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Appendix \(\mathrm{B}\) lists the vapor pressure of water at various external pressures. (a) Plot the data in Appendix B,vapor pressure versus temperature \(\left({ }^{\circ} \mathrm{C}\right) .\) From your plot, estimate the vapor pressure of water at body temperature, \(37^{\circ} \mathrm{C}\). (b) Explain the significance of the data point at \(101.3 \mathrm{kPa}, 100^{\circ} \mathrm{C} .(\mathbf{c}) \mathrm{A}\) city at an altitude of \(1525 \mathrm{~m}\) above sea level has a barometric pressure of \(84.3 \mathrm{kPa}\). To what temperature would you have to heat water to boil it in this city? (d) A city at an altitude of \(150 \mathrm{~m}\) below sea level would have a barometric pressure of \(103.14 \mathrm{kPa}\). To what temperature would you have to heat water to boil it in this city?

Short Answer

Expert verified
(a) By plotting the data in Appendix B and estimating from the graph, the vapor pressure of water at body temperature (\(37^{\circ} \mathrm{C}\)) is approximately \(6.3 \mathrm{kPa}\). (b) The data point at \(101.3 \mathrm{kPa}, 100^{\circ} \mathrm{C}\) represents the standard boiling point of water at sea level, since the external pressure is equal to the standard atmospheric pressure. (c) In a city at an altitude of \(1525 \mathrm{~m}\) above sea level with a barometric pressure of \(84.3 \mathrm{kPa}\), water would boil at approximately \(95^{\circ} \mathrm{C}\) based on the graph. (d) In a city at an altitude of \(150 \mathrm{~m}\) below sea level with a barometric pressure of \(103.14 \mathrm{kPa}\), water would boil at approximately \(101^{\circ} \mathrm{C}\) based on the graph.

Step by step solution

01

(a) Estimate the vapor pressure of water at body temperature

To do this, follow these steps: 1. Plot the data from Appendix B on graph paper or use software to create the graph. On the x-axis, plot the temperature in °C and on the y-axis, plot the vapor pressure in kPa. 2. Use a smooth curve to connect the points and estimate the vapor pressure of water at \(37^{\circ} \mathrm{C}\). The graph should resemble an increasing curve with a relatively smooth shape.
02

(b) Significance of the data point at \(101.3 \mathrm{kPa}, 100^{\circ} \mathrm{C}\)

At this data point, the external pressure is equal to the standard atmospheric pressure (\(101.3 \mathrm{kPa}\)). At this pressure, water boils at \(100^{\circ} \mathrm{C}\). This data point represents the standard boiling point of water at sea level.
03

(c) Boiling temperature of water at \(1525 \mathrm{~m}\) above sea level

To find the boiling temperature of water at this altitude, follow these steps: 1. Use the given barometric pressure, \(84.3 \mathrm{kPa}\), as the external pressure. 2. Locate the external pressure on the y-axis of the previously plotted graph. Find the corresponding temperature on the x-axis. 3. This temperature is the boiling point of water in a city at an altitude of \(1525 \mathrm{~m}\) above sea level.
04

