Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Rubbing alcohol is the common name for 2 -propanol (isopropanol), \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\). (a) Draw the three-dimensional structure of the 2 -propanol molecule and predict the geometry around each carbon atom. (b) Is the 2-propanol molecule polar or nonpolar? (c) What kinds of intermolecular attractive forces exist between the 2 -propanol molecules? (d) The isomer 1 -propanol has the same molecular weight as 2 -propanol, yet 2 -propanol boils at \(82.6^{\circ} \mathrm{C}\) and 1 -propanol boils at \(97.2{ }^{\circ} \mathrm{C}\). Explain the difference.

Short Answer

Expert verified
2-propanol is polar due to the OH group, exhibits hydrogen bonding, and boils lower than 1-propanol due to less extensive intermolecular forces.

Step by step solution

01

Draw the Three-Dimensional Structure

The molecule 2-propanol, or isopropanol, comprises three carbon atoms arranged in a chain. In a three-dimensional representation, C1 and C2 will have a tetrahedral shape since each is bonded to four atoms. The carbon atom at the center (C2) will also have a hydrogen and a hydroxyl group (OH) attached, representing its bond angles deviating slightly due to the larger electron cloud of the OH group.
02

Determine Molecular Geometry

Each carbon atom in 2-propanol is part of a tetrahedral geometry. The carbons are sp3 hybridized: the central carbon (C2) is connected to three hydrogen atoms and one hydroxyl group, while the terminal carbon atoms (C1 and C3) are each bonded to three hydrogen atoms and one other carbon atom.
03

Assess Molecular Polarity

2-propanol is a polar molecule primarily due to the presence of the hydroxyl group. The OH group has a significant dipole moment, making the overall molecular geometry polar despite the nonpolar C-C and C-H bonds. This dipole arises from the difference in electronegativity between oxygen and hydrogen.
04

Identify Intermolecular Forces

In 2-propanol, intermolecular forces include hydrogen bonding due to the OH group, as well as dipole-dipole interactions and London dispersion forces present in all molecules. Hydrogen bonds are the strongest interactions here, accounting for the molecule's relatively high boiling point.
05

Compare Boiling Points of Isomers

1-propanol also has hydrogen bonding capabilities like 2-propanol; however, 1-propanol can form a linear chain, which facilitates more extensive intermolecular hydrogen bonding. This linear arrangement allows for stronger intermolecular interactions in the liquid phase, explaining why 1-propanol has a higher boiling point than 2-propanol.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Geometry
2-propanol, also known as isopropanol, has a molecular formula of \( \text{C}_3\text{H}_7\text{OH} \). Its molecular geometry can be visualized by considering the arrangement of the atoms. The molecule consists of a chain of three carbon atoms. Each carbon exhibits a tetrahedral geometry, typical for sp3 hybridized carbon atoms. This means each carbon atom forms bonds with four other atoms.

In 2-propanol, the central carbon atom (C2) is bonded to one hydroxyl (OH) group, two hydrogen atoms, and one carbon atom, maintaining a tetrahedral shape. The terminal carbon atoms (C1 and C3) are each bonded to three hydrogen atoms and the central carbon atom. This gives the molecule its characteristic branched structure, which is important for its other properties.
Molecular Polarity
2-propanol is a polar molecule. The reason for its polarity primarily hinges on the presence of the hydroxyl group (OH). The oxygen in this group is more electronegative than the hydrogen, which creates a significant dipole moment across the molecule.

While the carbon-carbon and carbon-hydrogen bonds are nonpolar due to similar or equal electronegativity, the OH group disrupts this balance. The uneven distribution of electron density in the molecule leads to 2-propanol's overall polar nature. This polarity influences how 2-propanol interacts with other substances and its solubility in different solvents.
Intermolecular Forces
The intermolecular forces present in 2-propanol are a key factor in determining its properties, such as its boiling point. The primary force is hydrogen bonding, due to the OH group's strong attraction to other polar molecules, particularly involving hydrogen and oxygen.

In addition to hydrogen bonds, 2-propanol also exhibits dipole-dipole interactions, stemming from its polar nature. Furthermore, like all molecules, 2-propanol is subject to London dispersion forces. These are weak forces resulting from temporary dipoles that occur due to electron motion within molecules. Together, these forces play a crucial role in the molecule's physical characteristics and behavior.
Boiling Point Comparison
When comparing the boiling points of 2-propanol and its isomer 1-propanol, intermolecular interactions are key. Although both can form hydrogen bonds, the arrangement of atoms in the two molecules affects their boiling points.

1-propanol possesses a linear arrangement, which allows it to form more extensive hydrogen bonds compared to the branched structure of 2-propanol. These stronger intermolecular interactions in 1-propanol require more energy to break, resulting in a higher boiling point of 97.2°C, as opposed to 2-propanol's boiling point of 82.6°C. This difference underscores the impact molecular structure has on boiling point and physical properties.
Isomerism in Alcohols
Isomerism is a fascinating concept where compounds with the same molecular formula have different structures. In the case of alcohols, isomerism can lead to differences in physical and chemical properties. For 2-propanol and 1-propanol, they are structural isomers of each other.

Structural isomerism in alcohols arises from the different connectivity of the oxygen and carbon atoms within the molecule. This results in variations in molecular structure, such as branching, which in turn influences properties like boiling point, solubility, and reactivity. Understanding isomerism helps in recognizing how small changes in structure can massively alter a compound's behavior and uses.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Which type of intermolecular attractive force operates between all molecules? (b) Which type of intermolecular attractive force operates only between polar molecules? (c) Which type of intermolecular attractive force operates only between the hydrogen atom of a polar bond and a nearby small electronegative atom?

Benzoic acid, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH},\) melts at \(122{ }^{\circ} \mathrm{C} .\) The density in the liquid state at \(130^{\circ} \mathrm{C}\) is \(1.08 \mathrm{~g} / \mathrm{cm}^{3}\). The density of solid benzoic acid at \(15^{\circ} \mathrm{C}\) is \(1.266 \mathrm{~g} / \mathrm{cm}^{3} .\) (a) In which of these two states is the average distance between molecules greater? (b) If you converted a cubic centimeter of liquid benzoic acid into a solid, would the solid take up more, or less, volume than the original cubic centimeter of liquid?

Butane and 2 -methylpropane, whose space-filling models are shown here, are both nonpolar and have the same molecular formula, \(\mathrm{C}_{4} \mathrm{H}_{10}\), yet butane has the higher boiling point \(\left(-0.5^{\circ} \mathrm{C}\right.\) compared to \(\left.-11.7{ }^{\circ} \mathrm{C}\right)\). Explain.

Hydrazine \(\left(\mathrm{H}_{2} \mathrm{NNH}_{2}\right),\) hydrogen peroxide \((\mathrm{HOOH}),\) and water \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) all have exceptionally high surface tensions compared with other substances of comparable molecular weights. (a) Draw the Lewis structures for these three compounds. (b) What structural property do these substances have in common, and how might that account for the high surface tensions?

(a) What phase change is represented by the "heat of vaporization" of a substance? (b) Is the process of vaporization endothermic or exothermic? (c) If you compare a substance's heat of vaporization to the amount of heat released during condensation, which one is generally larger (consider the numerical value only)?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free