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How many microliters of \(1.000 \mathrm{M} \mathrm{NaOH}\) solution must be added to \(25.00 \mathrm{~mL}\) of a \(0.1000 \mathrm{M}\) solution of lactic acid \(\left[\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\right.\) or \(\left.\mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{3}\right]\) to produce a buffer with \(\mathrm{pH}=3.75 ?\)

Short Answer

Expert verified
You need around 1930 microliters of 1.000 M NaOH solution.

Step by step solution

01

Understanding the Problem

We need to calculate the amount of \( \text{NaOH} \) solution required to produce a buffer with a specified pH. A buffer is created when \( \text{NaOH} \) neutralizes some of the \( \text{lactic acid} \), forming its conjugate base. The Henderson-Hasselbalch equation will be used: \[ \text{pH} = \text{pK}_a + \log \left( \frac{[A^-]}{[HA]} \right) \]. Here, \([A^-]\) is the concentration of the conjugate base (lactate ion), and \([HA]\) is the concentration of lactic acid.
02

Finding pKa of Lactic Acid

The \( \text{pK}_a \) of lactic acid \([(\mathrm{HC}_3\mathrm{H}_5\mathrm{O}_3)]\) is given as 3.86. This value is crucial as it will allow us to use the Henderson-Hasselbalch equation.
03

Formulating the Henderson-Hasselbalch Equation

With the desired \( \text{pH} = 3.75 \) and \( \text{pK}_a = 3.86 \), the buffer equation becomes:\[ 3.75 = 3.86 + \log \left( \frac{[A^-]}{[HA]} \right) \].Solving, we find:\[ \log \left( \frac{[A^-]}{[HA]} \right) = 3.75 - 3.86 = -0.11 \].Convert this logarithmic ratio to its linear form:\[ \frac{[A^-]}{[HA]} = 10^{-0.11} \approx 0.776 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation is an invaluable tool in chemistry, especially when discussing buffer solutions. Buffers resist changes in pH when small amounts of acid or base are added.

The equation is expressed as: \[\text{pH} = \text{pK}_a + \log \left( \frac{[A^-]}{[HA]} \right)\] Here, \([A^-]\) stands for the concentration of the conjugate base and \([HA]\) for the acid. This formula helps chemists determine the pH of a buffer solution by comparing the concentrations of the acid and its conjugate base.

This equation assumes that the concentrations of the acid and conjugate base in the solution are similar and is most accurate when applied to weak acids and bases. It highlights the direct relationship between the pH of a buffer and the ratio of conjugate base to acid. When this ratio is equal to 1, the pH is equal to the pKₐ, indicating that there are equal concentrations of acid and conjugate base.
Lactic Acid
Lactic acid is a simple carboxylic acid represented by the chemical formula \(\mathrm{CH}_3\mathrm{CH}(\mathrm{OH})\mathrm{COOH}\). It is known for being a part of the fermentation process and can be found in sour milk products.

In the context of buffer solutions, lactic acid serves as the weak acid component. When dissociated in solution, it forms its conjugate base, the lactate ion \(\mathrm{C}_3\mathrm{H}_5\mathrm{O}_3^-\). This dissociation is a key component of how buffers work, as it allows for equilibrium adjustments when strong acids or bases are introduced to the system.

Lactic acid has a \(\text{pK}_a\) of 3.86, which is important when determining the pH range over which it can effectively act as part of a buffer system. Its presence contributes to the stability of the pH, making it an essential part of biochemical processes and industries where pH maintenance is crucial.
pH Calculation
pH calculation is a fundamental concept in chemistry that involves determining the acidity or basicity of an aqueous solution. The pH scale ranges from 0 to 14, where lower values indicate more acidic solutions and higher values signify more basic ones.

A pH of 7 is considered neutral, typically represented by pure water. In a buffered solution, such as one using lactic acid, knowing how to calculate the pH is essential. This is accomplished through the use of the Henderson-Hasselbalch equation by inputting known values of pKₐ and concentrations of the acid and its conjugate base.

For the buffer to be effective, it generally functions best when the pH is close to the pKₐ value of the acid being used. This proximity ensures that the components of the buffer can neutralize added acids or bases without significant fluctuations in pH, thus providing a stable environment in chemical processes.

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Most popular questions from this chapter

In nonaqueous solvents, it is possible to react HF to create \(\mathrm{H}_{2} \mathrm{~F}^{+} .\) Which of these statements follows from this observation? (a) HF can act like a strong acid in nonaqueous solvents, (b) HF can act like a base in nonaqueous solvents, (c) HF is thermodynamically unstable, \((\mathbf{d})\) There is an acid in the nonaqueous medium that is a stronger acid than HE.

The solubility product for \(\mathrm{Zn}(\mathrm{OH})_{2}\) is \(3.0 \times 10^{-16}\). The formation constant for the hydroxo complex, \(\mathrm{Zn}(\mathrm{OH})_{4}{ }^{2-},\) is \(4.6 \times 10^{17}\). What concentration of \(\mathrm{OH}^{-}\) is required to dissolve 0.015 mol of \(\mathrm{Zn}(\mathrm{OH})_{2}\) in a liter of solution?

Furoic acid \(\left(\mathrm{HC}_{5} \mathrm{H}_{3} \mathrm{O}_{3}\right)\) has a \(K_{a}\) value of \(6.76 \times 10^{-4} \mathrm{at}\) \(25^{\circ} \mathrm{C}\). Calculate the \(\mathrm{pH}\) at \(25^{\circ} \mathrm{C}\) of \((\mathbf{a})\) a solution formed by adding \(30.0 \mathrm{~g}\) of furoic acid and \(25.0 \mathrm{~g}\) of sodium furoate \(\left(\mathrm{NaC}_{5} \mathrm{H}_{3} \mathrm{O}_{3}\right)\) to enough water to form \(0.300 \mathrm{~L}\) of solution, \((\mathbf{b})\) a solution formed by mixing \(20.0 \mathrm{~mL}\). of \(0.200 \mathrm{M}\) \(\mathrm{HC}_{\mathrm{s}} \mathrm{H}_{3} \mathrm{O}_{3}\) and \(30.0 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{NaC}_{5} \mathrm{H}_{3} \mathrm{O}_{3}\) and diluting the total volume to \(125 \mathrm{~mL},(\mathbf{c})\) a solution prepared by adding \(25.0 \mathrm{~mL}\) of \(1.00 \mathrm{M} \mathrm{NaOH}\) solution to \(100.0 \mathrm{~mL}\) of \(0.100 \mathrm{MHC}_{3} \mathrm{H}_{3} \mathrm{O}_{3}\)

(a) True or false: "solubility" and "solubility-product constant" are the same number for a given compound. (b) Write the expression for the solubility- product constant for each of the following ionic compounds: \(\mathrm{MnCO}_{3}, \mathrm{Hg}(\mathrm{OH})_{2},\) and \(\mathrm{Cu}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

How many milliliters of \(0.0750 \mathrm{M} \mathrm{KOH}\) are required to titrate each of the following solutions to the equivalence point: (a) \(30.0 \mathrm{~mL}\) of \(0.0900 \mathrm{M} \mathrm{HCOOH}\), (b) \(45.0 \mathrm{~mL}\) of \(0.0750 \mathrm{M} \mathrm{HNO}_{3},(\mathbf{c}) 50.0 \mathrm{~mL}\) of a solution that contains \(3.00 \mathrm{~g}\) of HBr per liter?

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