Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What are the electron-domain and molecular geometries of a molecule that has the following electron domains on its central atom? (a) three bonding domains and no nonbonding domains, (b) three bonding domains and one nonbonding domain, (c) two bonding domains and two nonbonding domains.

Short Answer

Expert verified
In summary, for the given electron domains on the central atom: (a) three bonding domains and no nonbonding domains have both electron-domain and molecular geometries as trigonal planar. (b) three bonding domains and one nonbonding domain have an electron-domain geometry of tetrahedral and a molecular geometry of trigonal pyramidal. (c) two bonding domains and two nonbonding domains have an electron-domain geometry of tetrahedral and a molecular geometry of bent or V-shaped.

Step by step solution

01

(a) Three bonding domains and no nonbonding domains

In this case, there are a total of three electron domains (all bonding) around the central atom. According to VSEPR theory, these domains will arrange themselves to minimize repulsion and be as far apart as possible. In this situation, the electron-domain geometry is trigonal planar. Since there are no nonbonding domains, the molecular geometry is the same as the electron-domain geometry. Therefore, the molecular geometry is also trigonal planar.
02

(b) Three bonding domains and one nonbonding domain

In this case, there are a total of four electron domains (three bonding and one nonbonding) around the central atom. The electron-domain geometry will be tetrahedral, as the electron domains arrange themselves to be as far apart as possible in a tetrahedron shape. However, since there is one nonbonding domain, the molecular geometry will be different from the electron-domain geometry. In this case, the molecular geometry is trigonal pyramidal, as the three bonding domains form a pyramid shape around the central atom.
03

(c) Two bonding domains and two nonbonding domains

In this case, there are a total of four electron domains (two bonding and two nonbonding) around the central atom. Just like in case (b), the electron-domain geometry will be tetrahedral. However, since there are two nonbonding domains, the molecular geometry will be different from the electron-domain geometry. In this case, the molecular geometry is bent or V-shaped, as the two bonding domains form an angle around the central atom. The presence of the two nonbonding domains pushes the bonding domains closer together, resulting in a bent molecular geometry.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron-Domain Geometry
Understanding the spatial arrangement of electron domains (regions where electrons are most likely to be found) around a central atom is critical in molecular geometry. This arrangement, known as the electron-domain geometry, takes into account both bonding and nonbonding electron pairs. The electron domains repel each other and take on a geometry that minimizes this repulsion, which is the basis for predicting the shape of the molecule.

For instance, a molecule with three bonding domains around the central atom, as in our exercise (a), leads to what is called a trigonal planar electron-domain geometry. This is because three points equally spaced in two dimensions form a flat triangle, representing the optimal way to minimize repulsion between these domains.
VSEPR Theory
Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used to predict the shape of individual molecules based upon the extent of electron-pair electrostatic repulsion. It states that electron pairs around a central atom tend to orient themselves as far apart as possible. This behavior is due to the negatively charged electron domains repelling each other. The VSEPR theory is foundational for understanding why certain molecules take on specific shapes.

The beauty of VSEPR theory lies in its simplicity and predictive power. For example, with four electron domains, as in cases (b) and (c) in the exercise, the electron-domain geometry is predicted to be tetrahedral, which is a shape consisting of four points arranged in three dimensions so that each point is equidistant from the others.
Nonbonding Domains
Nonbonding domains, also known as lone pairs of electrons, are pairs of valence electrons that do not participate in bonding with other atoms. They occupy more space than bonding pairs because they are held by only one atom and do not have the bond's 'constrictive' effect. The presence and number of nonbonding domains profoundly influence the molecule's final shape, as seen in parts (b) and (c) of the exercise.

For example, in case (b), there's one nonbonding domain on the central atom, which results in a trigonal pyramidal molecular shape due to the lone pair 'pushing down' on the bonding domains. This shows how nonbonding domains impact the overall molecular geometry by altering the 'ideal' electron-domain geometry.
Trigonal Planar
A trigonal planar molecular shape occurs when there are three bonding domains and no nonbonding domains, as detailed in exercise (a). In this arrangement, the molecule is flat with angles of 120 degrees between each bonding domain. The atoms are arranged in a triangle on a single plane, with the central atom in the center. This shape is both the electron-domain geometry and the molecular geometry when there are no lone pairs to manipulate the structure.
Tetrahedral
With four total electron domains, whether bonding or nonbonding, the electron-domain geometry is tetrahedral. This is due to the fact that a tetrahedron, where each corner represents an electron domain, is the ideal shape for minimizing repulsions in three-dimensional space. The tetrahedral geometry has bond angles of about 109.5 degrees and is symmetrically arranged in three dimensions. It's critical to remember this base shape when trying to visualize molecules with four total electron domains, regardless of whether they are bonding or nonbonding.
Trigonal Pyramidal
When a molecule has three bonding domains and one nonbonding domain, like in exercise (b), the molecular shape becomes trigonal pyramidal. The nonbonding pair's repulsion 'pushes' the bonding domains into a pyramid shape with the central atom at the apex. In this configuration, the bond angles are slightly less than 109.5 degrees due to the larger space that the nonbonding domain occupies, which compresses the bonding domains slightly.
Bent Molecular Shape
The bent molecular shape, also known as angular or V-shaped, typically arises when there are two bonding domains and nonbonding domains present, as in exercise (c). The nonbonding domains are located on opposite sides of the central atom, which repel each other and cause the bonding atoms to come together at an angle. The bond angle is reduced from the theoretical 109.5 degrees of the tetrahedral arrangement to less than that, often around 105 degrees, as a result of the two lone electron pairs pushing away the bonding pairs. It is very important for students to grasp this visual as it demonstrates the distortive effect of nonbonding domains on molecular geometry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An \(\mathrm{AB}_{2}\) molecule is described as linear, and the \(\mathrm{A}-\mathrm{B}\) bond length is known. (a) Does this information completely describe the geometry of the molecule? (b) Can you tell how many nonbonding pairs of electrons are around the \(\mathrm{A}\) atom from this information?

In ozone, \(\mathrm{O}_{3}\), the two oxygen atoms on the ends of the molecule are equivalent to one another. (a) What is the best choice of hybridization scheme for the atoms of ozone? (b) For one of the resonance forms of ozone, which of the orbitals are used to make bonds and which are used to hold nonbonding pairs of electrons? (c) Which of the orbitals can be used to delocalize the \(\pi\) electrons? (d) How many electrons are delocalized in the \(\pi\) system of ozone?

The vertices of a tetrahedron correspond to four alternating corners of a cube. By using analytical geometry, demonstrate that the angle made by connecting two of the vertices to a point at the center of the cube is \(109.5^{\circ}\), the characteristic angle for tetrahedral molecules.

Propylene, \(\mathrm{C}_{3} \mathrm{H}_{6}\), is a gas that is used to form the important polymer called polypropylene. Its Lewis structure is (a) What is the total number of valence electrons in the propylene molecule? (b) How many valence electrons are used to make \(\sigma\) bonds in the molecule? (c) How many valence electrons are used to make \(\pi\) bonds in the molecule? (d) How many valence electrons remain in nonbonding pairs in the molecule? (e) What is the hybridization at each carbon atom in the molecule?

(a) What is meant by the term orbital overlap? (b) Describe what a chemical bond is in terms of electron density between two atoms.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free