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(a) Does \(\mathrm{SCl}_{2}\) have a dipole moment? If so, in which direction does the net dipole point? (b) Does \(\mathrm{BeCl}_{2}\) have a dipole moment? If so, in which direction does the net dipole point?

Short Answer

Expert verified
(a) Yes, SCl2 has a dipole moment. The net dipole points from the sulfur atom (less electronegative) to the center point between the two chlorine atoms (more electronegative). (b) No, BeCl2 does not have a dipole moment, as the bond dipoles cancel each other out due to its linear molecular structure.

Step by step solution

01

Molecular Structure and Polarity of SCl2

The molecule SCl2 (sulfur dichloride) has a central sulfur atom bonded to two chlorine atoms. The sulfur atom has 3 lone pairs and 2 bonding pairs of electrons. The electron pair geometry of SCl2 is trigonal bipyramidal, but because of the presence of only two bonding pairs of electrons, it has a bent molecular geometry. When determining molecular geometry, we only consider the positions of the bonded atoms and ignore the lone pairs. SCl2 molecule has polar S-Cl bonds due to the electronegativity difference between sulfur and chlorine atoms. Since the molecule has a bent shape, the bond dipoles do not cancel each other and there is a net dipole moment.
02

Direction of Dipole Moment in SCl2

The direction of the net dipole moment in SCl2 is from the sulfur atom (less electronegative) to the center point between the two chlorine atoms (more electronegative).
03

Molecular Structure and Polarity of BeCl2

The molecule BeCl2 (beryllium dichloride) consists of a central beryllium atom bonded to two chlorine atoms. The beryllium atom has no lone pairs and 2 bonding pairs of electrons. The electron pair geometry of BeCl2 is linear, and its molecular geometry is also linear since there are no lone pairs on the central atom to distort the shape. BeCl2 molecule has polar Be-Cl bonds due to the electronegativity difference between beryllium and chlorine atoms. However, because of the linear molecular geometry, the bond dipoles cancel each other out.
04

Direction of Dipole Moment in BeCl2

As the bond dipoles cancel each other out in BeCl2, it does not have a net dipole moment. To sum up: - SCl2 has a net dipole moment with its overall direction from the sulfur atom to the center point between the two chlorine atoms. - BeCl2 does not have a net dipole moment due to the cancellation of bond dipoles in its linear molecular structure.

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Most popular questions from this chapter

(a) Explain why the following ions have different bond angles: \(\mathrm{ClO}_{2}^{-}\) and \(\mathrm{NO}_{2}^{-}\). Predict the bond angle in each case. (b) Explain why the \(\mathrm{XeF}_{2}\) molecule is linear and not bent.

(a) What does the term diamagnetism mean? (b) How does a diamagnetic substance respond to a magnetic field? (c) Which of the following ions would you expect to be diamagnetic: \(\mathrm{N}_{2}{ }^{2-}, \mathrm{O}_{2}^{2-}, \mathrm{Be}_{2}{ }^{2+}, \mathrm{C}_{2}^{-}\) ?

You can think of the bonding in the \(\mathrm{Cl}_{2}\) molecule in several ways. For example, you can picturethe Cl- -Cl bond containing two electrons that each come from the \(3 p\) orbitals of a \(\mathrm{Cl}\) atom that are pointing in the appropriate direction. However, you can also think about hybrid orbitals. (a) Draw the Lewis structure of the \(\mathrm{Cl}_{2}\) molecule. (b) What is the hybridization of each Cl atom? (c) What kind of orbital overlap, in this view, makes the \(\mathrm{Cl}-\mathrm{Cl}\) bond? (d) Imagine if you could measure the positions of the lone pairs of electrons in \(\mathrm{Cl}_{2}\). How would you distinguish between the atomic orbital and hybrid orbital models of bonding using that knowledge? (e) You can also treat \(\mathrm{Cl}_{2}\) using molecular orbital theory to obtain an energy level diagram similar to that for \(\mathrm{F}_{2}\). Design an experiment that could tell you if the MO picture of \(\mathrm{Cl}_{2}\) is the best one, assuming you could easily measure bond lengths, bond energies, and the light absorption properties for any ionized species.

(a) Explain why \(\mathrm{BrF}_{4}^{-}\) is square planar, whereas \(\mathrm{BF}_{4}^{-}\) is tetrahedral. (b) Water, \(\mathrm{H}_{2} \mathrm{O}\), is a bent molecule. Predict the shape of the molecular ion formed from the water molecule if you were able to remove four electrons to make \(\left(\mathrm{H}_{2} \mathrm{O}\right)^{4+}\).

Predict the trend in the \(\mathrm{F}\) (axial) \(-\mathrm{A}-\mathrm{F}\) (equatorial) bond angle in the following \(\mathrm{AF}_{n}\) molecules: \(\mathrm{PF}_{5}, \mathrm{SF}_{4}\), and \(\mathrm{ClF}_{3}\).

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