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(a) Under what circumstances is the Nernst equation applicable? (b) What is the numerical value of the reaction quotient, \(Q\), under standard conditions? (c) What happens to the emf of a cell if the concentrations of the reactants are increased?

Short Answer

Expert verified
The Nernst equation is applicable when there is a redox reaction at the electrodes and the reaction is at equilibrium or close to it, and the temperature is constant. Under standard conditions, the numerical value of the reaction quotient, \(Q\), is 1. When the concentrations of the reactants are increased, the emf of the cell will decrease.

Step by step solution

01

Understanding the Nernst Equation and its Applicability

The Nernst equation is used to calculate the emf (electromotive force) of an electrochemical cell under non-standard conditions. It takes into account the concentrations or activities of the reactants and products involved in the electrochemical process. The Nernst equation is applicable when there is a redox reaction at the electrodes and the reaction is at equilibrium or close to it. Additionally, the temperature should be constant during the reaction.
02

Determining the Reaction Quotient, \(Q\), under Standard Conditions

The reaction quotient, \(Q\), is a dimensionless number that describes the ratio of the concentrations of the products to the concentrations of the reactants in a reversible chemical reaction at a given point in time. Standard conditions refer to 25°C (298.15 K) temperature, 1 atm pressure, and all species present at 1 M concentration. Under standard conditions, since all species have an equal concentration of 1 M, the concentration terms in the reaction quotient will cancel out, leaving: \[Q = \frac{[C]^c [D]^d}{[A]^a [B]^b}\] \[Q = \frac{[1]^c [1]^d}{[1]^a [1]^b}\] Therefore, under standard conditions, Q = 1.
03

Effect of Increasing Reactant Concentrations on the emf of a Cell

According to the Nernst equation, the emf of a cell (\(E_{cell}\)) is given by: \[E_{cell} = E_{cell}^0 - \frac{RT}{nF} \ln Q\] Where \(E_{cell}^0\) is the standard cell potential, R is the gas constant, T is the temperature, n is the number of electrons transferred in the redox reaction, F is the Faraday constant, and Q is the reaction quotient. When the reactant concentrations are increased, the value of the reaction quotient, \(Q\) will decrease because the concentration of the products remains unchanged. Since the term \(-\frac{RT}{nF} \ln Q\) contributes negatively to the Nernst equation, a decrease in Q will cause an increase in the magnitude of the negative term and, therefore, a decrease in the emf of the cell. In conclusion, when the concentrations of the reactants of an electrochemical cell are increased, the emf of the cell will decrease.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Quotient
The reaction quotient, denoted by \( Q \), is a crucial part of understanding chemical reactions at any point. It signifies the ratio of the concentrations (or partial pressures) of the products raised to their respective stoichiometric coefficients, divided by the reactants raised to their coefficients. This is generally represented as:\[ Q = \frac{[C]^c [D]^d}{[A]^a [B]^b} \]In the context of electrochemical cells, \( Q \) helps in assessing the cell potential under different conditions using the Nernst equation. When the reaction is at standard conditions, which we'll discuss in the next section, the concentrations of the reactants and products are typically equal, making \( Q = 1 \).
Understanding the value of \( Q \) helps predict the direction in which a reaction will naturally proceed towards equilibrium.
Standard Conditions
Standard conditions are specific reference points that allow chemists to compare different reactions under the same baseline. These conditions include:
  • Temperature of 25°C or 298.15 K.
  • Pressure of 1 atm.
  • Concentrations of all solutes at 1 M.
When an electrochemical reaction is under standard conditions, like those mentioned above, it simplifies calculations because the reaction quotient \( Q \) equals 1, thus having no logarithmic impact in the Nernst equation: \[ E_{cell} = E_{cell}^0 - \frac{RT}{nF} \ln Q \]Under these standard sets, you can focus on other variables that might affect the cell's performance without worrying about concentration impacts.
Electrochemical Cell
An electrochemical cell is a device that generates electrical energy from chemical reactions—either through spontaneous reactions in galvanic cells or by inputting energy to drive non-spontaneous reactions in electrolytic cells.
A basic electrochemical cell consists of two electrodes, the anode (where oxidation occurs) and the cathode (where reduction takes place), submerged in separate solutions that facilitate ion transfer.
The role of an electrochemical cell is crucial in industries for galvanization and energy generation. For students, understanding this cell is critical when applying the Nernst equation to calculate the cell's electromotive force (emf) during reactions.
Cell EMF
Electromotive force, abbreviated as emf, refers to the potential difference that drives the flow of electrons from the anode to the cathode in an electrochemical cell. It’s measured in volts and can be calculated using:\[ E_{cell} = E_{cell}^0 - \frac{RT}{nF} \ln Q \]This formula emphasizes how the emf is impacted by the standard cell potential \( E_{cell}^0 \), temperature \( T \), and the reaction quotient \( Q \). Under standard conditions, \( Q \) equals 1, hence the emf aligns closely with the standard cell potential.
A higher emf indicates a stronger driving force for the electron flow, critical for the efficiency of batteries and electrochemical sensors.
Redox Reaction
Redox reactions, short for reduction-oxidation reactions, entail the transfer of electrons between chemical species. The overarching principle is that one species loses electrons (oxidation) while another gains electrons (reduction).
These reactions are pivotal in the operation of electrochemical cells. For instance, your flashlight batteries rely on redox reactions to generate electronic power.
In the context of the Nernst equation, recognizing which redox reactions occur at the electrodes, and how they impact the reaction quotient \( Q \), helps in attaining accurate calculations for the cell emf and understanding how changes in conditions affect the reaction dynamics.

