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For each of the following gas-phase reactions, write the rate expression in terms of the appearance of each product and disappearance of each reactant: (a) \(\mathrm{O}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow 2 \mathrm{O}_{2}(g)+\mathrm{H}_{2}(g)\) (b) \(4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\) (c) \(2 \mathrm{C}_{2} \mathrm{H}_{2}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{3} \mathrm{H}_{6}(g)+\mathrm{NH}_{3}(g)\)

Short Answer

Expert verified
The rate expressions for the given reactions are: (a) Rate = -\(\frac{d[O_3]}{dt}\) = -\(\frac{d[H_2O]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[O_2]}{dt}\) = \(\frac{d[H_2]}{dt}\) (b) Rate = -\(\frac{1}{4}\) \(\frac{d[NH_3]}{dt}\) = -\(\frac{1}{5}\) \(\frac{d[O_2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[NO]}{dt}\) = \(\frac{1}{6}\) \(\frac{d[H_2O]}{dt}\) (c) Rate = -\(\frac{1}{2}\) \(\frac{d[C_2H_2]}{dt}\) = -\(\frac{1}{5}\) \(\frac{d[O_2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[CO_2]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[H_2O]}{dt}\) (d) Rate = -\(\frac{d[C_3H_7NH_2]}{dt}\) = \(\frac{d[C_3H_6]}{dt}\) = \(\frac{d[NH_3]}{dt}\)

Step by step solution

01

Analyzing Coefficients

In this reaction, all reactants and products have a coefficient of 1, except for O2 which has a coefficient of 2.
02

Rates of Appearance and Disappearance

Using the coefficients, the rate expression can be written as: Rate = -\(\frac{1}{1}\) \(\frac{d[O_3]}{dt}\) = -\(\frac{1}{1}\) \(\frac{d[H_2O]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[O_2]}{dt}\) = \(\frac{1}{1}\) \(\frac{d[H_2]}{dt}\) (b) \(4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\)
03

Analyzing Coefficients

The coefficients for this reaction are 4 for NH3, 5 for O2, 4 for NO, and 6 for H2O.
04

Rates of Appearance and Disappearance

Using the coefficients, the rate expression can be written as: Rate = -\(\frac{1}{4}\) \(\frac{d[NH_3]}{dt}\) = -\(\frac{1}{5}\) \(\frac{d[O_2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[NO]}{dt}\) = \(\frac{1}{6}\) \(\frac{d[H_2O]}{dt}\) (c) \(2 \mathrm{C}_{2} \mathrm{H}_{2}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\)
05

Analyzing Coefficients

The coefficients for this reaction are 2 for C2H2, 5 for O2, 4 for CO2, and 2 for H2O.
06

Rates of Appearance and Disappearance

Using the coefficients, the rate expression can be written as: Rate = -\(\frac{1}{2}\) \(\frac{d[C_2H_2]}{dt}\) = -\(\frac{1}{5}\) \(\frac{d[O_2]}{dt}\) = \(\frac{1}{4}\) \(\frac{d[CO_2]}{dt}\) = \(\frac{1}{2}\) \(\frac{d[H_2O]}{dt}\) (d) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{NH}_{2}(g) \longrightarrow \mathrm{C}_{3} \mathrm{H}_{6}(g)+\mathrm{NH}_{3}(g)\)
07

