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(a) Most commercial heterogeneous catalysts are extremely finely divided solid materials. Why is particle size important? (b) What role does adsorption play in the action of a heterogeneous catalyst?

Short Answer

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Particle size is essential in commercial heterogeneous catalysts because it directly affects the surface area exposed to reactants. Finely divided solid particles offer increased surface area, leading to more reaction sites and higher reaction rates. Adsorption plays a significant role in heterogeneous catalysis by bringing reactant molecules close together, weakening bond strengths, providing alternative reaction pathways and enabling better control over reaction conditions. This enhances and controls rate of chemical reactions, reduces energy costs, and ultimately improves process efficiency.

Step by step solution

01

Understanding heterogeneous catalysts

Heterogeneous catalysts are catalysts that are in a different phase than the reactants. They are typically solid materials that help speed up chemical reactions without being consumed in the process. Heterogeneous catalysts generally work by providing a surface for the reactants to interact with, reducing the energy barrier required for a successful reaction to take place. ### Step 2: The importance of particle size in heterogeneous catalysts ###
02

Importance of particle size

Particle size is crucial in commercial heterogeneous catalysts because it directly affects the surface area of the catalyst exposed to the reactants. When a solid catalyst is finely divided into smaller particles, the surface area per unit mass increases, which implies that more reaction sites are available for the reactants to interact. This increased surface area consequently leads to higher reaction rates and improved efficiency. ### Step 3: Understanding adsorption ###
03

Adsorption

Adsorption is a process where a substance (like a reactant molecule) accumulates on the surface of a solid or liquid material, such as a catalyst particle. In the context of heterogeneous catalysis, adsorption indicates the binding of reactant molecules onto the catalyst's surface, which typically involves chemical or physical forces. Adsorption can be classified into two categories: physisorption, which involves weak van der Waals forces, and chemisorption, which involves stronger covalent or ionic bonds between the reactant and the catalyst. ### Step 4: The role of adsorption in heterogeneous catalysis ###
04

Role of adsorption in heterogeneous catalysis

Adsorption plays a vital role in the action of a heterogeneous catalyst by facilitating the chemical reaction in the following ways: 1. Bringing reactant molecules close together on the catalyst surface, thereby increasing the probability of a successful collision and reaction. 2. Weakening the bonds within the reactant molecules, which lowers the activation energy required for the reaction to proceed. 3. Providing an alternative reaction pathway that may involve intermediates formed during the adsorption process. 4. Enabling better control over reaction conditions, such as temperature and pressure, which can affect the rate of adsorption and determine the selectivity of specific reactions. By adsorbing reactants on its surface, a heterogeneous catalyst can enhance and control the rate of chemical reactions, reduce energy costs, and ultimately improve process efficiency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Particle Size
Particle size is a critical factor in determining the effectiveness of a heterogeneous catalyst. Imagine a solid block of material designated as a catalyst. The outer surface area is limited, which means fewer sites for the reactant molecules to interact with. However, when this block is finely divided into smaller particles, the total surface area increases significantly.

This increase in surface area due to smaller particle size allows more reaction sites to become available on the catalyst. More available sites mean that more reactant molecules can adsorb on the catalyst simultaneously, facilitating multiple reactions at once. Think of it as opening more doors for the molecules to access the catalyst.

In practical applications, this means that finely divided catalysts can lead to higher reaction rates and greater efficiency. Industries often optimize particle size to ensure that the catalyst is neither too fine, leading to agglomeration, nor too large, reducing surface area. Thus, the right balance of particle size enhances the overall efficiency and reaction speed.
Adsorption
Adsorption is the process where molecules from a gas or liquid accumulate on a solid surface, such as a catalyst. In heterogeneous catalysis, adsorption is an essential first step that enables the reactants to interact closely with the catalyst's surface.

There are two primary types of adsorption:
  • **Physisorption**: This involves the adsorption through weak forces known as Van der Waals forces. It is generally reversible and does not require significant energy to occur.
  • **Chemisorption**: This type involves the formation of stronger chemical bonds between the reactant molecules and the catalyst surface. It is usually accompanied by an energy change and is not easily reversible.
In catalysis, adsorption helps to bind reactant molecules onto the active sites of the catalyst, altering their bonds, which is crucial for the reaction to proceed efficiently.

This process enables the conversion of reactants into products more smoothly by lowering the energy barriers, thus increasing the reaction's rate.
Reaction Efficiency
Reaction efficiency in the context of heterogeneous catalysis hinges significantly on how well the catalyst performs its role. Here, the efficiency is about how quickly and completely a reaction converts reactants into desired products.

A few ways through which a catalyst can boost reaction efficiency include:
  • **Improved Accessibility**: With a catalyst that has been optimally divided into fine particles, more sites are accessible for reactions, hence increasing the reaction rate time.
  • **Energy Cost Reduction**: Catalysts work by lowering the activation energy of reactions. Lower energy requirements mean that reactions can occur at lower temperatures, saving energy.
  • **Pathway Alteration**: Catalysts can offer alternative pathways for reactions, often facilitating mechanisms that avoid higher energy intermediates.
By enhancing these aspects, a well-designed heterogeneous catalyst can lead to higher selectivity of products, meaning fewer unwanted by-products and higher yields of the desired product. This increased efficiency is crucial in industrial applications where cost-effectiveness and resource utilization are essential.
Catalyst Surface Area
The surface area of a catalyst plays a pivotal role in determining its activity in catalytic processes. Surface area refers to the total area available on a catalyst for the adsorption of reactant molecules.

