Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Classify each of the following as a pure substance or a mixture. If a mixture, indicate whether it is homogeneous of heterogeneous: (a) air, \((\mathbf{b})\) chocolate with almond, \((\mathbf{c})\) alumin- (d) iodine tincture. ium,

Short Answer

Expert verified
- Air is a homogeneous mixture. - Chocolate with almond is a heterogeneous mixture. - Aluminum is a pure substance. - Iodine tincture is a homogeneous mixture.

Step by step solution

01

(a) Classifying air as a pure substance or a mixture

Air consists of different gases such as nitrogen, oxygen, carbon dioxide, and others present in variable proportions. Because it contains multiple components, air is a mixture. To determine if it is a homogeneous or heterogeneous mixture, we must consider how uniformly the gases are distributed. Since the gases in the air mix uniformly, air is a homogeneous mixture.
02

(b) Classifying chocolate with almond as a pure substance or a mixture

Chocolate with almonds consists of at least two different substances: chocolate and almonds. Thus, it is a mixture. To determine if it is a homogeneous or heterogeneous mixture, we must analyze the distribution of the components. In the case of chocolate with almonds, the distribution of almonds in the chocolate is not uniform; we can see regions with just chocolate and regions with almonds. Thus, chocolate with almond is a heterogeneous mixture.
03

(c) Classifying aluminum as a pure substance or a mixture

Aluminum is an element that appears on the periodic table. It is composed of only aluminum atoms, and there are no other substances mixed with it. Therefore, aluminum is a pure substance.
04

(d) Classifying iodine tincture as a pure substance or a mixture

Iodine tincture is a solution that consists of iodine dissolved in alcohol or another solvent. Because it has both iodine and a solvent such as alcohol, it is a mixture. Seeing as the iodine is uniformly dissolved in the solvent, it is a homogeneous mixture. In summary: - Air is a homogeneous mixture. - Chocolate with almond is a heterogeneous mixture. - Aluminum is a pure substance. - Iodine tincture is a homogeneous mixture.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pure Substances
Pure substances are materials composed of one type of particle. They have consistent properties throughout. Examples include elements and compounds.

Elements consist of a single type of atom, like aluminum or gold. Compounds are made from two or more elements that are chemically bonded, such as water or carbon dioxide.

These substances have fixed melting and boiling points. For instance, pure aluminum is just aluminum atoms with no impurities.
  • Elements: single type of atom, found on the periodic table.
  • Compounds: chemically bonded elements, represented by chemical formulas.
Understanding pure substances helps identify materials with uniform characteristics.
Mixtures
Mixtures involve two or more substances combined physically, not chemically. This means the components retain their original properties and can be separated by physical processes.

Mixtures don’t have a fixed composition. They can differ in proportions and can be either homogeneous or heterogeneous. Some common examples include air, chocolate with almonds, and iodine tincture.
  • Physically combined: can be separated by processes like filtration or distillation.
  • Variable composition: differing amounts of each component.
Knowing how to classify mixtures is crucial to understanding material composition.
Homogeneous Mixtures
Homogeneous mixtures are uniform in composition. This means the different components are evenly distributed throughout the mixture.

These mixtures are often referred to as solutions. For instance, air is a homogeneous mixture since the gases are mixed uniformly. Another example is iodine tincture, where iodine is evenly dissolved in alcohol.
  • Uniform composition: can't see different components.
  • Examples include vinegar, saltwater, and alloys.
Recognizing homogeneous mixtures helps in distinguishing them from heterogeneous ones.
Heterogeneous Mixtures
Heterogeneous mixtures have visibly different components or phases. These mixtures do not have uniform distribution, leading to distinct regions of different substances.

Chocolate with almonds is a classic example. You can easily see and separate the chocolate from the almonds due to the uneven distribution.
  • Non-uniform composition: can see different parts.
  • Examples include salad, cereal with milk, and granite.
Understanding heterogeneous mixtures is key to identifying materials that aren't uniformly mixed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A thief plans to steal a cylindrical platinum medal with a radius of \(2.3 \mathrm{~cm}\) and a thickness of \(0.8 \mathrm{~cm}\) from a jewellery store. If the platinum has a density of \(21.45 \mathrm{~g} / \mathrm{cm}^{3},\) what is the mass of the medal in \(\mathrm{kg} ?\) [The volume of a cylinder is \(\left.V=\pi r^{2} h .\right]\)

(a) To identify a liquid substance, a student determined its density, Using a graduated cylinder, she measured out a \(45-\mathrm{mL}\). sample of the substance. She then measured the mass of the sample, finding that it weighed \(38.5 \mathrm{~g}\). She knew that the substance had to be either isopropyl alcohol (density \(0.785 \mathrm{~g} / \mathrm{mL}\) ) or toluene (density \(0.866 \mathrm{~g} / \mathrm{mL}\) ). What are the calculated density and the probable identity of the substance? (b) An experiment requires \(45.0 \mathrm{~g}\) of ethylene glycol, a liquid whose density is \(1.114 \mathrm{~g} / \mathrm{mL}\). Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume of the liquid should he use? (c) Is a graduated cylinder such as that shown in Figure 1.21 likely to afford the (d) A cubic piece of metal accuracy of measurement needed? measures \(5.00 \mathrm{~cm}\) on each edge. If the metal is nickel, whose density is \(8.90 \mathrm{~g} / \mathrm{cm}^{3}\), what is the mass of the cube?

Water has a density of \(0.997 \mathrm{~g} / \mathrm{cm}^{3}\) at \(25^{\circ} \mathrm{C}\); ice has a density of \(0.917 \mathrm{~g} / \mathrm{cm}^{3}\) at \(-10^{\circ} \mathrm{C}\). (a) If a soft-drink bottle whose volume is \(1.50 \mathrm{~L}\) is completely filled with water and then frozen to \(-10^{\circ} \mathrm{C},\) what volume does the ice occupy? (b) Can the ice be contained within the bottle?

Suppose you decide to define your own temperature scale with units of \(\mathrm{O}\), using the freezing point \(\left(13^{\circ} \mathrm{C}\right)\) and boiling point \(\left(360^{\circ} \mathrm{C}\right)\) of oleic acid, the main component of olive oil. If you set the freezing point of oleic acid as \(0^{\circ} \mathrm{O}\) and the boiling point as \(100^{\circ} \mathrm{O},\) what is the freezing point of water on this new scale?

Using your knowledge of metric units, English units, and the information on the back inside cover, write down the conversion factors needed to convert (a) in. to \(\mathrm{cm}(\mathbf{b}) \mathrm{lb}\) to \(\mathrm{g}\) (c) \(\mu g\) to \(g\) (d) \(\mathrm{ft}^{2}\) to \(\mathrm{cm}^{2}\).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free