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Name each of the following oxides. Assuming that the compounds are ionic, what charge is associated with the metallic element in each case? (a) \(\mathrm{NiO}\), (b) \(\mathrm{MnO}_{2}\), (c) \(\mathrm{Cr}_{2} \mathrm{O}_{3}\), (d) \(\mathrm{MoO}_{3}\).

Short Answer

Expert verified
(a) Nickel(II) oxide, where nickel has a charge of +2. (b) Manganese(IV) oxide, where manganese has a charge of +4. (c) Chromium(III) oxide, where each chromium ion has a charge of +3. (d) Molybdenum(VI) oxide, where molybdenum has a charge of +6.

Step by step solution

01

(a) Identifying the metal and naming NiO

The metallic element in this case is nickel (Ni). Since oxygen has a -2 oxidation state, the charge on the nickel ion must be +2 to balance the charges. Therefore, the name of \(\mathrm{NiO}\) is "Nickel(II) oxide".
02

(b) Identifying the metal and naming MnO2

The metallic element in this case is manganese (Mn). Each oxygen ion has a -2 oxidation state, and as there are two oxygen ions, the total negative charge is -4. To balance this charge, manganese must have a +4 charge. Therefore, the name of \(\mathrm{MnO}_{2}\) is "Manganese(IV) oxide".
03

(c) Identifying the metal and naming Cr2O3

The metallic element in this case is chromium (Cr). Each oxygen ion has a -2 oxidation state, and as there are three oxygen ions, the total negative charge is -6. As there are two chromium ions, each chromium ion must have a +3 charge to balance the total negative charge. Therefore, the name of \(\mathrm{Cr}_{2} \mathrm{O}_{3}\) is "Chromium(III) oxide".
04

(d) Identifying the metal and naming MoO3

The metallic element in this case is molybdenum (Mo). Each oxygen ion has a -2 oxidation state, and as there are three oxygen ions, the total negative charge is -6. To balance this charge, molybdenum must have a +6 charge. Therefore, the name of \(\mathrm{MoO}_{3}\) is "Molybdenum(VI) oxide".

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
In chemistry, oxidation states, also known as oxidation numbers, are very important. They help us determine how elements combine and interact in compounds. An oxidation state is a hypothetical charge that an atom would have if all bonds to atoms of different elements were fully ionic. It helps us keep track of electrons in a reaction.

For example, in oxides, oxygen typically has an oxidation state of -2. When naming ionic compounds, it’s crucial to consider the oxidation states of each element involved. This is because the overall charge in a stable ionic compound must be zero.
  • In NiO, nickel must have an oxidation state of +2 to balance out the -2 from oxygen.
  • For MnO₂, manganese needs a +4 oxidation state since there are two oxygens, each with -2.
  • When it comes to Cr₂O₃, each chromium must be +3 as there are three oxygens generating a charge of -6.
  • In MoO₃, molybdenum balances three oxygens, leading it to have a +6 oxidation state.
Understanding these states helps in naming the compounds accurately, reflecting the specific charges of the metallic elements.
Metallic Elements
Metallic elements play a vital role in forming ionic compounds such as oxides. These are generally metals from the d-block of the periodic table, also known as transition metals. They can have various oxidation states, making it necessary to understand their specific charges in different compounds.

Transition metals like nickel, manganese, chromium, and molybdenum, as found in the given oxides, have the ability to form different ions based on the compound they are in. This versatile nature stems from their ability to use d-orbitals for bonding. These d-orbitals allow them to have multiple stable ionic forms, contributing to the rich chemistry of transition metals.
  • Nickel in NiO adopts a +2 oxidation state as it forms Nickel(II) oxide.
  • Manganese forms a +4 ion in MnO₂, hence it is Manganese(IV) oxide.
  • Chromium takes a +3 state in Cr₂O₃, which is Chromium(III) oxide.
  • Molybdenum in MoO₃ carries a +6 state, leading to Molybdenum(VI) oxide.
Recognizing the changes in these oxidation states is vital for correctly naming each compound.
Balancing Charges
Balancing charges is a fundamental aspect of forming stable ionic compounds. In these scenarios, the total positive charge must equal the total negative charge, ensuring the compound as a whole is electrically neutral.

