Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Indicate whether each statement is true or false: \((\) a) \(\mathrm{NaCl}\) dissolves in water but not in benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) because benzene is denser than water. (b) NaCl dissolves in water but not in benzene because water has a large dipole moment and benzene has zero dipole moment. (c) NaCl dissolves in water but not in benzene because the water-ion interactions are stronger than benzene-ion interactions.

Short Answer

Expert verified
(a) False, (b) True, (c) True. The solubility of NaCl depends on the interactions between the solute and the solvent, not their densities. NaCl dissolves in polar solvents like water due to its large dipole moment, and strong water-ion interactions. It does not dissolve in nonpolar solvents like benzene with zero dipole moment and weak benzene-ion interactions.

Step by step solution

01

Statement A: NaCl dissolves in water but not in benzene because benzene is denser than water.

This statement is false because the solubility of NaCl in a solvent depends on the interactions between the solute (NaCl) and the solvent (water or benzene), not on the density of the solvent.
02

Statement B: NaCl dissolves in water but not in benzene because water has a large dipole moment and benzene has zero dipole moment.

This statement is true. NaCl is an ionic compound, so it dissolves in polar solvents like water, which have a large dipole moment. Benzene, being a nonpolar solvent with zero dipole moment, cannot dissolve NaCl due to lack of strong interactions between the ions of NaCl and benzene molecules.
03

Statement C: NaCl dissolves in water but not in benzene because the water-ion interactions are stronger than benzene-ion interactions.

This statement is also true. In order for NaCl to dissolve in a solvent, the solvent-solute interactions must be strong enough to overcome the ionic bonds in NaCl. In water, the strong water-ion interactions, due to hydrogen bonding, are capable of breaking the ionic bonds in NaCl and allowing it to dissolve. However, in benzene, the interactions between the benzene molecules and the ions in NaCl are weak, so NaCl does not dissolve.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dipole Moment
A dipole moment is a measure of the polarity of a chemical bond within a molecule. It occurs when there is an unequal distribution of electrons between two atoms in a bond, leading to one end being slightly more positive and the other more negative. This polarity arises because different atoms have different electronegativities – the ability to attract electrons.

For instance, in water (\(\text{H}_2\text{O}\)), the oxygen atom is more electronegative than the hydrogen atoms. This makes the region around the oxygen atom more negatively charged, giving water a significant dipole moment. This characteristic is essential for water's ability to dissolve many substances, like ionic compounds.
  • High dipole moment: indicates a strong polarity
  • Zero dipole moment: means no polarity, as seen in molecules like benzene (\(\text{C}_6\text{H}_6\))
Ionic Compounds
Ionic compounds are formed when atoms transfer electrons to achieve a full outer shell of electrons, resulting in the formation of charged ions. These ions are held together by ionic bonds, which are the strong electrostatic forces of attraction between the oppositely charged ions.

Typical examples include common table salt, \(\text{NaCl}\), where sodium (\(\text{Na}^+\)) and chloride (\(\text{Cl}^-\)) ions bond together. In order for these compounds to dissolve, the solvent must be able to disrupt these strong ionic bonds. Water is particularly good at this due to its polar nature and ability to form strong ion-dipole interactions.
  • Made up of charged ions
  • Generally have high melting and boiling points
  • Conduct electricity when molten or dissolved in water
Polar Solvents
Polar solvents, such as water, are liquids that have molecules with significant electric dipole moments. This means they have partially charged regions within the molecule, contributing to their high polarity. Such solvents are excellent at dissolving ionic compounds because they can surround and stabilize the ions.

Water is the quintessential polar solvent, known for its ability to dissolve a wide range of salts, acids, and other ionic substances. This is because water molecules can form hydrogen bonds and effectively compete with the ionic bonds in compounds like \(\text{NaCl}\), separating the ions and allowing them to disperse in solution.
  • Can dissolve ionic and polar solutes
  • Examples include water, methanol, and ethanol
  • Effective at affecting reactions involving charged species
Nonpolar Solvents
Nonpolar solvents are liquids that consist of molecules without a significant dipole moment, meaning they lack the charged regions found in polar substances. This makes them ineffective at dissolving ionic compounds, such as \(\text{NaCl}\), which depend on strong ion-dipole interactions for dissolution.

Benzene is a classic example of a nonpolar solvent. It has a symmetrical ring structure and evenly distributed electron clouds, reducing the chance of forming dipoles.
  • Poor at dissolving ionic substances but effective for nonpolar solutes
  • Include solvents like benzene, hexane, and toluene
  • Often used in organic chemistry to dissolve grease, oils, and other nonpolar compounds

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

During a person's typical breathing cycle, the \(\mathrm{CO}_{2}\) concentration in the expired air rises to a peak of \(4.6 \%\) by volume. (a) Calculate the partial pressure of the \(\mathrm{CO}_{2}\) in the expired air at its peak, assuming \(101.3 \mathrm{kPa}\) pressure and a body temperature of \(37^{\circ} \mathrm{C}\). (b) What is the molarity of the \(\mathrm{CO}_{2}\) in the expired air at its peak, assuming a body temperature of \(37^{\circ} \mathrm{C} ?\)

Indicate whether each statement is true or false: (a) A solute will dissolve in a solvent if solute-solute interactions are stronger than solute-solvent interactions. (b) In making a solution, the enthalpy of mixing is always a positive number. (c) An increase in entropy favors mixing.

Commercial concentrated aqueous ammonia is \(28 \% \mathrm{NH}_{3}\) by mass and has a density of \(0.90 \mathrm{~g} / \mathrm{mL}\). What is the molarity of this solution?

The density of acetonitrile \(\left(\mathrm{CH}_{3} \mathrm{CN}\right)\) is \(0.786 \mathrm{~g} / \mathrm{mL}\) and the density of methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) is \(0.791 \mathrm{~g} / \mathrm{mL}\). A solution is made by dissolving \(25.0 \mathrm{~mL}\) of \(\mathrm{CH}_{3} \mathrm{OH}\) in \(100 \mathrm{~mL}\) of \(\mathrm{CH}_{3} \mathrm{CN}\) (a) What is the mole fraction of methanol in the solution? (b) What is the molality of the solution? (c) Assuming that the volumes are additive, what is the molarity of \(\mathrm{CH}_{3} \mathrm{OH}\) in the solution?

Lauryl alcohol is obtained from coconut oil and is used to make detergents. A solution of \(5.00 \mathrm{~g}\) of lauryl alcohol in \(0.100 \mathrm{~kg}\) of benzene freezes at \(4.1^{\circ} \mathrm{C}\). What is the molar mass of lauryl alcohol from this data?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free