Question

A four-coordinate complex \(\mathrm{MA}_{2} \mathrm{~B}_{2}\) is prepared and found to have two different isomers. Is it possible to determine from this information whether the complex is square planar or tetrahedral? If so, which is it?

Short answer

Based on the given information, the complex MA₂B₂ is square planar. This is because square planar complexes have two possible isomers (cis and trans), while tetrahedral complexes have only one arrangement. In this case, the two isomers for the square planar complex would be M(ABAB) and M(AABB).

Step-by-step solution

Understand the square planar structure

A square planar complex has a central metal atom surrounded by four ligands in a planar arrangement, with angles of 90 degrees between the ligands. In the case of the given complex MA₂B₂, the possible arrangements are either M(ABAB) or M(AABB).

Understand the tetrahedral structure

A tetrahedral complex has a central metal atom surrounded by four ligands, with angles of 109.5 degrees between the ligands. In the case of MA₂B₂, there is only one possible arrangement: M(ABAB).

Analyze isomers in both geometries

In the square planar geometry, we have two possible isomers: M(ABAB) with the A and B ligands being adjacent (cis), and M(AABB) with A and B ligands being opposite each other (trans). In the tetrahedral geometry, there is only one possible arrangement: M(ABAB).

Determine the geometry of the complex

Since we are given that the complex has exactly two different isomers, it suggests that the MA₂B₂ complex must be square planar, as the tetrahedral geometry only has one arrangement. Thus, the complex is square planar with two possible isomers: cis (M(ABAB)) and trans (M(AABB)).