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Although \(\mathrm{HCl}\) and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) have very different properties as pure substances, their aqueous solutions possess many common properties. List some general properties of these solutions, and explain their common behavior in terms of the species present.

Short Answer

Expert verified
The common properties of aqueous solutions of \(\mathrm{HCl}\) and \(\mathrm{H}_2\mathrm{SO}_4\) include a sour taste, color change in indicators, reaction with metals to produce hydrogen gas, strong electrolyte behavior, and neutralization of basic solutions. These properties can be attributed to the presence and behavior of hydrogen ions (\(\mathrm{H}^{+}\)) in the solutions. The dissociation reactions of these acids in water produce \(\mathrm{H}^{+}\) ions, which are responsible for the observed chemical properties of the acid solutions.

Step by step solution

01

Identify properties of \(\mathrm{HCl}\) and \(\mathrm{H}_2\mathrm{SO}_4\) solutions

First, let's list some general properties that aqueous solutions of \(\mathrm{HCl}\) and \(\mathrm{H}_2\mathrm{SO}_4\) share: 1. Both solutions have a sour taste. 2. They can change the color of certain indicators (e.g., turn blue litmus paper red). 3. They react with metals to produce hydrogen gas. 4. Both are strong electrolytes in solution, meaning they dissolve into ions and conduct electricity. 5. They neutralize basic solutions to form salts and water.
02

Determine the species present in the solutions

When these acids dissolve in water, the following dissociation reactions occur: 1. For \(\mathrm{HCl}\): \(\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{H}^{+}(\mathrm{aq}) + \mathrm{Cl}^{-}(\mathrm{aq})\) 2. For \(\mathrm{H}_2\mathrm{SO}_4\): \(\mathrm{H}_2\mathrm{SO}_4(\mathrm{aq}) \rightarrow 2\mathrm{H}^{+}(\mathrm{aq}) + \mathrm{SO}_4^{2-}(\mathrm{aq})\) In both reactions, there is a common species produced: the hydrogen ion, \(\mathrm{H}^{+}\).
03

Relate the properties to the common species

Now that we know that both solutions produce a common species (\(\mathrm{H}^{+}\)), we can explain their common properties: 1. The sour taste is a characteristic of acidic solutions, which is due to the presence of hydrogen ions. 2. The color change in indicators is due to the transfer of a proton, \( \mathrm{H}^+ \), from the acid to the indicator, which changes its structure and subsequently its color. 3. When an acid reacts with a metal, hydrogen gas is produced as hydrogen ions (\(\mathrm{H}^{+}\)) are supplied by the acidic solution and combined with metal atoms to form hydrogen molecules, \(\mathrm{H}_2\mathrm{(g)}\). 4. Both solutions are strong electrolytes because the dissociation reactions of \(\mathrm{HCl}\) and \(\mathrm{H}_2\mathrm{SO}_4\) produce ions, which increase the electrical conductivity of the solution. 5. The neutralization process occurs as \(\mathrm{H}^{+}\) ions from the acidic solution react with \(\mathrm{OH}^{-}\) ions from the basic solution to form water, with the remaining ions forming salts. This common behavior is due to the presence of \(\mathrm{H}^{+}\) ions in both acid solutions. In conclusion, the common properties of \(\mathrm{HCl}\) and \(\mathrm{H}_2\mathrm{SO}_4\) solutions are attributed to the presence and behavior of hydrogen ions (\(\mathrm{H}^{+}\)) in the solutions. The chemical properties of these acid solutions are determined by the presence and interactions of \(\mathrm{H}^{+}\) ions.

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Most popular questions from this chapter

At the freezing point of water \(\left(0^{\circ} \mathrm{C}\right), K_{w}=1.2 \times 10^{-15}\). Calculate \(\left[\mathrm{H}^{+}\right]\) and \(\left[\mathrm{OH}^{-}\right]\) for a neutral solution at this temperature.

Write the chemical equation and the \(K_{b}\) expression for the reaction of each of the following bases with water: (a) propylamine, \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{NH}_{2}\); (b) monohydrogen phosphate ion, \(\mathrm{HPO}_{4}{ }^{2-} ;\) (c) benzoate ion, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2}^{-}\)

In many reactions the addition of \(\mathrm{AlCl}_{3}\) produces the same effect as the addition of \(\mathrm{H}^{+} .\) (a) Draw a Lewis structure for \(\mathrm{AlCl}_{3}\) in which no atoms carry formal charges, and determine its structure using the VSEPR method. (b) What characteristic is notable about the structure in part (a) that helps us understand the acidic character of \(\mathrm{AlCl}_{3} ?\) (c) Predict the result of the reaction between \(\mathrm{AlCl}_{3}\) and \(\mathrm{NH}_{3}\) in a solvent that does not participate as a reactant. (d) Which acid-base theory is most suitable for discussing the similarities between \(\mathrm{AlCl}_{3}\) and \(\mathrm{H}^{+}\) ?

Lactic acid, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\), received its name because it is present in sour milk as a product of bacterial action. It is also responsible for the soreness in muscles after vigorous exercise. (a) The \(\mathrm{pK}_{a}\) of lactic acid is \(3.85\). Compare this with the value for propionic acid \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}, \mathrm{p} K_{a}=4.89\right)\), and explain the differ- ence. (b) Calculate the lactate ion concentration in a \(0.050 \mathrm{M}\) solution of lactic acid. (c) When a solution of sodium lactate, \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COONa}\), is mixed with an aqueous copper(II) solution, it is possible to obtain a solid salt of copper(II) lactate as a blue-green hydrate, \(\left(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COO}\right)_{2} \mathrm{Cu} \cdot x \mathrm{H}_{2} \mathrm{O} .\) Elemental analysis of the solid tells us that the solid is \(22.9 \% \mathrm{Cu}\) and \(26.0 \% \mathrm{C}\) by mass. What is the value for \(x\) in the formula for the hydrate? (d) The acid-dissociation constant for the \(\mathrm{Cu}^{2+}(a q)\) ion is \(1.0 \times 10^{-8}\). Based on this value and the acid-dissociation constant of lactic acid, predict whether a solution of copper(II) lactate will be acidic, basic, or neutral. Explain your answer.

The amino acid glycine \(\left(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\right)\) can participate in the following equilibria in water: $$ \begin{aligned} \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons & \\ \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-}+\mathrm{H}_{3} \mathrm{O}^{+} & K_{a}=4.3 \times 10^{-3} \\ \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons & \\ { }^{+} \mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}+\mathrm{OH}^{-} & K_{b}=6.0 \times 10^{-5} \end{aligned} $$ (a) Use the values of \(K_{a}\) and \(K_{b}\) to estimate the equilibrium constant for the intramolecular proton transfer to form a zwitterion: $$ \mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH} \rightleftharpoons{ }^{+} \mathrm{H}_{3} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COO}^{-} $$ What assumptions did you need to make? (b) What is the \(\mathrm{pH}\) of a \(0.050 \mathrm{M}\) aqueous solution of glycine? (c) What would be the predominant form of glycine in a solution with pH 13? With pH 1?

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