Chapter 3: Problem 62
Calcium hydride reacts with water to form calcium hydroxide and hydrogen gas. (a) Write a balanced chemical equation for the reaction. (b) How many grams of calcium hydride are needed to form \(8.500 \mathrm{~g}\) of hydrogen?
Short Answer
Expert verified
The balanced chemical equation for the reaction between calcium hydride and water is: CaH₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + 2H₂(g). To produce 8.500 g of hydrogen gas, 88.759 g of calcium hydride are needed.
Step by step solution
01
Write the balanced chemical equation
The first step is to write down the unbalanced chemical equation for the reaction between calcium hydride (CaH₂) and water (H₂O). This will help us understand the stoichiometry of the reaction and find the balanced chemical equation.
The unbalanced equation is:
CaH₂ + H₂O → Ca(OH)₂ + H₂
To balance the chemical equation, we need to ensure that the number of atoms of each element on the reactant side is equal to the number on the product side. After balancing the equation, we obtain:
CaH₂ + 2H₂O → Ca(OH)₂ + 2H₂
So, the balanced chemical equation is:
CaH₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + 2H₂(g)
02
Calculate the moles of hydrogen gas produced
We are given that 8.500 grams of hydrogen gas is produced in the reaction. To find out how many moles of hydrogen gas are produced, we need to use the molar mass of hydrogen gas (H₂). The molar mass of H₂ is 2.016 g/mol (since 1 mole of hydrogen has a mass of 1.008 g, and there are two hydrogen atoms in H₂).
Now, we can calculate the moles of hydrogen gas produced as follows:
moles of H₂ = (8.500 g) / (2.016 g/mol) = 4.220 moles of H₂
03
Use stoichiometry to find the moles of calcium hydride required
Now that we know the number of moles of hydrogen gas produced, we can use the stoichiometry given in the balanced chemical equation to find the number of moles of calcium hydride required for this reaction. From the balanced equation, we know that 1 mole of CaH₂ produces 2 moles of H₂. Therefore:
moles of CaH₂ = (4.220 moles of H₂) / 2 = 2.110 moles of CaH₂
04
Calculate the mass of calcium hydride required
Finally, we will convert moles of calcium hydride to grams using its molar mass. The molar mass of CaH₂ is 42.094 g/mol (40.078 g/mol for calcium, 1.008 g/mol for hydrogen, so 40.078 + 2*1.008).
mass of CaH₂ = (2.110 moles of CaH₂) * (42.094 g/mol) = 88.759 g
Therefore, 88.759 grams of calcium hydride are needed to form 8.500 grams of hydrogen gas.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Balanced Chemical Equation
A balanced chemical equation represents a chemical reaction with the same number of atoms for each element on both sides of the equation. This ensures that mass is conserved, following the law of conservation of mass. To balance an equation, we adjust the coefficients (the numbers in front of chemical formulas) until each element has the same number of atoms on both the reactants and products side.
In our example, calcium hydride (\(\text{CaH}_2\)) reacts with water (\(\text{H}_2\text{O}\)) to form calcium hydroxide (\(\text{Ca(OH)}_2\)) and hydrogen gas (\(\text{H}_2\)). The unbalanced equation initially looks like this:
In our example, calcium hydride (\(\text{CaH}_2\)) reacts with water (\(\text{H}_2\text{O}\)) to form calcium hydroxide (\(\text{Ca(OH)}_2\)) and hydrogen gas (\(\text{H}_2\)). The unbalanced equation initially looks like this:
- \(\text{CaH}_2 + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{H}_2\)
- Balanced equation: \(\text{CaH}_2 + 2\text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + 2\text{H}_2\)
Moles and Molar Mass
Moles and molar mass are crucial concepts in chemistry that help us understand the amount of a substance in a given sample. The mole is a unit of measurement used to discuss the amount of substance, where one mole contains exactly \(6.022 \times 10^{23}\) entities, be it atoms, molecules, or ions.
The molar mass is the mass of one mole of a substance. It is expressed in grams per mole (\(g/mol\)). For example, the molar mass of hydrogen gas (\(\text{H}_2\)) is about \(2.016\ g/mol\), calculated by doubling the atomic mass of a hydrogen atom, as each molecule consists of two hydrogen atoms.
To convert grams of a substance to moles, we divide the mass of the substance by its molar mass. Using the example, when given \(8.500\ g\) of \(\text{H}_2\), the number of moles can be calculated using its molar mass:
The molar mass is the mass of one mole of a substance. It is expressed in grams per mole (\(g/mol\)). For example, the molar mass of hydrogen gas (\(\text{H}_2\)) is about \(2.016\ g/mol\), calculated by doubling the atomic mass of a hydrogen atom, as each molecule consists of two hydrogen atoms.
To convert grams of a substance to moles, we divide the mass of the substance by its molar mass. Using the example, when given \(8.500\ g\) of \(\text{H}_2\), the number of moles can be calculated using its molar mass:
- \( \text{Moles of } \text{H}_2 = \frac{8.500 \text{ g}}{2.016 \text{ g/mol}} = 4.220 \text{ moles} \)
Stoichiometry
Stoichiometry is the branch of chemistry that deals with the relative quantities of reactants and products in chemical reactions. It relies heavily on the balanced chemical equation to provide a quantitative relationship between the different substances involved.
In the given reaction, the stoichiometry from the balanced equation indicates that 1 mole of calcium hydride generates 2 moles of hydrogen gas. Thus, if we know the number of moles of hydrogen gas produced, we can determine the number of moles of calcium hydride required.
For instance:
In the given reaction, the stoichiometry from the balanced equation indicates that 1 mole of calcium hydride generates 2 moles of hydrogen gas. Thus, if we know the number of moles of hydrogen gas produced, we can determine the number of moles of calcium hydride required.
For instance:
- We calculated that \(4.220\) moles of \(\text{H}_2\) are produced.
- According to stoichiometry, \(1\) mole of \(\text{CaH}_2\) forms \(2\) moles of \(\text{H}_2\).
- Thus, the required moles of \(\text{CaH}_2\) are \(\frac{4.220}{2} = 2.110\ moles\).
Chemical Reactions
Chemical reactions describe how substances transform into new substances with different properties. These reactions involve the breaking and forming of chemical bonds. In this exercise, calcium hydride reacts with water, resulting in the formation of calcium hydroxide and hydrogen gas.
To understand chemical reactions, it is important to know the reactants (starting materials) and the products (resulting substances). In our case:
This example also illustrates a basic type of chemical reaction — a displacement reaction, where an element in one compound is replaced by another element, forming a new compound as a result.
To understand chemical reactions, it is important to know the reactants (starting materials) and the products (resulting substances). In our case:
- Reactants: Calcium hydride (\(\text{CaH}_2\)) and water (\(\text{H}_2\text{O}\))
- Products: Calcium hydroxide (\(\text{Ca(OH)}_2\)) and hydrogen gas (\(\text{H}_2\))
This example also illustrates a basic type of chemical reaction — a displacement reaction, where an element in one compound is replaced by another element, forming a new compound as a result.