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(a) Define the terms theoretical yield, actual yield, and percent yield. (b) Why is the actual yield in a reaction almost always less than the theoretical yield? (c) Can a reaction ever have \(110 \%\) actual yield?

Short Answer

Expert verified
(a) Theoretical yield is the maximum amount of product that can be produced from a given amount of reactants, based on the balanced chemical equation. Actual yield is the amount of product that is actually obtained in a chemical reaction. Percent yield is a measure of the efficiency of a reaction, calculated by dividing the actual yield by the theoretical yield and multiplying by 100. (b) Actual yield is typically less than theoretical yield due to reasons such as side reactions, incomplete reactions, losses during product isolation, and limitations in reaction equilibrium. (c) In general, a reaction cannot have a percent yield greater than 100%. Percent yields slightly greater than 100% can be observed in some cases due to experimental error or variations in measurement techniques, but these cases represent measurement discrepancies rather than an actual excess of the product.

Step by step solution

01

(a) Definitions of Theoretical Yield, Actual Yield, and Percent Yield

Theoretical yield is the maximum amount of product that can be produced from a given amount of reactants, based on the balanced chemical equation. Actual yield is the amount of product that is actually obtained in a chemical reaction. Percent yield is a measure of the efficiency of a reaction, calculated by dividing the actual yield by the theoretical yield and multiplying by 100.
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(b) Why Actual Yield is Typically Less Than Theoretical Yield

There are several reasons why the actual yield in a reaction is almost always less than the theoretical yield: 1. Side reactions: Competing reactions may occur along with the desired reaction, consuming reactants and producing undesired products. 2. Incomplete reactions: Some reactants may not fully react, and a portion of them may remain unreacted. 3. Losses during product isolation: Product may be lost during the steps taken to separate it from the reaction mixture and purify it. 4. Limitations in reaction equilibrium: In some cases, the equilibrium constant for the reaction may be such that complete conversion of reactants to products is not favored.
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(c) Possibility of a Reaction Having a Percent Yield Greater Than 100%

In general, a reaction cannot have a percent yield greater than 100%. A percent yield over 100% would indicate that more product was obtained than what is theoretically possible based on the balanced chemical equation. However, percent yields slightly greater than 100% can be observed in some cases due to experimental error or variations in measurement techniques. These cases do not represent an actual excess of the product but rather a discrepancy in measurement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Actual Yield
In chemistry, when a reaction occurs, the term **actual yield** refers to the measured amount of product obtained from the chemical reaction. This is different from the theoretical yield, which is the maximum product that could be formed, calculated based on the stoichiometric relationships within the balanced chemical equation. The actual yield is often less because of several practical factors occurring during the reaction.

Some common reasons that lead to a lower actual yield include:
  • **Side Reactions**: Sometimes, other unwanted reactions take place consuming some of the reactants that were meant to produce the desired product.
  • **Incomplete Reactions**: Not all reactants completely turn into products; some remain unchanged.
  • **Product Recovery Losses**: During purification or separation processes, some of the product might be lost.
Understanding actual yield helps chemists to evaluate the efficiency of a reaction and potentially optimize conditions to improve product yield.
Percent Yield
Once you calculate the actual yield, you can determine how efficient a reaction is by calculating the **percent yield**. The percent yield is a crucial metric in chemistry for assessing how well a reaction performed compared to its theoretical maximum.To find the percent yield, you use the formula:\[\text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\]
This calculation expresses the efficiency of a reaction as a percentage. A percent yield that is close to 100% indicates a highly efficient reaction. However, it's important to note that **percent yields over 100%** typically suggest errors in measurement, such as impurities in the product or inaccuracies in tracking reactants.Careful experimentation and precise measurement can help achieve more accurate percent yield values, leading to more reliable chemical processes in practical applications.
Reaction Efficiency
Evaluating a reaction's efficiency involves comparing the actual yield to the theoretical yield, resulting in the percent yield that we discussed previously. A reaction’s **efficiency** is indicated by how close the percent yield is to 100%. A higher percent yield signifies better efficiency.
Factors affecting efficiency often arise from practical issues such as unwanted side reactions and losses during the recovery of product. Efficiency also depends on reaction conditions. For instance, temperature, pressure, and catalyst presence can significantly alter how completely reactants convert into products.
To maximize reaction efficiency, chemists aim to:
  • Minimize side reactions by selecting specific reaction conditions.
  • Ensure all reactants are fully consumed, possibly by increasing reaction time or optimizing concentrations.
  • Improve techniques for recovering and purifying the product to avoid significant losses.
Overall, understanding and improving reaction efficiency is crucial for industrial processes where cost-effectiveness and resource conservation are key.

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Most popular questions from this chapter

The fizz produced when an Alka-Seltzer \({ }^{B}\) tablet is dissolved in water is due to the reaction between sodium bicarbonate \(\left(\mathrm{NaHCO}_{3}\right)\) and citric acid \(\left(\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}\right)\) $$ \begin{gathered} 3 \mathrm{NaHCO}_{3}(a q)+\mathrm{H}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \longrightarrow \\ 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Na}_{3} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}_{7}(a q) \end{gathered} $$ In a certain experiment \(1.00 \mathrm{~g}\) of sodium bicarbonate and \(1.00 \mathrm{~g}\) of citric acid are allowed to react. (a) Which is the limiting reactant? (b) How many grams of carbon dioxide form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed?

Balance the following equations, and indicate whether they are combination, decomposition, or combustion reactions: (a) \(\mathrm{Al}(s)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{AlCl}_{3}(s)\) (b) \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) (c) \(\mathrm{Li}(s)+\mathrm{N}_{2}(g) \longrightarrow \mathrm{Li}_{3} \mathrm{~N}(s)\) (d) \(\mathrm{PbCO}_{3}(s) \longrightarrow \mathrm{PbO}(s)+\mathrm{CO}_{2}(g)\) (e) \(\mathrm{C}_{7} \mathrm{H}_{8} \mathrm{O}_{2}(l)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\)

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of \(\mathrm{NH}_{3}\) to \(\mathrm{NO}\) : $$ 4 \mathrm{NH}_{3}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{NO}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) $$ In a certain experiment, \(1.50 \mathrm{~g}\) of \(\mathrm{NH}_{3}\) reacts with \(2.75 \mathrm{~g}\) of \(\mathrm{O}_{2}\) (a) Which is the limiting reactant? (b) How many grams of \(\mathrm{NO}\) and of \(\mathrm{H}_{2} \mathrm{O}\) form? (c) How many grams of the excess reactant remain after the limiting reactant is completely consumed? (d) Show that your calculations in parts (b) and (c) are consistent with the law of conservation of mass.

Determine the formula weights of each of the following compounds: (a) nitric acid, \(\mathrm{HNO}_{3} ;\) (b) \(\mathrm{KMnO}_{4}\); (c) \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\); (d) quartz, \(\mathrm{SiO}_{2} ;\) (e) gallium sulfide, (f) chromium(III) sulfate, (g) phosphorus trichloride.

(a) When the metallic element sodium combines with the nonmetallic element bromine, \(\mathrm{Br}_{2}(l)\), how can you determine the chemical formula of the product? How do you know whether the product is a solid, liquid, or gas at room temperature? Write the balanced chemical equation for the reaction. (b) When a hydrocarbon burns in air, what reactant besides the hydrocarbon is involved in the reaction? What products are formed? Write a balanced chemical equation for the combustion of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}(I)\), in air.

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