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You know that an unlabeled bottle contains an aqueous solution of one of the following: \(\mathrm{AgNO}_{3}, \mathrm{CaCl}_{2}\), or \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\). A friend suggests that you test a portion of the solution with \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) and then with \(\mathrm{NaCl}\) solutions. According to your friend's logic, which of these chemical reactions could occur, thus helping you identify the solution in the bottle? (a) Barium sulfate could precipitate. (b) Silver chloride could precipitate. (c) Silver sulfate could precipitate. (d) More than one, but not all, of the reactions described in answers a-c could occur. (e) All three reactions described in answers a-c could occur.

Short Answer

Expert verified
(d) More than one, but not all, of the reactions described could occur.

Step by step solution

01

Analyze Possible Reactions with Ba(NO₃)₂

When you add \( \mathrm{Ba(NO}_3)_2 \) to the unknown solution, potential precipitates could form if the anion in the solution reacts with \( \mathrm{Ba}^{2+} \) to form an insoluble compound. From the given options, \( \mathrm{BaSO}_4 \) forms a precipitate because \( \mathrm{BaSO}_4 \) is insoluble in water. Therefore, if the solution contains \( \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \), \( \mathrm{BaSO}_4 \) will form.
02

Analyze Possible Reactions with NaCl

Adding \( \mathrm{NaCl} \) to the unknown solution could produce a precipitate if \( \mathrm{AgNO}_3 \) is present, as \( \mathrm{AgCl} \) is insoluble in water. Therefore, if the solution contains \( \mathrm{AgNO}_3 \), \( \mathrm{AgCl} \) will form when \( \mathrm{NaCl} \) is added.
03

Evaluate Precipitate Formation

\( \mathrm{BaSO}_4 \) precipitate would indicate the presence of \( \mathrm{Al}_2(\mathrm{SO}_4)_3 \), while \( \mathrm{AgCl} \) precipitate would indicate the presence of \( \mathrm{AgNO}_3 \). There is no scenario where \( \mathrm{CaCl}_2 \) would produce either \( \mathrm{AgCl} \) or \( \mathrm{BaSO}_4 \) as these are both products of reactions from other specific solutions.
04

Confirm the Correct Answer

Based on the analysis, either \( \mathrm{BaSO}_4 \) or \( \mathrm{AgCl} \) could precipitate depending on whether \( \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3 \) or \( \mathrm{AgNO}_3 \) is in the solution, respectively. Since both precipitates can form independently from different solutions, the correct choice is (d) More than one, but not all, of the reactions described could occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aqueous Solutions
An aqueous solution is a mixture where water acts as the solvent. In chemistry, solutions are essential because they allow substances to react more easily. This occurs because the solute, or the substance being dissolved, is uniformly dispersed within the solvent, making it available for reaction. One key characteristic of aqueous solutions is that they can be either an electrolyte or a nonelectrolyte. Electrolytes dissociate into ions, which allows them to conduct electricity. Common examples include salts like sodium chloride and acids like hydrochloric acid. Nonelectrolytes, on the other hand, do not dissociate into ions and therefore do not conduct electricity. Aqueous solutions are crucial in precipitation reactions, where soluble ions in separate solutions interact to form an insoluble solid. Understanding the properties of an aqueous solution can help predict the outcomes of various chemical reactions.
Precipitation Reactions
Precipitation reactions occur when two soluble salts react in aqueous solution to form one or more insoluble products, known as precipitates. These reactions are a subdivision of double displacement reactions and are governed by the solubility rules of the resultant compounds. When a precipitate forms, it appears as a solid settling out of the liquid solution. This is significant because it can be used to identify the ions present in a solution. For example, in a lab experiment, mixing a solution containing barium nitrate with one containing sulfate ions often results in the formation of barium sulfate. Barium sulfate appears as a white solid and is evidence of a precipitation reaction. Such reactions can also be utilized in various applications, such as removing unwanted ions from water or serving analytical purposes in chemistry labs for detecting specific elements or compounds.
Solubility Rules
Solubility rules are guidelines that help predict whether an ionic compound will dissolve in water, forming an aqueous solution, or remain as a precipitate. These rules are essential for identifying the likelihood of precipitate formation during a chemical reaction. While there are many specific solubility rules, a few critical ones include:
  • Most alkali metal salts and ammonium salts are soluble.
  • Nitrates (NO₃⁻), acetates (CH₃COO⁻), and most perchlorates (ClO₄⁻) are soluble.
  • Chlorides, bromides, and iodides are soluble, except when paired with Ag⁺, Pb²⁺, and Hg²⁺.
  • Sulfates (SO₄²⁻) are generally soluble, but exceptions include Ba²⁺, Sr²⁺, and Pb²⁺.
  • Most carbonates (CO₃²⁻), phosphates (PO₄³⁻), sulfides (S²⁻), and hydroxides (OH⁻) are insoluble, except when paired with alkali metals or NH₄⁺.
By utilizing these rules, chemists can anticipate which solutions, when mixed, will result in the formation of a precipitate, aiding in both practical applications and theoretical understanding of chemical behaviors.

