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(a) In which of the following reactions would you expect the orientation factor to be least important in leading to reaction? \(\mathrm{NO}+\mathrm{O} \longrightarrow \mathrm{NO}_{2}\) or \(\mathrm{H}+\mathrm{Cl} \longrightarrow \mathrm{HCl} ?\) (b) How does the kinetic-molecular theory help us understand the temperature dependence of chemical reactions?

Short Answer

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(a) The orientation factor is less important for the first reaction \(NO + O \rightarrow NO_2\) as the reactants are relatively simple and do not require specific alignment compared to the second reaction \(H + Cl \rightarrow HCl\). (b) The kinetic-molecular theory helps us understand the temperature dependence of chemical reactions as it states that gas particles are in constant random motion. As temperature increases, particles' kinetic energy also increases, leading to more effective collisions and an increased rate of reaction. Higher temperatures also allow particles to overcome activation energy more easily, making reactions more likely to occur.

Step by step solution

01

(Step 1: Understanding Orientation Factors)

Orientation factor refers to the importance of how reactant molecules must be oriented to effectively collide and form products. In a reaction, the orientation factor is more significant if the reactants are more complex or if there's a specific alignment needed for the reaction to proceed.
02

(Step 2: Compare the Orientation Factors in given reactions)

In the first reaction, nitrogen monoxide (NO) reacts with oxygen (O) to form nitrogen dioxide (NO₂). The reactants are relatively simple, and there is no specific alignment required for the reaction to proceed. In the second reaction, hydrogen (H) reacts with chlorine (Cl) to form hydrogen chloride (HCl). This reaction requires a specific alignment for the H-H bond and the Cl-Cl bond to break and form an H-Cl bond.
03

(Conclusion to Part A)

Since the first reaction (NO + O → NO₂) doesn't require specific alignment for the reactants, the orientation factor is expected to be less important for this reaction compared with the second reaction (H + Cl → HCl).
04

(Step 3: Understanding the Kinetic-Molecular Theory)

The kinetic-molecular theory states that the properties of gases can be explained by the motion of the ideal gas particles. The theory assumes that gas particles are in constant random motion, and their collisions cause an exchange of energy. As the temperature increases, the motion and kinetic energy of the particles also increase.
05

(Step 4: Explain Temperature Dependence of Reactions)

Chemical reactions involve collisions between particles with sufficient energy to overcome activation energy. The temperature dependence of chemical reactions can be understood through kinetic-molecular theory, as higher temperatures result in increased kinetic energy and more effective collisions between reactant molecules. This leads to an increased rate of reaction as the temperature rises. Also, higher temperatures can result in particles overcoming the required activation energy more easily, making the reaction more likely to occur.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic-Molecular Theory
The kinetic-molecular theory offers a fundamental explanation of how particles in gases behave. At its core, this theory posits that gas particles are small and in continuous, random motion. The theory highlights a few critical points that are important for understanding chemical reactions:

  • Particles of a gas move in straight lines until they collide with other particles or the walls of their container.
  • The collisions between gas particles are elastic, meaning no kinetic energy is lost in the collision, though energy can be transferred between particles.
  • The average kinetic energy of gas particles is proportional to the temperature of the gas in kelvins.

When considering chemical reactions, especially those occurring in the gaseous phase, this theory explains why certain reactions proceed more readily at higher temperatures. The energy of the particles increases with temperature, leading to more frequent and forceful collisions. These collisions are the beginning of most reactions, as they can disrupt chemical bonds and allow new bonds to form. Thus, kinetic-molecular theory not only gives us a model for ideal gas behavior but also bridges an understanding of how temperature affects molecular motion and reaction rates.
Temperature Dependence of Chemical Reactions
Temperature is a driving force in chemical reactions, influencing the rate at which reactions occur. According to the kinetic-molecular theory, as the temperature increases, the kinetic energy of the particles also increases. But what does this mean in the context of chemical reactions?

A higher temperature results in more energetic particles. These particles move faster and collide more often, and with greater force. These energetic collisions can break existing chemical bonds, leading to the formation of new bonds as part of the reaction process. But that's not all—higher temperatures also affect how often particles collide in the correct orientation, an aspect already touched upon as the 'orientation factor' in our initial exercise.

In summary, the temperature's role in chemical reactions is multi-faceted:
  • It increases the average kinetic energy of particles, leading to more frequent and vigorous collisions.
  • It raises the proportion of particles that have enough energy to surpass the activation energy barrier, thus enabling the reaction to proceed.
  • It can increase the number of successful collisions, where reactants are in the right orientation to react.
Consequently, understanding the temperature dependence is crucial for predicting reaction behavior and for the strategic design of chemical processes and reactions in industrial and laboratory settings.
Activation Energy
Activation energy is a key concept in chemical kinetics, essential for understanding why and how reactions occur. Defined simply, it is the minimum amount of energy that reacting particles must possess for a reaction to take place. Picture activation energy as a hurdle in the path of the reactants: they must have enough kinetic energy to leap over this hurdle to transform into products.

