Chemical calculations in solutions involve converting between different units of measurement to understand how a solute is distributed within a solvent, like water. For the exercise, it's essential to calculate how much sodium arsenate is permissible in a 1-liter sample of water, given a specific concentration of arsenic.
The process begins by converting arsenic mass concentration (in micrograms per liter) to a molar concentration (moles per liter) using arsenic's molar mass. This involves dividing the mass of arsenic by its molar mass to find moles.
- The concentration of arsenic is 10 µg/L, which is converted by calculating \(\frac{10 imes 10^{-6} \, \text{g}}{74.92 \, \text{g/mol}} \approx 1.34 \times 10^{-7} \, \text{mol/L}\).
Next, since sodium arsenate has a 1:1 molar ratio with arsenic in the compound, the moles of sodium arsenate will match those of arsenic. Finally, using the molar mass of sodium arsenate (207.87 g/mol), the mass of sodium arsenate in the solution can be found by multiplying the molarity by the molar mass.
- This leads to a mass calculation of \(1.34 \times 10^{-7} \, \text{mol/L} \times 207.87 \, \text{g/mol} = 2.79 \times 10^{-6} \, \text{g}\).
Such precise calculations are vital in ensuring chemical safety standards are adhered to in public water supplies, confirming compliance with regulations like those set forth in the Safe Drinking Water Act.