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(a) When you exercise vigorously, you sweat. How does this help your body cool? (b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

Short Answer

Expert verified
Sweating cools the body through evaporative cooling. In a vacuum, reduced pressure lowers the boiling point, causing water to boil and eventually freeze due to energy loss during evaporation.

Step by step solution

01

Understanding Sweat and Cooling

When you exercise vigorously, your body generates heat. Sweating helps cool the body because when sweat evaporates from the skin, it absorbs heat energy from the body. This process, known as evaporative cooling, helps maintain a stable body temperature by removing heat from the body surface.
02

Boiling Point and Pressure Relationship

In the flask connected to a vacuum pump, reducing pressure causes the boiling point of the water to decrease. When the boiling point drops below the water's temperature, it begins to boil at room temperature due to reduced pressure. This is because boiling occurs when the vapor pressure of the liquid equals the surrounding pressure, which is lowered by the vacuum.
03

Freezing during Evaporation

As the water in the flask boils, it undergoes a phase change from liquid to gas. This phase change requires energy, which is absorbed from the remaining liquid water, causing its temperature to drop. If the temperature falls below the water's freezing point, the water can freeze despite the presence of a vacuum, as energy loss due to continuous evaporation outweighs heat generation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boiling Point and Pressure
The boiling point of a liquid is the temperature at which it changes from a liquid to a gas. Normally, this occurs when the vapor pressure inside the liquid equals the surrounding atmospheric pressure. However, when the pressure around a liquid decreases, such as in a vacuum, the boiling point also decreases. This means that the liquid can begin to boil at a much lower temperature than it would under normal atmospheric conditions.

In the context of a vacuum pump and a flask of water, the reduced pressure leads to an interesting phenomenon: water can boil at room temperature. Under these conditions, the surrounding pressure is much lower due to the vacuum, allowing the water to boil without needing to be heated. This is a perfect demonstration of the relationship between boiling point and pressure.

  • Decreased pressure: Lowers boiling point
  • Vapor pressure: Must equal surrounding pressure for boiling to occur
Understanding this relationship helps explain how changes in pressure affect the phase stability of liquids.
Phase Change
Phase changes are transitions between different states of matter: solid, liquid, and gas. Common phase changes include melting, freezing, boiling, and condensation. During these changes, a substance can absorb or release energy without changing temperature. For instance, in the process of boiling, a liquid absorbs energy to overcome intermolecular forces and transition into vapor.

When a liquid, like water, boils in a vacuum, it goes through a phase change from liquid to gas as it vaporizes. This process utilizes energy from the surrounding liquid, causing the temperature to drop. If the energy absorbed leads to a decrease in temperature below the freezing point, the water can start to freeze, even while boiling.

  • Energy absorption: Necessary for phase changes
  • Temperature drop: Can lead to freezing during boiling
This paradoxical behavior highlights the complex nature of phase changes, where multiple transformations can occur simultaneously under unique conditions.
Thermodynamics
Thermodynamics is the branch of physics that deals with heat, work, and the internal energy of systems. One key aspect is the understanding of how energy is transferred and transformed. In the case of sweating and boiling water in a vacuum, thermodynamic principles are at work.

When you sweat, the evaporation process is a cooling mechanism that relies on energy transfer. The body releases heat energy as sweat evaporates, thus cooling the skin's surface. Similarly, boiling and subsequent freezing of water in a vacuum implement the principles of energy absorption and conservation. As water vaporizes, it absorbs energy, leading to a decrease in temperature. Eventually, this cooling effect can lead the remaining liquid water to freeze.

  • Energy transfer: Central to evaporative cooling
  • Heat absorption: Leads to phase transitions
These examples underscore the importance of thermodynamics in everyday processes and illustrate how energy changes can affect the state and temperature of a substance.

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Most popular questions from this chapter

Suppose the vapor pressure of a substance is measured at two different temperatures. (a) By using the Clausius-Clapeyron equation (Equation 11.1\()\) derive the following relationship between the vapor pressures, \(P_{1}\) and \(P_{2}\), and the absolute temperatures at which they were measured, \(T_{1}\) and \(T_{2}\) : $$ \ln \frac{P_{1}}{P_{2}}=-\frac{\Delta H_{\text {vap }}}{R}\left(\frac{1}{T_{1}}-\frac{1}{T_{2}}\right) $$ (b) Gasoline is a mixture of hydrocarbons, a component of which is octane \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\right)\). Octane has a vapor pressure of \(1.86 \mathrm{kPa}\) at \(25^{\circ} \mathrm{C}\) and a vapor pressure of \(19.3 \mathrm{kPa}\) at \(75^{\circ} \mathrm{C}\). Use these data and the equation in part (a) to calculate the heat of vaporization of octane. \((\mathbf{c})\) By using the equation in part (a) and the data given in part (b), calculate the normal boiling point of octane. Compare your answer to the one you obtained from Exercise 11.81 . (d) Calculate the vapor pressure of octane at \(-30^{\circ} \mathrm{C}\).

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{~F}, \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{Br} ?\)

The table below shows some physical properties of compounds containing O-H groups. \begin{tabular}{lccc} \hline Liquid & Molecular Weight & Experimental Dipole Moment & Boiling Point \\\ \hline \(\mathrm{CH}_{3} \mathrm{OH}\) & 32.04 & 1.7 & \(64.7^{\circ} \mathrm{C}\) \\\ \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) & 74.12 & 1.66 & \(117.7^{\circ} \mathrm{C}\) \\ \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) & 62.07 & 1.5 & \(197.3^{\circ} \mathrm{C}\) \\ \hline \end{tabular} Which of the following statements best explains these data? (a) The larger the dipole moment, the stronger the intermolecular forces, and therefore the boiling point is lowest for the molecule with the largest dipole moment. (b) The dispersion forces increase from \(\mathrm{CH}_{3} \mathrm{OH} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) and \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\); since the boiling point also increases in this order, the dispersion forces must be the major contributing factor for the boiling point trend; \((\mathbf{c}) \mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) has two groups capable of hydrogen bonding per molecule, whereas \(\mathrm{CH}_{3} \mathrm{OH}\) and \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) have only one; therefore, \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) has the highest boiling point.

As the intermolecular attractive forces between molecules increase in magnitude, do you expect each of the following to increase or decrease in magnitude? (a) Vapor pressure, (b) heat of vaporization, (c) boiling point, (d) freezing point, (e) viscosity, (f) surface tension, \((\mathrm{g})\) critical temperature.

At room temperature, \(\mathrm{CO}_{2}\) is a gas, \(\mathrm{CCl}_{4}\) is a liquid, and \(\mathrm{C}_{60}\) (fullerene) is a solid. List these substances in order of (a) increasing intermolecular energy of attraction and (b) increasing boiling point.

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