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Consider an octahedral complex \(\mathrm{MA}_{3} \mathrm{~B}_{3}\). How many geometric isomers are expected for this compound? Will any of the isomers be optically active? If so, which ones?

Short Answer

Expert verified
The octahedral complex MA3B3 has two geometric isomers, a facial (fac) isomer and a meridional (mer) isomer. However, both isomers are optically inactive as they possess a mirror plane of symmetry between the ligands A and B.

Step by step solution

01

Identify ligands and their arrangement around the metal center

In an octahedral complex, there are six coordinate positions for ligands in which three positions are occupied by A-type ligands (A) and three positions are occupied by B-type ligands (B). The metal center (M) can be located at the center of the octahedron.
02

Generate possible isomers for the complex

Two major geometric isomer types can be formed from an octahedral complex with MA3B3 composition: a facial (fac) isomer and a meridional (mer) isomer. To generate these isomers, we can systematically place ligands A and B around the metal center, maintaining the number of A ligands (3) and B ligands (3) in every structure. 1. Facial (fac) isomer: the A ligands and the B ligands each occupy one face of the octahedron. 2. Meridional (mer) isomer: the A ligands and the B ligands are positioned in a pairwise manner along the corners of the octahedron (an alternative interpretation of the mer arrangement is that the A ligands form a "tripod" by being placed on three alternating positions at a 90° angle from each other in the x, y, and z axis, the B ligands are placed in the empty sites in between the A ligands).
03

Determine optical activity of isomers

To determine if any of the isomers are optically active, we need to analyze the symmetry of the structures. Optically active compounds are enantiomers (chiral molecules) and have non-superimposable mirror images. In contrast, optically inactive compounds have superimposable mirror images (achiral molecules). 1. Facial (fac) isomer: This isomer has a mirror plane of symmetry between the A and B ligands, and thus isomers of the fac type are optically inactive. 2. Meridional (mer) isomer: This isomer also has a mirror plane of symmetry between the A and B ligands, and therefore isomers of the mer type are optically inactive as well.
04

Summarize the findings

The octahedral complex MA3B3 has two geometric isomers: a facial (fac) isomer and a meridional (mer) isomer. Both of these isomers are optically inactive due to the presence of a mirror plane of symmetry between the ligands A and B.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Octahedral Complexes
In coordination chemistry, an octahedral complex is formed when a central metal atom or ion is surrounded by six ligands. Ligands are molecules or ions that donate a pair of electrons to the metal, creating a coordination bond. The arrangement is highly symmetrical, resembling an octahedron shape.

For the chemical formula \(\text{MA}_3\text{B}_3\), we have six ligand positions, occupied by two types of ligands: A and B. The three ligand A's and three ligand B's can occupy these positions differently, forming different isomers.

Understanding how these ligands arrange themselves around the metal center is crucial for predicting and explaining the chemical behavior and properties of the complex. This arrangement influences the complex's color, reactivity, and magnetism. Making it clear why octahedral geometry is one of the most common and important in coordination chemistry.
Optical Activity in Chemistry
Optical activity refers to a molecule's ability to rotate the plane of polarized light. This characteristic is crucial for understanding many natural and synthetic compounds, especially in the field of stereochemistry.

A compound is optically active when it is chiral, meaning it has two non-superimposable mirror images called enantiomers. To determine if a complex is optically active, we check for symmetry.
If a compound has a plane of symmetry, it becomes achiral, meaning both its mirror images can be superimposed, making it optically inactive.

In the case of \(\text{MA}_3\text{B}_3\) octahedral complexes, both facial and meridional isomers possess a mirror plane due to the symmetrical arrangement of ligands. Thus, these isomers cannot rotate plane-polarized light and are optically inactive.
Facial and Meridional Isomers
In octahedral complexes like \(\text{MA}_3\text{B}_3\), the two primary geometric isomers are known as facial (fac) and meridional (mer) isomers. Each type has a distinct ligand arrangement that influences its properties and behavior.

- **Facial Isomer (fac)**: In this configuration, all three A ligands and all three B ligands occupy adjacent sites on one face of the octahedron. This arrangement forms a triangular face of ligands, like a triangle perched on one side of a die.
- **Meridional Isomer (mer)**: Here, the A and B ligands alternate around the octahedron, forming a "meridian" circle, connecting three alternating positions like the corners of a tripod. This arrangement is more diagonal and spread across different faces.

Both fac and mer isomers have significant mirror planes resulting in them being non-chiral and thus optically inactive.

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Most popular questions from this chapter

Write the formula for each of the following compounds, being sure to use brackets to indicate the coordination sphere: (a) tetraaquadibromomanganese(III) perchlorate (b) bis(bipyridyl) cadmium(II) chloride (c) potassium tetrabromo(ortho-phenanthroline)cobaltate (III) (d) cesium diamminetetracyanochromate(III) (e) tris(ethylenediammine)rhodium(III) tris(oxalato)cobaltate(III)

One of the more famous species in coordination chemistry is the Creutz-Taube complex, It is named for the two scientists who discovered it and initially studied its properties. The central ligand is pyrazine, a planar six-membered ring with nitrogens at opposite sides. (a) How can you account for the fact that the complex, which has only neutral ligands, has an odd overall charge? (b) The metal is in a low-spin configuration in both cases. Assuming octahedral coordination, draw the \(d\) -orbital energy-level diagram for each metal. (c) In many experiments the two metal ions appear to be in exactly equivalent states. Can you think of a reason that this might appear to be so, recognizing that electrons move very rapidly compared to nuclei?

(a) Sketch a diagram that shows the definition of the crystal-field splitting energy \((\Delta)\) for an octahedral crystal field. (b) What is the relationship between the magnitude of \(\Delta\) and the energy of the \(d-d\) transition for a \(d^{1}\) complex? (c) Calculate \(\Delta\) in \(\mathrm{kJ} / \mathrm{mol}\) if a \(d^{1}\) complex has an absorption maximum at \(590 \mathrm{~nm}\).

The complex \(\left[\mathrm{Mn}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}\) contains five unpaired electrons. Sketch the energy-level diagram for the \(d\) orbitals, and indicate the placement of electrons for this complex ion. Is the ion a high-spin or a low-spin complex?

In 2001 , chemists at SUNY-Stony Brook succeeded in synthesizing the complex trans-[Fe(CN) \(\left._{4}(\mathrm{CO})_{2}\right]^{2-}\), which could be a model of complexes that may have played a role in the origin of life. (a) Sketch the structure of the complex. (b) The complex is isolated as a sodium salt. Write the complete name of this salt. (c) What is the oxidation state of Fe in this complex? How many \(d\) electrons are associated with the Fe in this complex? (d) Would you expect this complex to be high spin or low spin? Explain.

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