Here's why activation energy is central to reactions:
  • It determines whether a collision between reactants will be successful in leading to a reaction.
  • Only a fraction of the reactant particles have enough energy to overcome this barrier at a given moment.
  • The distribution of kinetic energies among reactant particles means that, typically, only those with the highest energies at the 'tail' of the distribution can surpass the activation energy.
The role of temperature, as discussed earlier, also ties into the concept of activation energy. At higher temperatures, more particles will have energies exceeding the activation energy, making reactions more likely to proceed. When the temperature is sufficient to provide a significant number of particles with the required activation energy, the rate of the reaction increases, a concept that is both theoretically interesting and practically important in fields ranging from biochemistry to materials science.

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Most popular questions from this chapter

Consider the following reaction: $$ \mathrm{CH}_{3} \mathrm{Br}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{CH}_{3} \mathrm{OH}(a q)+\mathrm{Br}^{-}(a q) $$ The rate law for this reaction is first order in \(\mathrm{CH}_{3} \mathrm{Br}\) and first order in \(\mathrm{OH}^{-}\). When \(\left[\mathrm{CH}_{3} \mathrm{Br}\right]\) is \(5.0 \times 10^{-3} \mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]\) is \(0.050 \mathrm{M}\), the reaction rate at \(298 \mathrm{~K}\) is \(0.0432 \mathrm{M} / \mathrm{s}\) (a) What is the value of the rate constant? (b) What are the units of the rate constant? (c) What would happen to the rate if the concentration of \(\mathrm{OH}^{-}\) were tripled?

(a) The reaction \(\mathrm{H}_{2} \mathrm{O}_{2}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\frac{1}{2} \mathrm{O}_{2}(g)\), is first order. Near room temperature, the rate constant equals \(7.0 \times 10^{-4} \mathrm{~s}^{-1} .\) Calculate the half-life at this temperature. (b) At \(415^{\circ} \mathrm{C}\), \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}\) decomposes in the gas phase, \(\left(\mathrm{CH}_{2}\right)_{2} \mathrm{O}(g) \longrightarrow \mathrm{CH}_{4}(g)+\mathrm{CO}(g)\). If the reac- tion is first order with a half-life of \(56.3\) min at this temperature, calculate the rate constant in \(\mathrm{s}^{-1}\).

Consider the following reaction between mercury(II) chloride and oxalate ion: $$ 2 \mathrm{HgCl}_{2}(a q)+\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}(a q) \longrightarrow{ }_{2 \mathrm{Cl}^{-}(a q)}+2 \mathrm{CO}_{2}(g)+\mathrm{Hg}_{2} \mathrm{Cl}_{2}(s) $$ The initial rate of this reaction was determined for several concentrations of \(\mathrm{HgCl}_{2}\) and \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\), and the following rate data were obtained for the rate of disappearance of \(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\) \begin{tabular}{llll} \hline Experiment & {\(\left[\mathrm{HgCl}_{2}\right](M)\)} & {\(\left[\mathbf{C}_{2} \mathrm{O}_{4}{ }^{2-}\right](M)\)} & Rate \((M / \mathrm{s})\) \\ \hline 1 & \(0.164\) & \(0.15\) & \(3.2 \times 10^{-5}\) \\ 2 & \(0.164\) & \(0.45\) & \(2.9 \times 10^{-4}\) \\ 3 & \(0.082\) & \(0.45\) & \(1.4 \times 10^{-4}\) \\ 4 & \(0.246\) & \(0.15\) & \(4.8 \times 10^{-5}\) \\ \hline \end{tabular} (a) What is the rate law for this reaction? (b) What is the value of the rate constant? (c) What is the reaction rate when the concentration of \(\mathrm{HgCl}_{2}\) is \(0.100 \mathrm{M}\) and that of \(\left(\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}\right)\) is \(0.25 \mathrm{M}\), if the temperature is the same as that used to obtain the data shown?

Americium-241 is used in smoke detectors. It has a rate constant for radioactive decay of \(k=1.6 \times 10^{-3} \mathrm{yr}^{-1}\). By contrast, iodine- 125, which is used to test for thyroid functioning, has a rate constant for radioactive decay of \(k=0.011\) day \(^{-1} .\) (a) What are the half-lives of these two isotopes? (b) Which one decays at a faster rate? (c) How much of a \(1.00-\mathrm{mg}\) sample of either isotope remains after three half-lives?

The reaction \(2 \mathrm{ClO}_{2}(a q)+2 \mathrm{OH}^{-}(a q) \longrightarrow \mathrm{ClO}_{3}^{-}(a q)+\) \(\mathrm{ClO}_{2}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) was studied with the following results: \begin{tabular}{llll} \hline Experiment & {\(\left[\mathrm{ClO}_{2}\right](M)\)} & {\(\left[\mathrm{OH}^{-}\right](M)\)} & Rate \((M / \mathrm{s})\) \\ \hline 1 & \(0.060\) & \(0.030\) & \(0.0248\) \\ 2 & \(0.020\) & \(0.030\) & \(0.00276\) \\ 3 & \(0.020\) & \(0.090\) & \(0.00828\) \\ \hline \end{tabular} (a) Determine the rate law for the reaction. (b) Calculate the rate constant. (c) Calculate the rate when \(\left[\mathrm{ClO}_{2}\right]=\) \(0.100 \mathrm{M}\) and \(\left[\mathrm{OH}^{-}\right]=0.050 \mathrm{M}\)

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