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Some metal complexes have a coordination number of \(5 .\) One such complex is \(\mathrm{Fe}(\mathrm{CO})_{5}\), which adopts a trigonal bipyramidal geometry (see Figure 9.8). (a) Write the name for \(\mathrm{Fe}(\mathrm{CO})_{5}\), using the nomenclature rules for coordination compounds. (b) What is the oxidation state of Fe in this compound? (c) Suppose one of the CO ligands is replaced with a CN \(^{-}\) ligand, forming \(\left[\mathrm{Fe}(\mathrm{CO})_{4}(\mathrm{CN})\right]^{-}\). How many geometric isomers would you predict this complex could have?

Short Answer

Expert verified
The complex Fe(CO)5 is named as pentacarbonyliron. In this complex, the oxidation state of Fe is 0. The complex [Fe(CO)4(CN)]− can have 2 geometric isomers, with the CN- ligand occupying either an equatorial or axial position in the trigonal bipyramidal geometry.

Step by step solution

01

(a) Writing the name for Fe(CO)5

To name the Fe(CO)5 complex, we first need to name the metal (Fe) and the ligands (CO). CO is a neutral, monodentate ligand and is called carbonyl. The metal is iron. Since there is no charge on the complex, iron will be in its neutral state. Now, we can name the complex: pentacarbonyliron
02

(b) Oxidation state of Fe

To determine the oxidation state of Fe, we assume a charge on the metal and balance it with the charges on the ligands. Since carbonyl is neutral ligand (having a zero charge), the overall charge on the metal should be zero for a neutral complex. So, Fe has an oxidation state of 0 in Fe(CO)5.
03

(c) Geometric isomers for [Fe(CO)4(CN)]−

The [Fe(CO)4(CN)]− complex has 5 ligands around Fe, so it will adopt a trigonal bipyramidal geometry. When the CN- ligand replaces one of the CO ligands, it could take one of two positions: either an equatorial position or an axial position. If the CN- ligand occupies an equatorial position, there will be one geometric isomer. If the CN- ligand occupies an axial position, there will be a different geometric isomer. Thus, we predict that the [Fe(CO)4(CN)]− complex can have 2 geometric isomers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Number
In coordination chemistry, the coordination number refers to the number of ligand atoms that are directly bonded to the central metal atom or ion within a coordination complex. It essentially gives us the count of interactions around the metal center. For instance, in the case of the metal complex \( ext{Fe(CO)}_5\), the coordination number is 5. This means five carbon monoxide ligands, each with one lone pair, are attached to the iron atom, forming a stable structure.
Understanding the coordination number helps in predicting the geometry and reactivity of coordination compounds. Different metals and ligands can lead to varying coordination numbers, often influenced by factors such as the size of the central metal ion and the electronic properties of the ligands.
Trigonal Bipyramidal Geometry
Trigonal bipyramidal geometry is a specific shape that occurs when a metal complex has a coordination number of 5. This geometry is characterized by having three atoms or ligands in a plane (equatorial positions) and two more above and below this plane (axial positions).
In the example of \( ext{Fe(CO)}_5\), this geometry allows for optimal spatial arrangement and minimizes steric hindrance between the carbonyl ligands.
  • Three ligands are positioned equatorially around the central iron atom.
  • Two ligands are positioned axially, at opposite ends of the iron atom.
Such an arrangement contributes to the stability and unique properties of the complex, influencing how it interacts with other molecules or ions.
Coordination Compounds Nomenclature
Naming coordination compounds involves systematic rules established by the IUPAC. It starts by naming the ligands attached to the central metal first, followed by the name of the metal itself.
In the case of \( ext{Fe(CO)}_5\), which is a neutral complex, the name is constructed as 'pentacarbonyliron'. Here is how it's broken down:
  • 'penta' indicates five ligands are present.
  • 'carbonyl' refers to the CO ligands.
  • 'iron' is the name of the central metal atom.
For anionic ligands, suffixes such as '-o' are added, and the metal name sometimes changes if the entire complex carries a negative charge. Understanding these rules is crucial for writing and interpreting the names of complex compounds effectively.
Oxidation State
The oxidation state of a metal in a coordination complex is determined by the overall charge of the complex and the charges on the ligands. For example, in \( ext{Fe(CO)}_5\), the complex is neutral, and CO is a neutral ligand.
Therefore, the oxidation state of iron in this particular complex is 0. By assigning this zero charge, it suggests that iron neither loses nor gains electrons when forming its bonds with CO.
Understanding the oxidation state helps in deducing the electron configuration of the metal and the type of bonding in the complex, ultimately affecting its chemical behavior and reactivity.
Geometric Isomers
Geometric isomers are different arrangements of ligands around a central metal atom that result in distinct spatial orientations, even though the components of the complex remain unchanged.
For a complex like \([ ext{Fe(CO)}_4( ext{CN})]^−\), which has a trigonal bipyramidal geometry, two distinct geometric isomers are possible.
  • If the CN ligand takes an equatorial position, one geometric isomer forms.
  • If the CN ligand takes an axial position, a second isomer arises.
These variations affect the physical and chemical properties of the compound. Recognizing geometric isomers is essential for understanding the reactivity and potential applications of coordination compounds in various fields, such as catalysis and material science.

