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Why does xenon react with fluorine, whereas neon does not?

Short Answer

Expert verified
Xenon reacts with fluorine due to its larger atomic size and the greater shielding effect on its valence electrons, which allows the highly electronegative fluorine to attract the outermost electron of xenon, forming stable compounds such as XeF2, XeF4, and XeF6. In contrast, neon has a smaller atomic size, and its valence electrons are strongly attracted to its nucleus, making it difficult for fluorine to attract its electrons and therefore remaining unreactive.

Step by step solution

01

Introduction to Noble Gases and their Reactivity

Noble gases (Group 18 elements), such as Xenon (Xe) and Neon (Ne), generally have a full valence electron shell. This makes them very stable and less reactive compared to other elements in the periodic table. However, some noble gases can still react under certain conditions. In this case, we will discuss why xenon reacts with fluorine and neon does not.
02

Electronic Configuration of Xenon and Neon

To understand the reactivity of xenon and neon, we first need to look at their electronic configurations. The electronic configuration of xenon (Xe) is [Kr]4d10 5s2 5p6, and neon (Ne) is [He] 2s2 2p6. Both elements have full valence electron shells, making them stable and less reactive. However, xenon has more energy levels than neon, giving it a larger atomic size and more shielding of its valence electrons by inner electrons. This shielding effect in xenon reduces the effective nuclear charge on its valence electrons, thus making it easier to remove electrons from the outermost shell when compared with neon.
03

Fluorine and its Reactivity

Fluorine (F) is a very reactive element as it belongs to the halogens (Group 17) in the periodic table. Fluorine has the highest electronegativity among all elements, making it highly attractive to electrons. As a result, it has a strong tendency to acquire an electron to complete its valence electron shell. Fluorine can react with a range of elements and can even break the stability of noble gases, such as xenon.
04

Xenon and Fluorine Reaction

When xenon reacts with fluorine, it forms compounds such as XeF2, XeF4, and XeF6, depending on the reaction conditions. The outermost shell electrons of xenon are not strongly attracted to the nucleus due to the shielding effect. The highly electronegative fluorine can attract the outermost electron of xenon. This allows xenon to lose the electron to fluorine, and a stable compound is formed by sharing the electrons between the two atoms in a covalent bond.
05

Neon and Fluorine Reaction

Neon, on the other hand, has a full valence shell and a smaller atomic size. Its outer electrons are very close to the nucleus, and the effective nuclear charge is quite strong. As a result, it is challenging for the highly electronegative fluorine to attract the outermost electrons of neon to form a stable compound. Since neon's valence electrons remain strongly attracted to its nucleus, it does not react with fluorine. In conclusion, xenon can react with fluorine because of its larger atomic size and the greater shielding effect on its valence electrons, which allows fluorine to attract the outermost electron of xenon and form stable compounds. In contrast, neon's small atomic size and strong effective nuclear charge make it difficult for fluorine to attract its valence electrons, thus remaining unreactive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Xenon and Fluorine Reaction
Xenon, a noble gas, is known to react with the highly reactive element fluorine under certain conditions. Despite the traditional view of noble gases as being inert, xenon's larger atomic size and unique properties allow it to form compounds with fluorine, such as XeF2, XeF4, and XeF6. This reactivity is possible due to the relatively weaker hold of its nucleus on the outermost electrons, a result of the shielding effect. This makes it feasible for the electronegative fluorine to attach and stabilize these electrons, facilitating covalent bonding.
Electronic Configuration
Understanding the electronic configuration of elements is crucial to grasping their chemical behavior. Xenon has the electronic configuration of \([Kr]4d^{10}5s^25p^6\), indicating a completely filled valence shell. Similarly, neon's electronic configuration is \([He]2s^22p^6\), also showing a full valence shell. However, xenon's electrons are distributed across more energy levels than those of neon. This multi-layered distribution contributes to xenon's ability to interact with fluorine, distinguishing its reactivity from neon's typical stability.
Shielding Effect
The shielding effect plays a vital role in the reactivity of xenon compared to neon. In simple terms, the shielding effect occurs when inner electron shells partly block or 'shield' the positive charge exerted by the nucleus on the valence electrons. This effect is more pronounced in xenon because of its larger number of inner electron shells, leading to a reduction in the effective nuclear charge experienced by the outermost electrons. With a reduced effective nuclear charge, it becomes easier for xenon's electrons to be attracted by a strong electron acceptor like fluorine.
Fluorine Reactivity
Fluorine is renowned for its high reactivity, attributed to its status as the most electronegative element. This means that fluorine has a very strong tendency to attract and accept electrons to complete its valence shell, often attaining a stable electron configuration in the process. Its power to break into even the most stable electron configurations, like that of xenon, stems from its intense drive to gain electrons, making it one of the few elements that can coax a reaction from typically unreactive noble gases.

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Most popular questions from this chapter

Identify the element whose ions have the following electron configurations: (a) a 2+ ion with \([\operatorname{Ar}] 3 d^{9}\), (b) a 1+ ion with [Xe]4f \(^{14} 5 d^{10} 6 s^{2}\). How many unpaired electrons does each ion contain?

Explain the following variations in atomic or ionic radii: (a) \(1^{-}>\mathrm{I}>\mathrm{I}^{+},(\mathrm{b}) \mathrm{Ca}^{2+}>\mathrm{Mg}^{2+}>\mathrm{Be}^{2+}\) (c) \(\mathrm{Fe}>\mathrm{Fe}^{2+}>\mathrm{Fe}^{3+}\).

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like a nonmetal. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity. (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals.

(a) Why does the quantum mechanical description of many-electron atoms make it difficult to define a precise atomic radius? (b) When nonbonded atoms come up against one another, what determines how closely the nuclear centers can approach?

As we move across a period of the periodic table, why do the sizes of the transition elements change more gradually than those of the representative elements?

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