Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For each of the following metals, write the electronic configuration of the atom and its \(3+\) ion: (a) Ru, (b) Mo, (c) Co. Draw the crystal-field energy-level diagram for the \(d\) orbitals of an octahedral complex, and show the placement of the \(d\) electrons for each \(3+\) ion, assuming a weak-field complex. How many unpaired electrons are there in each case?

Short Answer

Expert verified
The electronic configurations of the given transition metals and their 3+ ions are: - Ru: \([Kr] 4d^7 5s^1\), Ru³⁺: \([Kr] 4d^4\) - Mo: \([Kr] 4d^5 5s^1\), Mo³⁺: \([Kr] 4d^3\) - Co: \([Ar] 3d^7 4s^2\), Co³⁺: \([Ar] 3d^6\) For an octahedral weak-field complex, the d electrons have the following placements: - Ru³⁺: \(\uparrow \downarrow\) in first and second \(t_{2g}\) orbitals, empty in others. - Mo³⁺: \(\uparrow \downarrow\) in first \(t_{2g}\) orbital, \(\uparrow\) in second \(t_{2g}\) orbital, empty in others. - Co³⁺: \(\uparrow \downarrow\) in all \(t_{2g}\) orbitals and one \(e_g\) orbital. The number of unpaired electrons for each 3+ ion is: - Ru³⁺: 0 - Mo³⁺: 1 - Co³⁺: 2

Step by step solution

01

Electronic configuration of the given transition metals

We will use the periodic table to find the atomic numbers of each transition metal and write their electronic configurations. Ruthenium (Ru): - Atomic number: 44 - Electronic configuration: \([Kr] 4d^7 5s^1\) Molybdenum (Mo): - Atomic number: 42 - Electronic configuration: \([Kr] 4d^5 5s^1\) Cobalt (Co): - Atomic number: 27 - Electronic configuration: \([Ar] 3d^7 4s^2\)
02

Electronic configuration of the 3+ ions

Now let's find the electronic configurations for the 3+ ions. Three electrons are removed from the highest n and l value orbitals. Ruthenium 3+ (Ru³⁺): - Electronic configuration: \([Kr] 4d^4\) Molybdenum 3+ (Mo³⁺): - Electronic configuration: \([Kr] 4d^3\) Cobalt 3+ (Co³⁺): - Electronic configuration: \([Ar] 3d^6\)
03

Draw the crystal-field energy-level diagram for an octahedral complex

In an octahedral complex, the d orbitals are split into two sets: \(t_{2g}\) (lower energy) and \(e_g\) (higher energy). They are separated by an energy gap called Δ. Since we are considering weak-field complexes, the Δ is small, and the electrons will fill the orbitals according to the Aufbau's principle. The energy-level diagram for an octahedral complex is: ``` e_g ----- Δ ----- t_{2g} ```
04

Show the placement of the d electrons for each 3+ ion

We will fill the electrons in the energy-level diagram according to the Aufbau's principle and Hund's rule. Here, \(t_{2g}\) has three d orbitals while \(e_g\) has two d orbitals. Ruthenium 3+ (Ru³⁺): - 4 d electrons: \(\uparrow \downarrow\) in first \(t_{2g}\) orbital, \(\uparrow \downarrow\) in second \(t_{2g}\) orbital, and empty in others. Molybdenum 3+ (Mo³⁺): - 3 d electrons: \(\uparrow \downarrow\) in first \(t_{2g}\) orbital, \(\uparrow\) in second \(t_{2g}\) orbital, and empty in others. Cobalt 3+ (Co³⁺): - 6 d electrons: \(\uparrow \downarrow\) in all \(t_{2g}\) orbitals and \(\uparrow \downarrow\) in one \(e_g\) orbital.
05

Determine the number of unpaired electrons in each case

Now we will count the number of unpaired electrons from the energy-level diagrams that we obtained in step 4. Ruthenium 3+ (Ru³⁺): - Number of unpaired electrons: 0 Molybdenum 3+ (Mo³⁺): - Number of unpaired electrons: 1 Cobalt 3+ (Co³⁺): - Number of unpaired electrons: 2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Crystal-Field Theory
Crystal-field theory (CFT) is a model that describes how the arrangement of ligands around a central metal ion within a complex influences the energies of its d-orbitals. It is particularly useful in understanding the electronic structures and properties of transition metal complexes.

In an octahedral complex, which consists of six ligands symmetrically arranged around the central metal ion, the d-orbitals split into two distinct energy levels due to the electrostatic interactions between the d-orbitals of the metal ion and the negative charges on the ligands. The lower energy set is denoted as \(t_{2g}\) and consists of three orbitals (\(d_{xy}\), \(d_{xz}\), and \(d_{yz}\)), while the higher energy set is called \(e_g\) and contains two orbitals (\(d_{z^2}\) and \(d_{x^2-y^2}\)).