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Most popular questions from this chapter

Complete and balance the following molecular equations, and then write the net ionic equation for each: (a) \(\mathrm{HBr}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \longrightarrow\) (b) \(\mathrm{Cu}(\mathrm{OH})_{2}(s)+\mathrm{HClO}_{4}(a q) \longrightarrow\) (c) \(\mathrm{Al}(\mathrm{OH})_{3}(s)+\mathrm{HNO}_{3}(a q) \longrightarrow\)

Calculate the concentration of each ion in the following solutions obtained by mixing: (a) \(32.0 \mathrm{~mL}\) of \(0.30 \mathrm{M} \mathrm{KMnO}_{4}\) with \(15.0 \mathrm{~mL}\) of \(0.60 \mathrm{M} \mathrm{KMnO}_{4}\) (b) \(60.0 \mathrm{~mL}\) of \(0.100 \mathrm{M} \mathrm{ZnCl}_{2}\) with \(5.0 \mathrm{~mL}\) of \(0.200 \mathrm{MZn}\left(\mathrm{NO}_{3}\right)_{2},(\mathbf{c}) 4.2 \mathrm{~g}\) of \(\mathrm{CaCl}_{2}\) in \(150.0 \mathrm{~mL}\) of \(0.02 M \mathrm{KCl}\) solution. Assume that the volumes are additive.

You want to analyze a silver nitrate solution. (a) You could add \(\mathrm{HCl}(a q)\) to the solution to precipitate out \(\mathrm{AgCl}(s) .\) What volume of a \(0.150 \mathrm{M} \mathrm{HCl}(a q)\) solution is needed to precipitate the silver ions from \(15.0 \mathrm{~mL}\) of a \(0.200 \mathrm{M} \mathrm{AgNO}_{3}\) solution? (b) You could add solid \(\mathrm{KCl}\) to the solution to precipitate out AgCl(s). What mass of KCl is needed to precipitate the silver ions from \(15.0 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{AgNO}_{3}\) solution? (c) Given that a \(0.150 \mathrm{M} \mathrm{HCl}(a q)\) solution costs \(\$ 39.95\) for \(500 \mathrm{~mL}\) and that KCl costs \(\$ 10 /\) ton, which analysis procedure is more cost-effective?

True or false: (a) If a substance is oxidized, there must be more oxygen in the substance. (b) If a substance is oxidized, it must lose at least one electron and form an anion.

Some sulfuric acid is spilled on a lab bench. You can neutralize the acid by sprinkling sodium bicarbonate on it and then mopping up the resulting solution. The sodium bicarbonate reacts with sulfuric acid according to: $$ \begin{aligned} 2 \mathrm{NaHCO}_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+& \\ 2 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{CO}_{2}(g) \end{aligned} $$ Sodium bicarbonate is added until the fizzing due to the formation of \(\mathrm{CO}_{2}(g)\) stops. If \(27 \mathrm{~mL}\) of \(6.0 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}\) was spilled, what is the minimum mass of \(\mathrm{NaHCO}_{3}\), that must be added to the spill to neutralize the acid?

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