Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

At constant pressure, the mean free path \((\lambda)\) of a gas molecule is directly proportional to temperature. At constant temperature, \(\lambda\) is inversely proportional to pressure. If you compare two different gas molecules at the same temperature and pressure, \(\lambda\) is inversely proportional to the square of the diameter of the gas molecules. Put these facts together to create a formula for the mean free path of a gas molecule with a proportionality constant (call it \(R_{\mathrm{mfp}}\), like the ideal-gas constant) and define units for \(R_{\mathrm{mfp}^{-}}\)

Short Answer

Expert verified
The formula for the mean free path (λ) of a gas molecule, taking into account its direct proportionality to temperature (T), inverse proportionality to pressure (P), and inverse proportionality to the square of the diameter of the gas molecules (d), is given by: \[λ = R_{\mathrm{mfp}} \times T \times \frac{1}{P} \times \frac{1}{d^2}\] where the proportionality constant R_mfp has the units of \(L/(K \times Pa)\).

Step by step solution

01

Relation between λ and Temperature

According to the problem, at constant pressure, the mean free path (λ) of a gas molecule is directly proportional to temperature (T). So, we can write this as: \[λ ∝ T\]
02

Relation between λ and Pressure

Next, at constant temperature, the problem states that λ is inversely proportional to pressure (P). So, we can write this as: \[λ ∝ \frac{1}{P}\]
03

Relation between λ and Diameter of Gas Molecules

Finally, if we compare two different gas molecules at the same temperature and pressure, λ is inversely proportional to the square of the diameter of the gas molecules (d). Therefore, we can write this as: \[λ ∝ \frac{1}{d^2}\]
04

Combining the Relations

Now, we will combine the three proportional relationships to form a single formula for λ: \[λ ∝ T \times \frac{1}{P} \times \frac{1}{d^2}\]
05

Introducing the Proportionality Constant

To convert this proportionality relation into an equation, we need to introduce a proportionality constant, called R_mfp, which will have the same functionality as the ideal-gas constant in the ideal gas equation. So the final formula will look like this: \[λ = R_{\mathrm{mfp}} \times T \times \frac{1}{P} \times \frac{1}{d^2}\]
06