The extent of this splitting, designated as \(\Delta\), varies based on the field strength of the ligands. Ligands that cause a large splitting are known as strong-field ligands, and those that cause a smaller splitting are referred to as weak-field ligands. In weak-field complexes, the gap \(\Delta\) is relatively small, allowing electrons to occupy the higher energy \(e_g\) orbitals as per the Aufbau principle, which states that electrons fill orbitals starting with the lowest energy first.
Octahedral Complex Ions Formation
Octahedral complex ions are a common type of coordination complexes where a central metal ion is surrounded by six ligands at the vertices of an octahedron. The electronic configuration of transition metal ions plays a pivotal role in the formation and characteristics of these complexes.

When transitioning from the electronic configuration of a metal atom to that of a \(3+\) ion, electrons are typically removed from the s-orbitals before the d-orbitals due to their higher energy. After the removal of electrons to form a \(3+\) ion, the configuration is solely based on the d-orbitals. In the provided examples: Ruthenium (Ru) forms Ru\(3+\) with a \([Kr] 4d^4\) configuration, Molybdenum (Mo) forms Mo\(3+\) with a \([Kr] 4d^3\) configuration, and Cobalt (Co) forms Co\(3+\) with a \([Ar] 3d^6\) configuration.

These configurations are the starting point for understanding how the d-electrons will fill the \(t_{2g}\) and \(e_g\) orbitals in an octahedral crystal-field. The weak-field assumption means that the electrons will first fill the \(t_{2g}\) orbitals before pairing up or moving to the \(e_g\) level.
Determining Unpaired Electrons
Unpaired electrons are electrons in an atom or ion that are not paired with another electron in the same orbital. These unpaired electrons are significant in understanding the magnetic properties of the compound and are often determined using Hund's Rule and the principles of crystal-field theory.

According to Hund's Rule, orbitals are singly occupied as far as possible before electrons start to pair up. For transition metals and their ions, particularly those forming weak-field octahedral complexes, electrons will enter into the lower energy \(t_{2g}\) orbitals first. Once these are fully or half-filled, electrons may then occupy the higher energy \(e_g\) orbitals.

Taking the 3+ ions in the given exercise: Ruthenium (Ru\(3+\)) with a \([Kr] 4d^4\) configuration will have all electrons paired and no unpaired electrons. Molybdenum (Mo\(3+\)) with a \([Kr] 4d^3\) configuration will have one unpaired electron. Similarly, Cobalt (Co\(3+\)) with a \([Ar] 3d^6\) configuration will have two unpaired electrons. Understanding the placement of these unpaired electrons within the energy-level diagram is crucial for predicting the magnetic and spectral properties of these complexes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A certain complex of metal \(\mathrm{M}\) is formulated as \(\mathrm{MCl}_{3} \cdot 3 \mathrm{H}_{2} \mathrm{O}\). The coordination number of the complex is not known but is expected to be 4 or 6 . (a) Would conductivity measurements provide information about the coordination number? (b) In using conductivity measurements to test which ligands are bound to the metal ion, what assumption is made about the rate at which ligands enteror leave the coordination sphere of the metal?

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) hexaamminechromium(III) nitrate (b) tetraamminecarbonatocobalt(III) sulfate (c) dichlorobis(ethylenediamine)platinum(IV) bromide (d) potassium diaquatetrabromovanadate(III) (e) bis(ethylenediamine) zinc(II) tetraiodomercurate(II)

A palladium complex formed from a solution containing bromide ion and pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\) (a good electronpair donor), is found on elemental analysis to contain \(37.6 \%\) bromine, \(28.3 \%\) carbon, \(6.60 \%\) nitrogen, and \(2.37 \%\) hydrogen by mass. The compound is slightly soluble in several organic solvents; its solutions in water or alcohol do not conduct electricity. It is found experimentally to have a zero dipole moment. Write the chemical formula, and indicate its probable structure.

Pyridine \(\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\right)\), abbreviated py, is the following molecule: (a) Why is pyridine referred to as a monodentate ligand? (b) Consider the following equilibrium reaction: \(\left[\mathrm{Ru}(\mathrm{py})_{4}(\mathrm{bipy})\right]^{2+}+2 \mathrm{py} \rightleftharpoons\left[\mathrm{Ru}(\mathrm{py})_{6}\right]^{2+}+\mathrm{bipy}\) What would you predict for the magnitude of the equilibrium constant for this equilibrium? Explain the basis for your answer.

Give the number of \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{TiCl}_{6}\right]\), (b) \(\mathrm{Na}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right]\) (c) \(\left[\operatorname{Ru}(\mathrm{en})_{3}\right] \mathrm{Br}_{3}\) (d) \([\mathrm{Mo}(\mathrm{EDTA})] \mathrm{ClO}_{4},(\mathrm{e}) \mathrm{K}_{3}\left[\mathrm{ReCl}_{6}\right]\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free