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(a) What does the term electromotive force mean? (b) What is the definition of the volt? (c) What does the term cell potential mean?

Short Answer

Expert verified
(a) Electromotive force (EMF) is the energy per unit charge supplied by a power source to drive the flow of electrical charges through a circuit. (b) A volt (V) is the SI unit of electric potential difference, defined as the potential difference when 1 joule of energy is expended to move 1 coulomb of charge, expressed as 1 V = 1 J/C. (c) Cell potential refers to the difference in electrical potential between the two electrodes of an electrochemical cell, representing the driving force for the spontaneous flow of electrons, generating a flow of electric current.

Step by step solution

01

(a) Electromotive Force Definition

Electromotive force, often abbreviated as EMF, is the energy per unit charge that is supplied by a power source, such as a battery or generator, to drive the flow of electrical charges (electrons) through an electrical circuit. In other words, EMF is the force responsible for pushing the charges to create an electric current in a circuit.
02

(b) Definition of the Volt

The volt (symbolized by the letter "V") is the SI unit of electric potential difference or voltage. One volt is defined as the potential difference between two points in an electric circuit when one joule of energy is expended to move a charge of one coulomb from one point to another. Mathematically, 1 V = 1 J/C.
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(c) Cell Potential Definition

Cell potential, also known as cell voltage or cell EMF, refers to the difference in electrical potential between the two electrodes of an electrochemical cell, such as a galvanic or voltaic cell. It represents the driving force that causes the spontaneous flow of electrons from the anode (negative electrode) to the cathode (positive electrode) through an external circuit, thereby generating a flow of electric current.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Volt
The volt is an essential concept in understanding electromotive force and electrical circuits. It is the standard unit of measurement for electric potential difference or voltage in the International System of Units (SI). The volt measures the potential energy per unit charge available to cause current to flow between two points in a circuit.
When we say that there is a voltage of one volt between two points, it means that one joule of energy is used to move a charge of one coulomb between those points. This relationship can be expressed with the formula:
  • 1 Volt = 1 Joule/Coulomb (1 V = 1 J/C)
This formula helps us quantify how much work is done when the charge moves through a potential difference. The volt is denoted by the symbol "V" and forms the basis for understanding how batteries and power sources activate devices by creating a potential difference.
Cell Potential
Cell potential, also known as cell voltage or electromotive force (EMF), is crucial in electrochemistry. It refers to the voltage difference between two electrodes in an electrochemical cell. This difference is what drives the spontaneous flow of electrons from the anode to the cathode.
An electrochemical cell consists of two different metal electrodes immersed in electrolyte solutions. The cell potential is measured in volts and indicates the tendency of a chemical reaction to occur, which generates electricity. This potential represents the ability of the cell to push electric charges through an external circuit.
Factors affecting cell potential include
  • The nature of the metals used
  • Concentration of the electrolyte solutions
  • Temperature of the environment
Understanding cell potential is key to harnessing electrochemical processes in batteries and fuel cells, which convert chemical energy into electrical energy efficiently.
Electric Current
Electric current is the flow of electric charge through a conductor, such as a wire. It is a fundamental concept in electronics and electrical engineering. Electric current is measured in amperes (A), where one ampere represents the movement of one coulomb of charge per second.
An electric current is typically generated when there is a potential difference, or voltage, present across two points. The electric field created by this difference causes charges, usually electrons, to move from areas of higher potential to lower potential. This movement is what constitutes the current flow.
Several factors influence the magnitude of electric current:
  • The voltage applied across the circuit
  • The resistance offered by the materials in the circuit
  • The temperature of the conductive materials
Understanding electric current is essential for designing and analyzing circuits, as it dictates how devices consume and operate on electrical energy.
Electrochemical Cell
An electrochemical cell is a device that generates electrical energy from chemical reactions. It consists of two electrodes, called the anode and cathode, and an electrolyte solution that allows ions to move between the electrodes. Electrochemical cells are divided into two categories: galvanic (or voltaic) cells and electrolytic cells.
Galvanic Cells:
  • These cells generate electrical energy through spontaneous redox reactions.
  • Commonly used in batteries to power devices.
Electrolytic Cells:
  • Use electrical energy to drive non-spontaneous chemical reactions.
  • Employed in processes like electroplating and electrolysis.
The operation of an electrochemical cell is based on the principle of turning chemical energy into electrical energy or vice versa. This conversion makes them vital components in a variety of applications, from energy storage systems to material processing. Understanding the components and functionality of these cells is important for innovating energy solutions.