Analyzing Coefficients

In this reaction, all of the substances have a coefficient of 1.
08

Rates of Appearance and Disappearance

Using the coefficients, the rate expression can be written as: Rate = -\(\frac{1}{1}\) \(\frac{d[C_3H_7NH_2]}{dt}\) = \(\frac{1}{1}\) \(\frac{d[C_3H_6]}{dt}\) = \(\frac{1}{1}\) \(\frac{d[NH_3]}{dt}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Expressions
In the study of reaction kinetics, a rate expression is a mathematical equation that shows the relationship between the rate of a chemical reaction and the concentrations of the reactants and products. It helps us understand how quickly or slowly a reaction proceeds over time. Rate expressions use the concept of rates of appearance and disappearance of substances in a chemical reaction.
For a general gas-phase reaction formula
  • A + B \rightarrow C + D
the rate expression can be shown as:
  • Rate = -\(\frac{1}{a}\) \(\frac{d[A]}{dt}\) = -\(\frac{1}{b}\) \(\frac{d[B]}{dt}\) = \(\frac{1}{c}\) \(\frac{d[C]}{dt}\) = \(\frac{1}{d}\) \(\frac{d[D]}{dt}\)
Here, the negative signs for reactants indicate their consumption over time, while positive signs for products show their formation. The terms \(\frac{d[A]}{dt}\), \(\frac{d[B]}{dt}\), \(\frac{d[C]}{dt}\), and \(\frac{d[D]}{dt}\) represent the change in concentration per unit time for each species. Dividing by their respective coefficients ensures that the rate calculation is consistent throughout the reaction.
Gas-Phase Reactions
Gas-phase reactions involve substances in the gaseous state interacting with one another to form new products. These types of reactions are important in fields like atmospheric chemistry and industrial processes. Understanding gas-phase reactions can help in developing clean energy technologies and reducing environmental pollution.
Characteristics of gas-phase reactions include:
  • High molecular mobility: Particles are free to move and collide, increasing reaction rates.
  • Volume and pressure dependency: Reaction rates can be affected by changes in pressure and volume.
  • Homogeneity: All reactants and products are in the same state, making reactions comparably predictable.
In these reactions, the rate expression provides insight into how efficiently reactants transform into products under certain conditions. Observing the behavior of gases can involve measuring pressure changes or detecting concentration shifts.
Coefficients Analysis
Analyzing the coefficients in a chemical reaction is crucial when writing rate expressions. Coefficients indicate the number of moles of each substance involved. They help balance the chemical equation and ensure the mass is conserved across the reaction.
In rate expressions, coefficients play a role in adjusting rate calculations to reflect the stoichiometry of the reaction. For example, in the reaction
  • \(2 \text{A} + 3 \text{B} \rightarrow \text{C} + 4 \text{D}\)
the coefficients \(2, 3, 1,\) and \(4\) tell us how the molecules relate to each other.
When writing rate expressions:
  • Dividing the rate of change of concentration by the coefficient ensures the reaction rates of reactants and products are directly comparable, even if the number of molecules differs.
  • Each term in the rate expression provides insight into how the change of one component might affect the entire reaction process, proportional to its coefficient.
By analyzing these coefficients, one can determine how the manipulation of reactant concentrations or reaction conditions might accelerate or decelerate the chemical process.

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Most popular questions from this chapter

The reaction \(2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\) is second order in \(\mathrm{NO}\) and first order in \(\mathrm{O}_{2} .\) When \([\mathrm{NO}]=0.040 \mathrm{M}\) and \(\left[\mathrm{O}_{2}\right]=0.035 \mathrm{M},\) the observed rate of disappearance of \(\mathrm{NO}\) is \(9.3 \times 10^{-5} \mathrm{M} / \mathrm{s} .(\mathbf{a})\) What is the rate of disappearance of \(\mathrm{O}_{2}\) at this moment? (b) What is the value of the rate constant? (c) What are the units of the rate constant? (d) What would happen to the rate if the concentration of NO were increased by a factor of \(1.8 ?\)

Ozone in the upper atmosphere can be destroyed by the following two-step mechanism: $$ \begin{aligned} \mathrm{Cl}(g)+\mathrm{O}_{3}(g) & \longrightarrow \mathrm{ClO}(g)+\mathrm{O}_{2}(g) \\ \mathrm{ClO}(g)+\mathrm{O}(g) & \longrightarrow \mathrm{Cl}(g)+\mathrm{O}_{2}(g) \end{aligned} $$ (a) What is the overall equation for this process? (b) What is the catalyst in the reaction? (c) What is the intermediate in the reaction?

For each of the following gas-phase reactions, indicate how the rate of disappearance of each reactant is related to the rate of appearance of each product: (a) \(\mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\) (b) \(2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NOCl}(g)\) (c) \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \longrightarrow 2 \mathrm{NO}_{2}(g)\)

(a) The reaction \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q)+\) \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(a q)\) is first order with in \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}(a q)\) and zero-order in \(\mathrm{H}_{2} \mathrm{O}\). At \(300 \mathrm{~K}\) the rate constant equals \(3.30 \times 10^{-2} \mathrm{~min}^{-1} .\) Calculate the half- life at this temperature. \((\mathbf{b})\) If the activation energy for this reaction is \(80.0 \mathrm{~kJ} / \mathrm{mol}\), at what temperature would the reaction rate be doubled?

The activation energy of an uncatalyzed reaction is \(95 \mathrm{~kJ} / \mathrm{mol}\). The addition of a catalyst lowers the activation energy to \(55 \mathrm{~kJ} / \mathrm{mol}\). Assuming that the collision factor remains the same, by what factor will the catalyst increase the rate of the reaction at (a) \(25^{\circ} \mathrm{C},(\mathbf{b}) 125^{\circ} \mathrm{C} ?\)

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