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How many of the indicated atoms are represented by each chemical formula: (a) carbon atoms in \(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3}\), (b) oxygen atoms in \(\mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2},(\mathbf{c})\) hydrogen atoms in \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4} ?\)

Short Answer

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(a) 5 carbon atoms; (b) 6 oxygen atoms; (c) 9 hydrogen atoms.

Step by step solution

01

Analyzing the Formula for Carbon Atoms

Identify the number of carbon atoms in the compound \( \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3} \). The formula shows \( \mathrm{C}_{4} \) indicating 4 carbon atoms from the first section of the formula, and the "COOCH\(_3\)" segment adds 1 more carbon. Therefore, the total number of carbon atoms is \( 4 + 1 = 5 \).
02

Determining Oxygen Atoms in the Compound

Examine \( \mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2} \). The group \( \mathrm{ClO}_{3} \) contains 3 oxygen atoms. Since this group is inside the parentheses followed by a \(2\), multiply the oxygen count by 2: \( 3 \times 2 = 6 \) oxygen atoms are present.
03

Calculating Hydrogen Atoms

Look at \( \left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4} \). Each \( \mathrm{NH}_{4} \) contains 4 hydrogen atoms, and the parentheses indicate there are 2 such groups, giving \( 4 \times 2 = 8 \) hydrogen atoms. Additionally, there is 1 more hydrogen atom from \( \mathrm{HPO}_{4} \), leading to a total of \( 8 + 1 = 9 \) hydrogen atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbon Atoms
Carbon atoms are fundamental to the structure of organic compounds. They are tetravalent, which means that each carbon atom can form four covalent bonds with other atoms. This makes carbon one of the most versatile elements, capable of forming long chains and complex rings. In the chemical formula \( \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{COOCH}_{3} \), the indicated carbon atoms are found in two parts: the \( \mathrm{C}_{4} \) section and the "COOCH\(_3\)" part. The \( \mathrm{C}_{4} \) part directly tells us there are 4 carbon atoms. The additional carbon comes from the "COOCH\(_3\)" group, which contains 1 more carbon atom. Thus, we have a total of 5 carbon atoms in this molecule. Understanding the placement and count of carbon atoms helps in determining the molecular structure of a compound, influencing properties like volatility, solubility, and reactivity.
  • \( \mathrm{C}_{4} \): 4 carbon atoms
  • "COOCH\(_3\)": 1 additional carbon atom
  • Total carbon atoms: 5
Oxygen Atoms
Oxygen atoms, with their ability to form two covalent bonds, are abundant in many compounds, especially those that are involved in biological and chemical processes. In the compound \( \mathrm{Ca}\left(\mathrm{ClO}_{3}\right)_{2} \), oxygen atoms are part of the \( \mathrm{ClO}_{3} \) group. Each \( \mathrm{ClO}_{3} \) contains 3 oxygen atoms. Since the formula indicates \( \left(\mathrm{ClO}_{3}\right)_{2} \), you multiply the number of oxygen atoms by 2, giving you \( 3 \times 2 = 6 \) oxygen atoms in total.
Understanding how to count oxygen atoms in chemical formulas is crucial in determining the oxygen content, and thereby the potential reactivity and interaction with other substances.
  • Each \( \mathrm{ClO}_{3} \): 3 oxygen atoms
  • Total groups: 2
  • Total oxygen atoms: 6
Hydrogen Atoms
Hydrogen atoms are the simplest and most abundant chemical elements. Their presence in a molecule influences factors like acidity and basicity, as well as molecular shape and stability. In the formula \( \left(\mathrm{NH}_{4}\right)_{2} \mathrm{HPO}_{4} \), hydrogen atoms can be found in two places. The \( \mathrm{NH}_{4} \) part, known as the ammonium ion, provides 4 hydrogen atoms per group. Since there are 2 ammonium groups (as shown by the parentheses and the subscript \(2\)), this contributes \( 4 \times 2 = 8 \) hydrogen atoms. The \( \mathrm{HPO}_{4} \) component adds 1 more hydrogen atom, for a total of 9 hydrogen atoms. Counting hydrogen atoms is important for predicting chemical behavior, such as reaction pathways and energy content.
  • \( \mathrm{NH}_{4} \) groups: 4 hydrogen atoms each
  • Total \( \mathrm{NH}_{4} \) groups: 2
  • Additional hydrogen from \( \mathrm{HPO}_{4} \): 1
  • Total hydrogen atoms: 9

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Most popular questions from this chapter

What fraction of the \(\alpha\) particles in Rutherford's gold foil experiment are scattered at large angles? Assume the gold foil is two layers thick, as shown in Figure \(2.9,\) and that the approximate diameters of a gold atom and its nucleus are 270 \(\mathrm{pm}\) and \(1.0 \times 10^{-2} \mathrm{pm}\), respectively. Hint: Calculate the cross sectional area occupied by the nucleus as a fraction of that occupied by the atom. Assume that the gold nuclei in each layer are offset from each other.

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