Chapter 4: Problem 64
A person suffering from hyponatremia has a sodium ion concentration in the blood of \(0.118 \mathrm{M}\) and a total blood volume of \(4.6 \mathrm{~L} .\) What mass of sodium chloride would need to be added to the blood to bring the sodium ion concentration up to \(0.138 M\), assuming no change in blood volume?
Short Answer
Step by step solution
Calculate initial moles of sodium ions
Calculate needed moles of sodium ions for desired concentration
Calculate additional moles of sodium ions needed
Convert moles of sodium ions to moles of sodium chloride
Calculate mass of sodium chloride needed
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sodium Ions
In the original exercise, the initial sodium ion concentration in a patient's blood was \(0.118 \, \text{M}\). This unit, "M," stands for molarity, which is the number of moles of a solute per liter of solution. Maintaining appropriate sodium ion levels is vital for health, and in our problem, an adjustment was needed to reach \(0.138 \, \text{M}\). By understanding the role of sodium ions, we see why precise calculations are critical when adjusting them in blood chemistry.
Sodium Chloride
In our exercise, sodium chloride is used to adjust the sodium ion concentration in the blood. To find out how much sodium chloride is needed, we assumed complete dissociation in the aqueous blood medium. After calculating the extra sodium ions needed to reach a desired blood concentration, it was determined that \(0.092 \,\text{mol}\) of sodium ions was required. Therefore, \(0.092 \,\text{mol}\) of sodium chloride was also needed due to the 1:1 dissociation ratio.
This makes sodium chloride an effective, simple means of adjusting sodium ion levels in the body due to its consistent dissociation behavior in fluids like blood.
Molar Concentration
The exercise utilized this concept by calculating the molar concentration of sodium ions in blood, where initially it was \(0.118 \, \text{M}\). To correct the hyponatremia condition, a new target concentration of \(0.138 \, \text{M}\) was necessary. By employing the equation \(\text{moles} = \text{concentration} \times \text{volume}\), the change in moles required was determined so the right amount of sodium chloride could be added. This exemplified how molar concentration calculations are crucial for solving practical problems in health and chemistry.
- It allows precise measurements of substances in a solution.
- Provides a method to adjust concentrations in medical scenarios.
- Facilitates clear understanding of chemical reactions in solutions.