Defining the Units for R_mfp

Since the units for λ should be length (L), for temperature (T) it's Kelvin (K), for pressure (P) it's Pascal (Pa), and for the diameter of gas molecules (d) it's also length (L), we need to define the units for R_mfp in such a way that the units in the formula balance out properly. Therefore R_mfp should have units: \[[R_{\mathrm{mfp}}] = \frac{L^3}{K \times Pa \times L^2} = \frac{L}{K \times Pa}\] So, the required formula for the mean free path of a gas molecule is given by: \[λ = R_{\mathrm{mfp}} \times T \times \frac{1}{P} \times \frac{1}{d^2}\] where R_mfp has the units of \(L/(K \times Pa)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Molecules
Gas molecules are tiny particles that make up gases. They move around freely and independently, often colliding with each other and the walls of their container. This movement forms the basis of the kinetic theory of gases. The term "mean free path" refers to the average distance a molecule travels between these collisions.
  • Gas molecules are constantly in motion.
  • Their motion is random and they often interact with one another.
The mean free path is a critical concept because it helps us understand how gas molecules behave under different conditions. This distance depends on a variety of factors, including temperature, pressure, and the size of the molecules themselves.
Temperature
Temperature is a measure of the average kinetic energy of gas molecules. In simpler terms, it indicates how fast the molecules are moving. The higher the temperature, the faster the molecules move, which impacts the mean free path. At constant pressure, as temperature increases, gas molecules move more rapidly and collide less often, leading to a longer mean free path.
  • Higher temperature generally means faster-moving molecules.
  • Temperature is measured in Kelvin (K) in scientific contexts.
Understanding the relationship between temperature and the mean free path is crucial for predicting gas behavior in different thermal conditions.
Pressure
Pressure is the force exerted by gas molecules on the walls of their container. It is caused by the frequent collisions of gas molecules within the container. When the temperature remains constant, an increase in pressure indicates more frequent collisions, resulting in a shorter mean free path.
  • Pressure is commonly measured in Pascals (Pa).
  • More collisions mean a shorter mean free path at constant temperature.
By exploring the inverse relationship between pressure and the mean free path, we can better understand how gases will behave under different pressures and use this knowledge to develop systems and processes involving gases.
Diameter of Molecules
The diameter of gas molecules is a key factor in determining the mean free path. Larger molecules are more likely to collide with each other, which reduces the mean free path. At constant temperature and pressure, the mean free path is inversely proportional to the square of the molecular diameter.
  • Larger diameter results in more frequent collisions.
  • The mean free path decreases with increasing diameter size.
This relationship is crucial for comparing different gases or understanding how a change in molecular size might affect the behavior of a gas.
Proportionality Constant
The proportionality constant, denoted as \(R_{\mathrm{mfp}}\), helps convert the qualitative proportional relationships into a quantitative equation. This constant plays a similar role to the ideal-gas constant in the ideal gas law, providing a precise relation that incorporates temperature, pressure, and molecular diameter to calculate the mean free path. For the mean free path formula, \(R_{\mathrm{mfp}}\) has units of \(L/(K \times Pa)\).
  • Transforms proportionality into an exact mathematical expression.
  • Ensures dimensional consistency and accurate calculations.
By understanding the role of this constant, one can apply it effectively to model gas behavior and predict how changes in environmental conditions will affect gases.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Cyclopropane, a gas used with oxygen as a general anesthetic, is composed of \(85.7 \% \mathrm{C}\) and \(14.3 \% \mathrm{H}\) by mass. \((\mathbf{a})\) If \(1.56 \mathrm{~g}\) of cyclopropane has a volume of \(1.00 \mathrm{~L}\) at 99.7 \(\mathrm{kPa}\) and \(50.0^{\circ} \mathrm{C}\), what is the molecular formula of cyclopropane? (b) Judging from its molecular formula, would you expect cyclopropane to deviate more or less than Ar from ideal-gas behavior at moderately high pressures and room temperature? Explain. (c) Would cyclopropane effuse through a pinhole faster or more slowly than methane, \(\mathrm{CH}_{4} ?\)

Hydrogen has two naturally occurring isotopes, \({ }^{1} \mathrm{H}\) and \({ }^{2} \mathrm{H}\). Chlorine also has two naturally occurring isotopes, \({ }^{35} \mathrm{Cl}\) and \({ }^{37} \mathrm{Cl}\). Thus, hydrogen chloride gas consists of four distinct types of molecules: \({ }^{1} \mathrm{H}^{35} \mathrm{Cl},{ }^{1} \mathrm{H}^{37} \mathrm{Cl},{ }^{2} \mathrm{H}^{35} \mathrm{Cl},\) and \({ }^{2} \mathrm{H}^{37} \mathrm{Cl}\). Place these four molecules in order of increasing rate of effusion.

Torricelli, who invented the barometer, used mercury in its construction because mercury has a very high density, which makes it possible to make a more compact barometer than one based on a less dense fluid. Calculate the density of mercury using the observation that the column of mercury is \(760 \mathrm{~mm}\) high when the atmospheric pressure is \(1.01 \times 10^{5} \mathrm{~Pa}\). Assume the tube containing the mercury is a cylinder with a constant cross-sectional area.

A piece of dry ice (solid carbon dioxide) with a mass of \(20.0 \mathrm{~g}\) is placed in a 25.0-L vessel that already contains air at \(50.66 \mathrm{kPa}\) and \(25^{\circ} \mathrm{C}\). After the carbon dioxide has totally sublimed, what is the partial pressure of the resultant \(\mathrm{CO}_{2}\) gas, and the total pressure in the container at \(25^{\circ} \mathrm{C} ?\)

The molar mass of a volatile substance was determined by the Dumas-bulb method described in Exercise 10.53 . The unknown vapor had a mass of \(2.55 \mathrm{~g} ;\) the volume of the bulb was \(500 \mathrm{~mL}\), pressure \(101.33 \mathrm{kPa}\), and temperature \(37^{\circ} \mathrm{C.Calculate}\) the molar mass of the unknown vapor.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free