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Most popular questions from this chapter

The \(K_{\infty}\) value for \(\mathrm{PbS}(s)\) is \(8.0 \times 10^{-28} .\) By using this value together with an electrode potential from Appendix \(\mathrm{E}\), determine the value of the standard reduction potential for the reaction $$ \mathrm{PbS}(s)+2 \mathrm{e}^{-}-\cdots \mathrm{Pb}(s)+\mathrm{S}^{2-}(a q) $$

A voltaic cell is constructed that uses the following halfcell reactions: $$ \begin{aligned} \mathrm{Cu}^{+}(a q)+\mathrm{e}^{-} & \longrightarrow \mathrm{Cu}(s) \\ \mathrm{I}_{2}(s)+2 \mathrm{e}^{-} \longrightarrow 2 \mathrm{I}^{-}(a q) \end{aligned} $$ The cell is operated at \(298 \mathrm{~K}\) with \(\left[\mathrm{Cu}^{+}\right]=0.25 \mathrm{M}\) and \(\left[\mathrm{I}^{-}\right]=3.5\) M. (a) Determine \(E\) for the cell at these concentrations. (b) Which electrode is the anode of the cell? (c) Is the answer to part (b) the same as it would be if the cell were operated under standard conditions? (d) If \(\left[\mathrm{Cu}^{+}\right]\) was equal to \(0.15 \mathrm{M}\), at \(\mathrm{what}\) concentration of \(\mathrm{I}^{-}\) would the cell have zero potential?

A voltaic cell is constructed with two silver-silver chloride electrodes, each of which is based on the following half-reaction: $$ \mathrm{AgCl}(s)+\mathrm{e}^{-\longrightarrow} \mathrm{Ag}(s)+\mathrm{Cl}^{-}(a q) $$ The two cell compartments have \(\left[\mathrm{Cl}^{-}\right]=0.0150 \mathrm{M}\) and \(\left[\mathrm{Cl}^{-}\right]=2.55 M\), respectively. (a) Which electrode is the cathode of the cell? (b) What is the standard emf of the cell? (c) What is the cell emf for the concentrations given? (d) For each electrode, predict whether [Cl \(^{-}\) ] will increase, decrease, or stay the same as the cell operates.

A \(1 M\) solution of \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) is placed in a beaker with a strip of Cu metal. A \(1 M\) solution of \(\mathrm{SnSO}_{4}\) is placed in a second beaker with a strip of Sn metal. A salt bridge connects the two beakers, and wires to a voltmeter link the two metal electrodes. (a) Which electrode serves as the anode, and which as the cathode? (b) Which electrode gains mass and which loses mass as the cell reaction proceeds? (c) Write the equation for the overall cell reaction. (d) What is the emf generated by the cell under standard conditions?

A plumber's handbook states that you should not connect a copper pipe directly to a steel pipe because electrochemical reactions between the two metals will cause corrosion. The handbook recommends you use, instead, an insulating fitting to connect them. What spontaneous redox reaction(s) might cause the corrosion? Justify your answer with standard emf calculations.

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