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Most popular questions from this chapter

(a) Write the anode and cathode reactions that cause the corrosion of iron metal to aqueous iron(II). (b) Write the balanced half-reactions involved in the air oxidation of \(\mathrm{Fe}^{2+}(a q)\) to \(\mathrm{Fe}_{2} \mathrm{O}_{3} \cdot 3 \mathrm{H}_{2} \mathrm{O}\)

From each of the following pairs of substances, use data in Appendix \(\mathrm{E}\) to choose the one that is the stronger oxidizing agent: (a) \(\mathrm{Cl}_{2}(g)\) or \(\mathrm{Br}_{2}(l)\) (b) \(\mathrm{Zn}^{2+}(a q)\) or \(\mathrm{Cd}^{2+}(a q)\) (c) \(\mathrm{BrO}_{3}^{-}(a q)\) or \(\mathrm{IO}_{3}^{-}(a q)\) (d) \(\mathrm{H}_{2} \mathrm{O}_{2}(a q)\) or \(\mathrm{O}_{3}(g)\)

Complete and balance the following half-reactions. In each case indicate whether the half-reaction is an oxidation or a reduction. (a) \(\mathrm{Mo}^{3+}(a q) \longrightarrow \mathrm{Mo}(s)\) (acidic or basic solution) (b) \(\mathrm{H}_{2} \mathrm{SO}_{3}(a q)-\rightarrow \mathrm{SO}_{4}{ }^{2-}(a q)\) (acidic solution) (c) \(\mathrm{NO}_{3}^{-}(a q)-\cdots \operatorname{NO}(g)\) (acidic solution) (d) \(\mathrm{O}_{2}(g) \rightarrow-\rightarrow \mathrm{H}_{2} \mathrm{O}(l)\) (acidic solution) (e) \(\mathrm{Mn}^{2+}(a q)-\rightarrow \mathrm{MnO}_{2}(s)\) (basic solution) (f) \(\mathrm{Cr}(\mathrm{OH})_{3}(s)-\longrightarrow \mathrm{CrO}_{4}{ }^{2-}(a q)\) (basic solution) (g) \(\mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)\) (basic solution)

A common shorthand way to represent a voltaic cell is to list its components as follows: anode|anode solution || cathode solution|cathode A double vertical line represents a salt bridge or a porous barrier. A single vertical line represents a change in phase, such as from solid to solution. (a) Write the half-reactions and overall cell reaction represented by \(\mathrm{Fe}\left|\mathrm{Fe}^{2+} \| \mathrm{Ag}^{+}\right| \mathrm{Ag}\); sketch the cell. (b) Write the half-reactions and overall cell reaction represented by \(\mathrm{Zn}\left|\mathrm{Zn}^{2+} \| \mathrm{H}^{+}\right| \mathrm{H}_{2} ;\) sketch the cell. (c) Using the notation just described, represent a cell based on the following reaction: $$ \begin{aligned} \mathrm{ClO}_{3}^{-}(a q)+3 \mathrm{Cu}(s)+& 6 \mathrm{H}^{+}(a q)--\rightarrow \\ & \mathrm{Cl}^{-}(a q)+3 \mathrm{Cu}^{2+}(a q)+3 \mathrm{H}_{2} \mathrm{O}(l) \end{aligned} $$ \(\mathrm{Pt}\) is used as an inert electrode in contact with the \(\mathrm{ClO}_{3}^{-}\) and \(\mathrm{Cl}^{-}\). Sketch the cell.

Using data in Appendix \(\mathrm{E}\), calculate the standard emf for each of the following reactions: (a) \(\mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \longrightarrow 2 \mathrm{H}^{+}(a q)+2 \mathbf{F}^{-}(a q)\) (b) \(\mathrm{Cu}^{2+}(a q)+\mathrm{Ca}(\mathrm{s}) \longrightarrow \mathrm{Cu}(s)+\mathrm{Ca}^{2+}(a q)\) (c) \(3 \mathrm{Fe}^{2+}(a q) \longrightarrow \mathrm{Fe}(s)+2 \mathrm{Fe}^{3+}(a q)\) (d) \(\mathrm{Hg}_{2}{ }^{2+}(a q)+2 \mathrm{Cu}^{+}(a q) \longrightarrow 2 \mathrm{Hg}(l)+2 \mathrm{Cu}^{2+}(a q)\)

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