(d) Boiling temperature of water at \(150 \mathrm{~m}\) below sea level

To find the boiling temperature of water at this altitude, follow these steps: 1. Use the given barometric pressure, \(103.14 \mathrm{kPa}\), as the external pressure. 2. Locate the external pressure on the y-axis of the previously plotted graph. Find the corresponding temperature on the x-axis. 3. This temperature is the boiling point of water in a city at an altitude of \(150 \mathrm{~m}\) below sea level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boiling Point
The boiling point of a substance is the temperature at which its vapor pressure equals the external pressure surrounding the liquid. This is the temperature where a liquid changes into vapor, and boiling occurs. Water is a classic example for students learning about the boiling point. At standard atmospheric pressure, water boils at 100°C.
Many factors can affect boiling points. Key among them is atmospheric pressure. For instance, in a city located at sea level, the boiling point of water is typically higher than in a city located at a higher altitude. The vapor pressure reaches the external pressure more swiftly at higher altitudes. This means the boiling occurs at a lower temperature compared to sea level.
Understanding boiling points has practical implications in cooking and chemistry, influencing everything from how quickly food cooks to the efficiency of laboratory and industrial processes.
Standard Atmospheric Pressure
Standard atmospheric pressure is defined as the pressure that supports a column of mercury 760 mm high in a barometer at sea level and at a temperature of 0°C. In more familiar terms, this equates to approximately 101.3 kilopascals (kPa).
This standard pressure is crucial because it serves as a reference point for defining the boiling point of water and other substances. At this stable pressure, water boils at a consistent temperature of 100°C. When the pressure changes, such as in different weather conditions or at different altitudes, the boiling point of water also changes accordingly.
In many scientific and engineering calculations, standard atmospheric pressure is used as a baseline to understand and predict the behavior of gases and liquids. It's important for students to understand this concept, as it links directly to discussions about weather patterns and altitude effects on boiling points.
Altitude and Pressure
Altitude significantly impacts atmospheric pressure. As one ascends to higher altitudes, atmospheric pressure decreases. This is because there are fewer air molecules pushing down from above, which reduces the pressure.
As the atmospheric pressure drops, so does the boiling point of water. For example, in a city at an altitude of 1525 meters above sea level, the atmospheric pressure might drop to 84.3 kPa. Under these conditions, water boils at a lower temperature than the typical 100°C. This concept explains why cooking times and methods differ at various altitudes, particularly in mountainous regions.
Conversely, below sea level, atmospheric pressure increases. Here, the boiling point of water will be higher. In a city 150 meters below sea level, the pressure might be 103.14 kPa, shifting the boiling point upwards. Understanding these adjustments is critical for industries and professions that rely on precise temperature and pressure conditions, such as culinary arts and meteorology.

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Most popular questions from this chapter

The boiling points, surface tensions, and viscosities of water and several alcohols are as shown below: (a) From ethanol to propanol to \(n\) -butanol the boiling points, surface tensions, and viscosities all increase. What is the reason for this increase? (b) How do you explain the fact that propanol and ethylene glycol have similar molecular weights ( 60 versus \(62 \mathrm{u}\) ), yet the viscosity of ethylene glycol is more than 10 times larger than propanol? (c) How do you explain the fact that water has the highest surface tension but the lowest viscosity?

At standard temperature and pressure, the molar volumes of \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) gases are 22.06 and \(22.40 \mathrm{~L}\), respectively. (a) Given the different molecular weights, dipole moments, and molecular shapes, why are their molar volumes nearly the same? (b) On cooling to \(160 \mathrm{~K}\), both substances form crystalline solids. Do you expect the molar volumes to decrease or increase on cooling the gases to \(160 \mathrm{~K} ?\) (c) The densities of crystalline \(\mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) at \(160 \mathrm{~K}\) are 2.02 and \(0.84 \mathrm{~g} / \mathrm{cm}^{3}\), respectively. Calculate their molar volumes. (d) Are the molar volumes in the solid state as similar as they are in the gaseous state? Explain. (e) Would you expect the molar volumes in the liquid state to be closer to those in the solid or gaseous state?

Describe how a cholesteric liquid crystalline phase differs from a smectic A liquid crystalline phase.

Ethyl chloride \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right)\) boils at \(12^{\circ} \mathrm{C}\). When liquid \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\) under pressure is sprayed on a room-temperature \(\left(25^{\circ} \mathrm{C}\right)\) surface in air, the surface is cooled considerably. (a) What does this observation tell us about the specific heat of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(g)\) as compared with that of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(l) ?(\mathbf{b})\) Assume that the heat lost by the surface is gained by ethyl chloride. What enthalpies must you consider if you were to calculate the final temperature of the surface?

Propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) is pressurized into liquid and stored in cylinders to be used as a fuel. The normal boiling point of propane is listed as \(-42^{\circ} \mathrm{C}\). (a) When converting propane into liquid at room temperature of \(25^{\circ} \mathrm{C},\) would you expect the pressure in the tank to be greater or less than atmospheric pressure? How does the pressure within the tank depend on how much liquid propane is in it? (b) Suppose the fuel tank leaks and a few liters of propane escape rapidly. What do you expect would happen to the temperature of the remaining liquid propane in the tank? Explain. (c) How much heat must be added to vaporize \(20 \mathrm{~g}\) of propane if its heat of vaporization is \(18.8 \mathrm{~kJ} / \mathrm{mol} ?\) What volume does this amount of propane occupy at \(100 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C} ?\)

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