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Most popular questions from this chapter

Write balanced chemical equations to represent the following observations. (In some instances the complex involved has been discussed previously in the text.) (a) Solid silver chloride dissolves in an excess of aqueous ammonia. (b) The green complex \(\left[\mathrm{Cr}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right] \mathrm{Cl}\), on treatment with water over a long time, converts to a brown-orange complex. Reaction of \(\mathrm{AgNO}_{3}\) with a solution of the product precipitates \(3 \mathrm{~mol}\) of \(\mathrm{AgCl}\) per mole of Cr present. (Write two chemical equations.) (c) When an \(\mathrm{NaOH}\) solution is added to a solution of \(\mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}, \mathrm{a}\) precipitate forms. Addition of excess \(\mathrm{NaOH}\) solution causes the precipitate to dissolve. (Write two chemical equations.) (d) A pink solution of \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\) turns deep blue on addition of concentrated hydrochloric acid.

The complex \(\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) contains five unpaired electrons. Sketch the energy-level diagram for the \(d\) orbitals, and indicate the placement of electrons for this complex ion. Is the ion a high-spin or a low-spin complex?

(a) Draw the two linkage isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SCN}\right]^{2+}\). (b) Draw the two geometric isomers of \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]^{2+}\). (c) Two compounds with the formula \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{ClBr}\) can be prepared. Use structural formulas to show how they differ. What kind of isomerism does this illustrate?

The molecule methylamine \(\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)\) can act as a monodentate ligand. The following are equilibrium reactions and the thermochemical data at \(298 \mathrm{~K}\) for reactions of methylamine and en with \(\mathrm{Cd}^{2+}(a q)\) : \(\mathrm{Cd}^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) \rightleftharpoons\left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q)\) \(\Delta H^{\circ}=-57.3 \mathrm{~kJ} ; \quad \Delta S^{\circ}=-67.3 \mathrm{~J} / \mathrm{K} ; \quad \Delta G^{\circ}=-37.2 \mathrm{~kJ}\) $$ \mathrm{Cd}^{2+}(a q)+2 \mathrm{en}(a q) \rightleftharpoons\left[\mathrm{Cd}(\mathrm{en})_{2}\right]^{2+}(a q) $$ \(\Delta H^{\circ}=-56.5 \mathrm{~kJ} ; \quad \Delta S^{\circ}=+14.1 \mathrm{~J} / \mathrm{K} ; \quad \Delta G^{\circ}=-60.7 \mathrm{~kJ}\) (a) Calculate \(\Delta G^{\circ}\) and the equilibrium constant \(K\) for the following ligand exchange reaction: \(\left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q)+2 \mathrm{en}(a q) \rightleftharpoons\) $$ \left[\mathrm{Cd}(\mathrm{en})_{2}\right]^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) $$ (b) Based on the value of \(K\) in part (a), what would you conclude about this reaction? What concept is demonstrated? (c) Determine the magnitudes of the enthalpic \(\left(\Delta H^{\circ}\right)\) and the entropic \(\left(-T \Delta S^{\circ}\right)\) contributions to \(\Delta G^{\circ}\) for the ligand exchange reaction. Explain the relative magnitudes. (d) Based on information in this exercise and in the "A Closer Look" box on the chelate effect, predict the sign of \(\Delta H^{\circ}\) for the following hypothetical reaction: \(\left[\mathrm{Cd}\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)_{4}\right]^{2+}(a q)+4 \mathrm{NH}_{3}(a q) \rightleftharpoons\) $$ \left[\mathrm{Cd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}(a q)+4 \mathrm{CH}_{3} \mathrm{NH}_{2}(a q) $$

When Alfred Werner was developing the field of coordination chemistry, it was argued by some that the optical activity he observed in the chiral complexes he had prepared was because of the presence of carbon atoms in the molecule. To disprove this argument, Werner synthesized a chiral complex of cobalt that had no carbon atoms in it, and he was able to resolve it into its enantiomers. Design a cobalt(III) complex that would be chiral if it could be synthesized and that contains no carbon atoms. (It may not be possible to synthesize the complex you design, but we won't worry about that for now.)

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