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(a) What is the significance of the critical point in a phase diagram? (b) Why does the line that separates the gas and liquid nhases end at the criticat noint?

Short Answer

Expert verified
The critical point marks where liquid and gas become indistinguishable. It ends the vapor-liquid line because beyond this, there's no distinct phase transition.

Step by step solution

01

- Understanding Critical Point Significance

The critical point in a phase diagram represents the unique temperature and pressure at which the distinction between liquid and gas phases vanishes. At this point, the properties of the gas and liquid become indistinguishable, and this state is known as a supercritical fluid. Thus, the critical point signifies the end of the line that separates liquid and gas phases.
02

- Exploring Phase Boundaries

In a phase diagram, different boundaries represent the conditions under which different phases (solid, liquid, gas) coexist. The line separating liquid and gas phases is called the vapor-liquid equilibrium line. This line ends at the critical point because beyond this point, there is no distinct phase transition between liquid and gas; instead, the substance exists as a supercritical fluid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phase Diagram
In the world of chemistry and physics, a phase diagram is a crucial tool used to understand the conditions under which different states of matter exist and coexist. A phase diagram is a graphical representation that shows regions of stability for the solid, liquid, and gaseous phases of a substance based on temperature and pressure.

  • On the diagram, each region signifies a different state: solid, liquid, or gas.
  • The lines or boundaries between these regions represent phase equilibrium, where two phases can exist together.
  • The critical point marks the end of the vapor-liquid equilibrium line, illustrating where the liquid and gas phases become indistinguishable.
Understanding phase diagrams helps predict the behavior of substances under varying pressure and temperature conditions, providing a visual guide for complex thermodynamic concepts.
Supercritical Fluid
Beyond the critical point on a phase diagram lies an intriguing phase known as the "supercritical fluid". This state of matter emerges when a substance's temperature and pressure exceed the critical threshold, causing traditional properties of gas and liquid to blend.

Supercritical fluids possess unique characteristics:
  • They have the ability to diffuse through solids like a gas.
  • They have densities closer to liquids, allowing them to dissolve materials effectively.
  • Due to these properties, supercritical fluids find applications in fields such as extraction, chromatography, and as reaction solvents.
By understanding supercritical fluids, we can harness their unique properties for innovative industrial and scientific applications.
Vapor-Liquid Equilibrium
The concept of vapor-liquid equilibrium is key to understanding phase changes between gas and liquid. As seen in a phase diagram, the vapor-liquid equilibrium line represents the set of conditions where the two phases exist together.

  • This line is crucial for determining phase changes during processes like boiling and condensation.
  • It shows the boiling point of a substance at various pressures.
  • As pressure increases, so does the boiling point, until it reaches the critical point where this line ends.
Beyond this line, no clear boundary exists between vapor and liquid, indicating that the substance behaves as a supercritical fluid. Understanding vapor-liquid equilibrium is essential for processes in industries like distillation and refrigeration, where precise control over phase changes is needed.

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Most popular questions from this chapter

True or false: (a) \(\mathrm{CBr}_{4}\) is more volatile than \(\mathrm{CCl}_{4}\). (b) \(\mathrm{CBr}_{4}\) has a higher boiling point than \(\mathrm{CCl}_{4}\). (c) \(\mathrm{CBr}_{4}\) has weaker intermolecular forces than \(\mathrm{CCl}_{4}\). (d) \(\mathrm{CBr}_{4}\) has a higher yapor pressure at the same temperature than \(C O\)

Describe the intermolecular forces that must be overcome to convert these substances from a liquid to a gas: (a) \(\mathrm{CF}_{4}\) (b) \(\mathrm{NH}_{3}\), (c) \(\mathrm{BCl}_{3}\)

The table shown here lists the molar heats of vaporization for several organic compounds. Use specific examples from this list to illustrate how the heat of vaporization varies with (a) molar mass, (b) molecular shape, \((\mathbf{c})\) molecular polarity, (d) hydrogen-bonding interactions. Explain these comparisons in terms of the nature of the intermolecular forces at work. (You may find it helpful to draw out the structural formula for each compound.) \begin{tabular}{lc} \hline Compound & Heat of Vaporization (kJ/mol) \\ \hline \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\) & 19.0 \\ \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\) & 27.6 \\ \(\mathrm{CH}_{3} \mathrm{CHBrCH}_{3}\) & 31.8 \\ \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) & 32.0 \\ \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}\) & 33.6 \\ \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) & 47.3 \\ \hline \end{tabular}

The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temperature and pressure. In an experiment, \(8.00 \mathrm{~L}\) of argon gas is passed through \(11.7872 \mathrm{~g}\) of liquid hexane \(\mathrm{C}_{6} \mathrm{H}_{14}\) at \(30.0^{\circ} \mathrm{C}\). The mass of the remaining liquid after the experiment is \(4.875 \mathrm{~g}\). Assuming that the gas becomes saturated with hexane vapor and that the total gas volume and temperature remain constant, what is the vapor pressure of hexane in atm?

CHClFz is a type of hydrochlorofluorocarbon (HCFC) that has a comparatively lower damaging effect on the ozone layer. It is used as a replacement for chlorofluorocarbons (CFCs). The heat of vaporization is \(233.95 \mathrm{~kJ} / \mathrm{g}\). What mass of this substance must evaporate to freeze \(15 \mathrm{~g}\) of water ini. tially at \(15^{\circ} \mathrm{C} ?\) (The heat of fusion of water is \(334 \mathrm{~J} / \mathrm{g}\); the specific heat of water is \(4.18 \mathrm{~J} / \mathrm{g} \cdot \mathrm{K} .\) )

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