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Commercial concentrated aqueous ammonia is \(28 \% \mathrm{NH}_{3}\) by mass and has a density of \(0.90 \mathrm{~g} / \mathrm{mL}\). What is the molarity of this solution?

Short Answer

Expert verified
The molarity of the concentrated aqueous ammonia solution can be calculated as follows: 1. Mass of solution = \(0.90 \frac{\mathrm{g}}{\mathrm{mL}}\) × 1000 \(\mathrm{mL}\) = 900 g 2. Mass of \(\mathrm{NH}_{3}\) = 900 g × 28% = 252 g 3. Moles of \(\mathrm{NH}_{3}\) = \(\frac{252 \mathrm{~g}}{17 \mathrm{~g/mol}}\) = 14.82 moles 4. Molarity = \(\frac{14.82 \text{ moles}}{1 \text{ L}}\) = 14.82 M Therefore, the molarity of the concentrated aqueous ammonia solution is 14.82 M.

Step by step solution

01

Calculate the mass of \(\mathrm{NH}_{3}\) in 1 L of solution.

In order to accomplish this, we first need to find the mass of 1 L (1000 mL) of the solution. We can do this by multiplying the density of the solution by its volume: Mass of solution = Density × Volume Mass of solution = \(0.90 \frac{\mathrm{g}}{\mathrm{mL}}\) × 1000 \(\mathrm{mL}\) Next, we use the percentage composition of the solution to find the mass of \(\mathrm{NH}_{3}\) in it. To do this, we multiply the mass of the solution by the mass percentage of \(\mathrm{NH}_{3}\): Mass of \(\mathrm{NH}_{3}\) = Mass of solution × mass percentage of \(\mathrm{NH}_{3}\) Mass of \(\mathrm{NH}_{3}\) = Mass of solution × 28%
02

Convert the mass of \(\mathrm{NH}_{3}\) to moles.

To convert the mass of \(\mathrm{NH}_{3}\) to moles, we divide it by its molar mass: Moles of \(\mathrm{NH}_{3}\) = \(\frac{\text{Mass of }\mathrm{NH}_{3}}{\text{Molar mass of }\mathrm{NH}_{3}}\) Molar mass of \(\mathrm{NH}_{3}\) = 14 (N) + 3 × 1 (H) = 17 \(\mathrm{g/mol}\)
03

Calculate the molarity of the solution.

To find the molarity, we divide the moles of \(\mathrm{NH}_{3}\) by the volume of the solution in liters (since we are calculating the mass of the solution for 1 L): Molarity = \(\frac{\text{Moles of }\mathrm{NH}_{3}}{\text{Volume of solution}}\) Now, we can combine and calculate the steps above to find the molarity of the concentrated aqueous ammonia solution.

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Most popular questions from this chapter

Carbon disulfide \(\left(\mathrm{CS}_{2}\right)\) boils at \(46.30^{\circ} \mathrm{C}\) and has a density of \(1.261 \mathrm{~g} / \mathrm{mL}\) (a) When \(0.250 \mathrm{~mol}\) of a nondissociating solute is dissolved in \(400.0 \mathrm{~mL}\) of \(\mathrm{CS}_{2}\), the solution boils at \(47.46^{\circ} \mathrm{C}\). What is the molal boiling-point-elevation constant for \(\mathrm{CS}_{2} ?\) (b) When \(5.39 \mathrm{~g}\) of a nondissociating unknown is dissolved in \(50.0 \mathrm{~mL}\) of \(\mathrm{CS}_{2}\), the solution boils at \(47.08^{\circ} \mathrm{C}\). What is the molecular weight of the unknown?

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At ordinary body temperature \(\left(37^{\circ} \mathrm{C}\right)\) the solubility of \(\mathrm{N}_{2}\) in water in contact with air at ordinary atmospheric pressure \((1.0 \mathrm{~atm})\) is \(0.015 \mathrm{~g} / \mathrm{L}\). Air is approximately \(78 \mathrm{~mol} \% \mathrm{~N}_{2}\). Calculate the number of moles of \(\mathrm{N}_{2}\) dissolved per liter of blood, which is essentially an aqueous solution. At a depth of \(100 \mathrm{ft}\) in water, the pressure is \(4.0 \mathrm{~atm}\). What is the solubility of \(\mathrm{N}_{2}\) from air in blood at this pressure? If a scuba diver suddenly surfaces from this depth, how many milliliters of \(\mathrm{N}_{2}\) gas, in the form of tiny bubbles, are released into the bloodstream from each liter of blood?

The solubility of \(\mathrm{MnSO}_{4} \cdot \mathrm{H}_{2} \mathrm{O}\) in water at \(20{ }^{\circ} \mathrm{C}\) is \(70 \mathrm{~g}\) per \(100 \mathrm{~mL}\) of water. (a) \(\mathrm{ls}\) a \(1.22 \mathrm{M}\) solution of \(\mathrm{MnSO}_{4} \cdot \mathrm{H}_{2} \mathrm{O}\) in water at \(20^{\circ} \mathrm{C}\) saturated, supersaturated, or unsaturated? (b) Given a solution of \(\mathrm{MnSO}_{4} \cdot \mathrm{H}_{2} \mathrm{O}\) of unknown concentration, \(w\) hat experiment could you perform to determine whether the new solution is saturated, supersaturated, or unsaturated?

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