A larger surface area implies more accessible sites for adsorption, which is directly linked to the catalyst's performance. By increasing the surface area, more reactants can interact with the catalyst at the same time, leading to an increased rate of reaction.

Typically, catalysts with a large surface area are achieved through processes such as:
  • **Finely Dividing the Catalyst**: Smaller particles increase the overall surface area.
  • **Creating Porosity**: Catalysts might be designed to have a porous structure, providing an internal surface that boosts total available surface area.
The optimization of surface area ensures high efficiency of the catalyst and is a key factor considered during the preparation of catalysts in industry, especially for large-scale chemical production. This is because more surface area means more reactions can happen concurrently, improving the overall productivity and efficiency of the process.

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Most popular questions from this chapter

Consider the following reaction between mercury(II) chloride and oxalate ion: $$ 2 \mathrm{HgCl}_{2}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q) \longrightarrow 2 \mathrm{Cl}^{-}(a q)+2 \mathrm{CO}_{2}(g)+\mathrm{Hg}_{2} \mathrm{Cl}_{2}(s) $$ The initial rate of this reaction was determined for several concentrations of \(\mathrm{HgCl}_{2}\) and \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\), and the following rate data were obtained for the rate of disappearance of \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\) : $$ \begin{array}{llll} \hline \text { Experiment } & {\left[\mathrm{HgCl}_{2}\right](M)} & {\left[\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\right](M)} & \text { Rate }(M / \mathrm{s}) \\ \hline 1 & 0.164 & 0.15 & 3.2 \times 10^{-5} \\ 2 & 0.164 & 0.45 & 2.9 \times 10^{-4} \\ 3 & 0.082 & 0.45 & 1.4 \times 10^{-4} \\ 4 & 0.246 & 0.15 & 4.8 \times 10^{-5} \\ \hline \end{array} $$ (a) What is the rate law for this reaction? (b) What is the value of the rate constant with proper units? (c) What is the reaction rate when the initial concentration of \(\mathrm{HgCl}_{2}\) is \(0.100 \mathrm{M}\) and that of \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\) is \(0.25 \mathrm{M}\) if the temperature is the same as that used to obtain the data shown?

(a) What factors determine whether a collision between two molecules will lead to a chemical reaction? (b) Does the rate constant for a reaction generally increase or decrease with an increase in reaction temperature? (c) Which factor is most sensitive to changes in temperature-the frequency of collisions, the orientation factor, or the fraction of molecules with energy greater than the activation energy?

The reaction between ethyl bromide \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right)\) and hydroxide ion in ethyl alcohol at \(330 \mathrm{~K}\), \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{Br}^{-}(a l c),\) is first order each in ethyl bromide and hydroxide ion. When \(\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Br}\right]\) is \(0.0477 \mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]\) is \(0.100 \mathrm{M},\) the rate of disappearance of ethyl bromide is \(1.7 \times 10^{-7} \mathrm{M} / \mathrm{s}\). (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) How would the rate of disappearance of ethyl bromide change if the solution were diluted by adding an equal volume of pure ethyl alcohol to the solution?

You perform a series of experiments for the reaction \(\mathrm{A} \rightarrow 2 \mathrm{~B}\) and find that the rate law has the form, rate \(=k[\mathrm{~A}]^{x} .\) Determine the value of \(x\) in each of the following cases: (a) The rate increases by a factor of \(6.25,\) when \([\mathrm{A}]_{0}\) is increased by a factor of \(2.5 .(\mathbf{b})\) There is no rate change when \([\mathrm{A}]_{0}\) is increased by a factor of \(4 .(\mathbf{c})\) The rate decreases by a factor of \(1 / 2,\) when \([\mathrm{A}]_{0}\) is cut in half.

The first-order rate constant for the decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}, 2 \mathrm{~N}_{2} \mathrm{O}_{5}(g) \longrightarrow 4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g), \quad\) at \(\quad 70^{\circ} \mathrm{C}\) is \(6.82 \times 10^{-3} \mathrm{~s}^{-1}\). Suppose we start with \(0.0250 \mathrm{~mol}\) of \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) in a volume of \(2.0 \mathrm{~L} .(\mathbf{a})\) How many moles of \(\mathrm{N}_{2} \mathrm{O}_{5}\) will remain after \(5.0 \mathrm{~min} ?\) (b) How many minutes will it take for the quantity of \(\mathrm{N}_{2} \mathrm{O}_{5}\) to drop to \(0.010 \mathrm{~mol}\) ? (c) What is the half-life of \(\mathrm{N}_{2} \mathrm{O}_{5}\) at \(70{ }^{\circ} \mathrm{C}\) ?

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