalyst affects the reaction rate by providing a pathway with a lower activation energy.
Factors affecting reaction rate include the nature of the reactants, temperature, concentration, and the presence of a catalyst.
  • Catalysts significantly alter reaction rates without being consumed themselves.
  • The concentration of the catalyst can affect how much the reaction rate is increased.
  • Understanding reaction rates is essential in both laboratory and industrial settings to control the speed of reactions and optimize output.
Overall Reaction Equation
The overall reaction equation sums up the reactants and products of a chemical process, discounting any intermediates or catalysts involved in the multiple steps. In the decomposition of \(\mathrm{N}_2\mathrm{O}\), the overall reaction is simplified to:
\[\mathrm{N}_2 \mathrm{O}(g) \longrightarrow \mathrm{N}_2(g) + \mathrm{O}_2(g)\]
The process to obtain this involves adding up the individual steps of a reaction mechanism and canceling out species that appear on both sides of the equation.
  • Catalysts like NO do not appear in the final equation, even though they are involved in intermediate steps.
  • The overall equation provides a simplified view of the chemical transformation occurring between reactants and products.
  • This simplification is essential for stoichiometric calculations and predicting the yields of reactants and products.

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Most popular questions from this chapter

The first-order rate constant for the decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}, 2 \mathrm{~N}_{2} \mathrm{O}_{5}(g) \longrightarrow 4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g), \quad\) at \(\quad 70^{\circ} \mathrm{C}\) is \(6.82 \times 10^{-3} \mathrm{~s}^{-1}\). Suppose we start with \(0.0250 \mathrm{~mol}\) of \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) in a volume of \(2.0 \mathrm{~L} .(\mathbf{a})\) How many moles of \(\mathrm{N}_{2} \mathrm{O}_{5}\) will remain after \(5.0 \mathrm{~min} ?\) (b) How many minutes will it take for the quantity of \(\mathrm{N}_{2} \mathrm{O}_{5}\) to drop to \(0.010 \mathrm{~mol}\) ? (c) What is the half-life of \(\mathrm{N}_{2} \mathrm{O}_{5}\) at \(70{ }^{\circ} \mathrm{C}\) ?

The iodide ion reacts with hypochlorite ion (the active ingredient in chlorine bleaches) in the following way: \(\mathrm{OCl}^{-}+\mathrm{I}^{-} \longrightarrow \mathrm{OI}^{-}+\mathrm{Cl}^{-} .\) This rapid reaction gives the following rate data: $$ \begin{array}{ccc} \hline\left[\mathrm{OCI}^{-}\right](M) & {\left[\mathrm{I}^{-}\right](M)} & \text { Initial Rate }(\mathrm{M} / \mathrm{s}) \\ \hline 1.5 \times 10^{-3} & 1.5 \times 10^{-3} & 1.36 \times 10^{-4} \\ 3.0 \times 10^{-3} & 1.5 \times 10^{-3} & 2.72 \times 10^{-4} \\ 1.5 \times 10^{-3} & 3.0 \times 10^{-3} & 2.72 \times 10^{-4} \\ \hline \end{array} $$ (a) Write the rate law for this reaction. (b) Calculate the rate constant with proper units. (c) Calculate the rate when \(\left[\mathrm{OCl}^{-}\right]=2.0 \times 10^{-3} \mathrm{M}\) and \(\left[\mathrm{I}^{-}\right]=5.0 \times 10^{-4} \mathrm{M}\)

Platinum nanoparticles of diameter \(\sim 2 \mathrm{nm}\) are important catalysts in carbon monoxide oxidation to carbon dioxide. Platinum crystallizes in a face-centered cubic arrangement with an edge length of \(392.4 \mathrm{pm} .(\mathbf{a})\) Estimate how many platinum atoms would fit into a \(2.0-\mathrm{nm}\) sphere; the volume of a sphere is \((4 / 3) \pi r^{3} .\) Recall that \(1 \mathrm{pm}=1 \times 10^{-12} \mathrm{~m}\) and \(1 \mathrm{nm}=1 \times 10^{-9} \mathrm{~m} .(\mathbf{b})\) Estimate how many platinum atoms are on the surface of a 2.0-nm Pt sphere, using the surface area of a sphere \(\left(4 \pi r^{2}\right)\) and assuming that the "footprint" of one Pt atom can be estimated from its atomic diameter of \(280 \mathrm{pm}\) (c) Using your results from (a) and (b), calculate the percentage of \(\mathrm{Pt}\) atoms that are on the surface of a \(2.0-\mathrm{nm}\) nanoparticle. (d) Repeat these calculations for a 5.0-nm platinum nanoparticle. (e) Which size of nanoparticle would you expect to be more catalytically active and why?

(a) What is meant by the term elementary reaction? (b) What is the difference between a unimolecular and a bimolecular elementary reaction? (c) What is a reaction mechanism? (d) What is meant by the term rate determining step?

(a) Consider the combustion of ethylene, \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+\) \(3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) .\) If the concentration of \(\mathrm{C}_{2} \mathrm{H}_{4}\) is decreasing at the rate of \(0.025 \mathrm{M} / \mathrm{s}\), what are the rates of change in the concentrations of \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) ? (b) The rate of decrease in \(\mathrm{N}_{2} \mathrm{H}_{4}\) partial pressure in a closed reaction vessel from the reaction \(\mathrm{N}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)\) is \(10 \mathrm{kPa}\) per hour. What are the rates of change of \(\mathrm{NH}_{3}\) partial pressure and total pressure in the vessel?

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