When naming ionic compounds like the oxides discussed, it’s necessary to balance the charges of the metallic and non-metallic ions. Oxygen consistently presents a -2 charge in oxides. Hence, the metallic elements must adjust their charges accordingly:
  • In NiO, nickel balances a single oxygen with its +2 charge.
  • In MnO₂, two oxygen ions at -2 each sum to -4, requiring manganese to be +4.
  • For Cr₂O₃, three oxygens lead to a -6 charge, balanced by two chromiums each at +3.
  • In MoO₃, three oxygens total to a -6 charge, which molybdenum offsets with a +6 charge.
The principle of charge balancing is what ensures the stability and accurate naming of ionic compounds. Paying attention to this aspect simplifies the understanding of ionic compound formulas.

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Most popular questions from this chapter

From the following list of elements \(-\mathrm{Ar}, \mathrm{H}, \mathrm{Ga}, \mathrm{Al}, \mathrm{Ca}\), \(\mathrm{Br}, \mathrm{Ge}, \mathrm{K}, \mathrm{O}-\) pick the one that best fits each description. Use each element only once: (a) an alkali metal, (b) an alkaline earth metal, (c) a noble gas, (d) a halogen, (e) a metalloid, (f) a nonmetal listed in group \(1 \mathrm{~A},(\mathrm{~g})\) a metal that forms a \(3+\) ion, \((h)\) a nonmetal that forms a \(2-\) ion, (i) an element that resembles aluminum.

How did Rutherford interpret the following observations made during his \(\alpha\) -particle scattering experiments? (a) Most \(\alpha\) particles were not appreciably deflected as they passed through the gold foil. (b) A few \(\alpha\) particles were deflected at very large angles. (c) What differences would you expect if beryllium foil were used instead of gold foil in the \(\alpha\) -particle scattering experiment?

Determine whether each of the following statements is true or false. If false, correct the statement to make it true: (a) The nucleus has most of the mass and comprises most of the volume of an atom; (b) every atom of a given element has the same number of protons; (c) the number of electrons in an atom equals the number of neutrons in the atom; (d) the protons in the nucleus of the helium atom are held together by a force called the strong nuclear force.

Mass spectrometry is more often applied to molecules than to atoms. We will see in Chapter 3 that the molecular weight of a molecule is the sum of the atomic weights of the atoms in the molecule. The mass spectrum of \(\mathrm{H}_{2}\) is taken under conditions that prevent decomposition into \(\mathrm{H}\) atoms. The two naturally occurring isotopes of hydrogen are \({ }^{1} \mathrm{H}\) (atomic mass \(=1.00783\) amu; abundance \(99.9885 \%\) ) and \({ }^{2} \mathrm{H}\) (atomic mass \(=2.01410 \mathrm{amu}\); abundance \(0.0115 \%\). (a) How many peaks will the mass spectrum have? (b) Give the relative atomic masses of each of these peaks. (c) Which peak will be the largest, and which the smallest?

An \(\alpha\) particle is the nucleus of an \({ }^{4} \mathrm{He}\) atom. (a) How many protons and neutrons are in an \(\alpha\) particle? (b) What force holds the protons and neutrons together in the \(\alpha\) particle? (c) What is the charge on an \(\alpha\) particle in units of electronic charge? (d) The charge- to-mass ratio of an \(\alpha\) particle is \(4.8224 \times 10^{4} \mathrm{C} / \mathrm{g}\). Based on the charge on the particle, calculate its mass in grams and in amu. (e) By using the data in Table 2.1, compare your answer for part (d) with the sum of the masses of the individual subatomic particles. Can you explain the difference in mass? (If not, we will discuss such mass differences further in Chapter 21.)

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