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Write a balanced chemical equation for the formation of a polymer via a condensation reaction from the monomers 1,4-phenylenediamine \(\left(\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\right)\) and terephthalic acid \(\left(\mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH}\right)\)

Short Answer

Expert verified
The balanced chemical equation for the formation of a polymer via a condensation reaction between 1,4-phenylenediamine $\left(\mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\right)$ and terephthalic acid $\left(\mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH}\right)$ is: \( \mathrm{H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH}_{2} + \mathrm{HOOCC}_{6} \mathrm{H}_{4} \mathrm{COOH \to [H}_{2} \mathrm{NC}_{6} \mathrm{H}_{4} \mathrm{NH - CO - C}_{6} \mathrm{H}_{4} \mathrm{CO]_n + \mathrm{H}_{2} \mathrm{O} \)

Step by step solution

01

Identify the reacting groups of the monomers

In the monomers, 1,4-phenylenediamine has two amino groups (-NH_2), and terephthalic acid has two carboxylic acid groups (-COOH). These groups will react to form an amide bond (-CONH-) and release a water molecule.
02

Write the chemical equation for the reaction

The condensation reaction between 1,4-phenylenediamine and terephthalic acid can be represented as: H_2NC_6H_4NH_2 + HOOC - C_6H_4 - COOH → [H_2NC_6H_4NH - CO - C_6H_4 - CO]n + H_2O Here, [H_2NC_6H_4NH - CO - C_6H_4 - CO]n represents the repeating unit of the polymer, and n is the degree of polymerization.
03

Balance the chemical equation

In this case, the chemical equation is already balanced as each side of the equation contains the same number of atoms for each element (2 H, 1 N, 4 C for the 1,4-phenylenediamine monomer and 8 H, 2 O, and 8 C for the terephthalic acid monomer). Therefore, the balanced chemical equation for the formation of the polymer via this condensation reaction is: H_2NC_6H_4NH_2 + HOOC - C_6H_4 - COOH → [H_2NC_6H_4NH - CON(C_6H_4)]n + H_2O

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polymer Formation
Polymer formation through a condensation reaction involves combining monomers to create long-chain polymer molecules. In the case of 1,4-phenylenediamine and terephthalic acid, these monomers join by establishing amide bonds through eliminating a molecule of water. This kind of reaction not only extends the chain length but also builds stronger polymer structures. The newly formed amide linkages increase the chain's rigidity and strength. As monomers combine, their functional groups react; here, the amino groups (-NH₂) of 1,4-phenylenediamine react with the carboxylic acid groups (-COOH) of terephthalic acid to form the polyamide chain. The repeating unit of the polymer acts as the foundation and dictates the overall properties of the resulting material.
Balanced Chemical Equation
A balanced chemical equation accurately portrays the reactants and products involved in a chemical reaction. Ensuring that the number of atoms for each element is equal on both sides of the equation is vital. In our polymerization example, the equation provided: H₂NC₆H₄NH₂ + HOOC-C₆H₄-COOH → [H₂NC₆H₄NH-CO-C₆H₄-CO]ₙ + H₂O This equation captures the major reactants and the resulting polyamide formed. Each atom count is maintained across the equation, indicating a sound balance. To write a balanced equation, follow these steps:
  • Identify the functional groups and reacting portions of each monomer.
  • Calculate the atoms on both sides of the equation.
  • Confirm that all elements balance, resulting in no excess atoms or molecules left out.
Balancing equations is fundamental in illustrating conservation of mass and showing that the reaction metrics adhere to empirical laws.
Amide Bond
Amide bonds are crucial connections within polymer chains formed through condensation reactions. In the synthesis of repeating polyamide units, an amide bond (-CONH-) connects monomers. How do these bonds form? When primary amines (-NH₂) react with carboxylic acids (-COOH), the loss of a water molecule leads to the covalent linkage called an amide bond:
  • The amino group's nitrogen atom attaches to the carbon atom in the carboxyl group, while a hydroxyl group (-OH) and a hydrogen (-H) are removed as water.
  • This new amide linkage acts as a sturdy chain in polymers, contributing to the toughness and heat resistance typical of many polyamide materials such as nylon.
Understanding amide bonds provides insights into polymer durability and performance, which makes them desirable for many industrial applications.
Degree of Polymerization
The degree of polymerization (DP) refers to the total number of repeating units within a polymer molecule. It provides insight into the length and, therefore, the properties of the polymer. For any polymerization reaction described, the value of "n" in the equation [H₂NC₆H₄NH-CO-C₆H₄-CO]ₙ indicates this degree. The larger the "n",
  • The longer the polymer chain, resulting in increased material strength and durability.
  • Increased viscosity and melting point.
  • Altered mechanical properties which may include elasticity, rigidity, or toughness depending on the polymer type.
Understanding DP helps us tailor the polymer synthesis to meet specific engineering and commercial requirements, creating materials with precisely controlled attributes.

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Most popular questions from this chapter

The karat scale used to describe gold alloys is based on mass percentages. (a) If an alloy is formed that is \(75 \mathrm{~mol} \%\) silver and \(25 \mathrm{~mol} \%\) gold, what is the karat number of the alloy? Use Figure 12.18 to estimate the color of this alloy. (b) If an alloy is formed that is 75 mol\% copper and 25 mol\% gold, what is the karat number of the alloy? What is the color of this alloy?

Covalent bonding occurs in both molecular and covalentnetwork solids. Which of the following statements best explains why these two kinds of solids differ so greatly in their hardness and melting points? (a) The molecules in molecular solids have stronger covalent bonding than covalent-network solids do. (b) The molecules in molecular solids are held together by weak intermolecular interactions. (c) The atoms in covalent-network solids are more polarizable than those in molecular solids. (d) Molecular solids are denser than covalent-network solids.

An element crystallizes in a face-centered cubic lattice. The edge of the unit cell is \(0.408 \mathrm{nm}\), and the density of the crystal is \(10.49 \mathrm{~g} / \mathrm{cm}^{3}\). Calculate the atomic weight of the element and identify the element.

(a) What molecular features make a polymer flexible? (b) If you cross-link a polymer, is it more flexible or less flexible than it was before?

Which of these statements about alloys and intermetallic compounds is false? (a) Bronze is an example of an alloy. (b) "Alloy" is just another word for "a chemical compound of fixed composition that is made of two or more metals." (c) Intermetallics are compounds of two or more metals that have a definite composition and are not considered alloys. (d) If you mix two metals together and, at the atomic level, they separate into two or more different compositional phases, you have created a heterogeneous alloy. (e) Alloys can be formed even if the atoms that comprise them are rather different in size.

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