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(a) What conditions must be met if a molecule with polar bonds is nonpolar? (b) What geometries will give nonpolar molecules for \(\mathrm{AB}_{2}, \mathrm{AB}_{3}\), and \(\mathrm{AB}_{4}\) geometries?

Short Answer

Expert verified
(a) For a molecule with polar bonds to be nonpolar, it must have a symmetrical distribution of bond dipoles, resulting in the vector sum of all bond dipoles being zero. (b) The nonpolar geometries for AB_2, AB_3, and AB_4 molecules are linear, trigonal planar, and tetrahedral, respectively.

Step by step solution

01

Identify conditions for a molecule with polar bonds to be nonpolar

For a molecule with polar bonds to be nonpolar, the bond dipoles must cancel each other out. This can happen if the molecule has a symmetrical distribution of these bond dipoles. In other words, the molecule must have a geometry where the vector sum of all the bond dipoles is zero.
02

Determine geometry for nonpolar AB2 molecules

For an AB_2 molecule to be nonpolar, the bond dipoles must cancel each other out. This can happen when the A atom is in the center and the two B atoms are in a linear orientation. The bond dipoles will be equal and opposite, thus canceling each other out. So, the nonpolar geometry for an AB_2 molecule is linear.
03

Determine geometry for nonpolar AB3 molecules

For an AB_3 molecule to be nonpolar, the bond dipoles must cancel each other out. This can happen when the A atom is in the center and the three B atoms are in a trigonal planar orientation. The bond dipoles will be equal in magnitude and in a symmetrical distribution, thus canceling each other out. So, the nonpolar geometry for an AB_3 molecule is trigonal planar.
04

Determine geometry for nonpolar AB4 molecules

For an AB_4 molecule to be nonpolar, the bond dipoles must cancel each other out. This can happen when the A atom is in the center and the four B atoms are in a tetrahedral orientation. The bond dipoles will be equal in magnitude and in a symmetrical distribution, thus canceling each other out. So, the nonpolar geometry for an AB_4 molecule is tetrahedral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polar Bonds
Polar bonds occur when two atoms share a pair of electrons, but the sharing is not even. One atom pulls the electrons closer due to its higher electronegativity, creating a difference in electric charge. This uneven distribution of charge creates what we call a dipole moment. It is essential to remember that just because a molecule has polar bonds, it doesn't necessarily mean the whole molecule is polar. There are other factors at play, like the molecule's shape, that can influence the overall polarity. Understanding polar bonds is crucial for predicting how a molecule will interact with others, influencing properties such as solubility and boiling points.
Molecular Geometry
Molecular geometry describes the three-dimensional arrangement of atoms within a molecule. It is a significant factor in determining whether a molecule with polar bonds is overall polar or nonpolar. Specific geometries allow the bond dipoles to cancel each other out, resulting in a nonpolar molecule despite the presence of polar bonds. For example:
  • Linear geometry (e.g., AB2) can lead to nonpolar molecules if the dipoles are exactly opposite.
  • Trigonal planar geometry (e.g., AB3) can be nonpolar when dipoles are evenly distributed at 120 degrees.
  • Tetrahedral geometry (e.g., AB4) achieves nonpolarity when the dipoles are symmetrically arranged around the central atom.
Thus, understanding molecular geometry helps in predicting whether the molecule's polar bonds cancel out or not.
Bond Dipoles
A bond dipole arises when electrons in a bond are unevenly shared between two atoms, creating a miniature electric "push and pull" along the bond. This dipole can be visualized as an arrow pointing toward the more electronegative atom. It's like having a little battery in each bond where one side is slightly positive, and the other is slightly negative. These bond dipoles can add together to affect the whole molecule's polarity. If bond dipoles in a molecule point in different directions and do not cancel out, the molecule is polar as a whole. In contrast, if they cancel out, the molecule becomes nonpolar overall, regardless of having polar bonds.
Symmetrical Distribution
Symmetrical distribution in molecules with polar bonds is key to achieving nonpolarity. When the bond dipoles distribute uniformly around the central atom, they can effectively cancel each other out. In such arrangements, the vector of each dipole is balanced by another, leading to a net dipole moment of zero. This means the molecule does not have a positive or negative side, appearing neutral in terms of electric charge. Symmetry is crucial in determining the overall nonpolar nature in molecules such as CO2, where linear geometry ensures opposite dipoles counterbalance each other, resulting in no net dipole moment.

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Most popular questions from this chapter

You can think of the bonding in the \(\mathrm{Cl}_{2}\) molecule in several ways. For example, you can picturethe Cl- -Cl bond containing two electrons that each come from the \(3 p\) orbitals of a \(\mathrm{Cl}\) atom that are pointing in the appropriate direction. However, you can also think about hybrid orbitals. (a) Draw the Lewis structure of the \(\mathrm{Cl}_{2}\) molecule. (b) What is the hybridization of each Cl atom? (c) What kind of orbital overlap, in this view, makes the \(\mathrm{Cl}-\mathrm{Cl}\) bond? (d) Imagine if you could measure the positions of the lone pairs of electrons in \(\mathrm{Cl}_{2}\). How would you distinguish between the atomic orbital and hybrid orbital models of bonding using that knowledge? (e) You can also treat \(\mathrm{Cl}_{2}\) using molecular orbital theory to obtain an energy level diagram similar to that for \(\mathrm{F}_{2}\). Design an experiment that could tell you if the MO picture of \(\mathrm{Cl}_{2}\) is the best one, assuming you could easily measure bond lengths, bond energies, and the light absorption properties for any ionized species.

How many nonbonding electron pairs are there in each of the following molecules: (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~S} ;\) (b) \(\mathrm{HCN}\); (c) \(\mathrm{H}_{2} \mathrm{C}_{2} ;\) (d) \(\mathrm{CH}_{3} \mathrm{~F}\) ?

The \(\mathrm{O}-\mathrm{H}\) bond lengths in the water molecule \(\left(\mathrm{H}_{2} \mathrm{O}\right)\) are \(0.96 \AA\), and the \(\mathrm{H}-\mathrm{O}-\mathrm{H}\) angle is \(104.5^{\circ}\). The dipole moment of the water molecule is \(1.85 \mathrm{D}\). (a) In what directions do the bond dipoles of the \(\mathrm{O}-\mathrm{H}\) bonds point? In what direction does the dipole moment vector of the water molecule point? (b) Calculate the magnitude of the bond dipole of the \(\mathrm{O}-\mathrm{H}\) bonds. (Note: You will need to use vector addition to do this.) (c) Compare your answer from part (b) to the dipole moments of the hydrogen halides (Table 8.3). Is your answer in accord with the relative electronegativity of oxygen?

The molecules \(\mathrm{SiF}_{4}, \mathrm{SF}_{4}\), and \(\mathrm{XeF}_{4}\) have molecular formulas of the type \(\mathrm{AF}_{4}\), but the molecules have different molecular geometries. Predict the shape of each molecule, and explain why the shapes differ.

Consider the Lewis structure for glycine, the simplest amino acid: (a) What are the approximate bond angles about each of the two carbon atoms, and what are the hybridizations of the orbitals on each of them? (b) What are the hybridizations of the orbitals on the two oxygens and the nitrogen atom, and what are the approximate bond angles at the nitrogen? (c) What is the total number of \(\sigma\) bonds in the entire molecule, and what is the total number of \(\pi\) bonds?

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