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By using estimation techniques, determine which of the following is the heaviest and which is the lightest: a 5-lb bag of potatoes, a \(5-\mathrm{kg}\) bag of sugar, or 1 gal of water (density \(=1.0 \mathrm{~g} / \mathrm{mL}\) ).

Short Answer

Expert verified
The heaviest item is the 5-kg bag of sugar, and the lightest item is the 5-lb bag of potatoes.

Step by step solution

01

Convert 5 lb of potatoes to kilograms

To convert pounds to kilograms, we can use the conversion factor: 1 pound ≈ 0.4536 kilograms. So, 5 pounds of potatoes can be converted to kilograms as: 5 lb × (0.4536 kg / 1 lb) ≈ 2.27 kg
02

Convert 1 gal of water to liters

To convert gallons to liters, we can use the conversion factor: 1 gallon ≈ 3.7854 liters. So, 1 gallon of water can be converted to liters as: 1 gal × (3.7854 L / 1 gal) ≈ 3.79 L
03

Calculate the weight of 1 gal of water in kilograms

We know the density of water is 1.0 g/mL, and 1 L of water is equal to 1,000 mL. Given 3.79 L of water, we can find the weight in grams and then convert it to kilograms by dividing by 1,000. 3.79 L × (1,000 mL / 1 L) × (1.0 g / 1 mL) ≈ 3,790 g To convert grams to kilograms, we can use the conversion factor: 1,000 g ≈ 1 kg. So, 3,790 g of water can be converted to kilograms as: 3,790 g × (1 kg / 1,000 g) ≈ 3.79 kg
04

Compare the weights of the three items

Now that we have all the weights in kilograms, we can compare them to determine the heaviest and lightest items. 5-lb bag of potatoes: 2.27 kg 5-kg bag of sugar: 5 kg 1 gal of water: 3.79 kg
05

Identify the heaviest and lightest items

Comparing the weights, we can determine that the 5-kg bag of sugar (5 kg) is the heaviest, and the 5-lb bag of potatoes (2.27 kg) is the lightest. So, the heaviest item is the 5-kg bag of sugar, and the lightest item is the 5-lb bag of potatoes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Understanding unit conversion is essential to compare measurements consistently in science, and particularly in chemistry. Converting units allows us to transform a quantity expressed in one system of measurement to another, using a conversion factor.

For instance, in the given exercise, to compare the weight of different items, we first need to convert their weights into a common unit. The conversion factor between pounds and kilograms is 1 lb \(\approx 0.4536\) kg. By multiplying the weight in pounds by this factor, we obtain its equivalent in kilograms.

This process was demonstrated when converting the 5 lb bag of potatoes to kilograms: \(5\) lb \(\times (0.4536\) kg / 1 lb) \(\approx 2.27\) kg. A similar process is applied to convert gallons to liters, another critical step in the given problem solving process.
Density Calculations
Density is a measure of how much mass is contained in a given volume and is crucial in identifying the quantity of matter present in a sample. The formula used to calculate density is: \[\text{Density} = \frac{\text{Mass}}{\text{Volume}}\]

In the exercise, the density of water is given as 1.0 g/mL, which simplifies the process as the mass is equal to the volume in milliliters. To find the total weight of 1 gallon of water in kilograms, we must first convert the gallon into liters, then into milliliters, and finally use the density to find the mass.

This operation involves sequential conversions using the given density, starting with volume in liters and ending with mass in kilograms. Specifically, \(3.79\) L of water was converted to grams and then to kilograms. It is important to know that such conversions and calculations are not just academic exercises; they have practical applications in daily life and professional science fields.
Mass and Weight Comparison
In physics, mass refers to the quantity of matter in an object, while weight is the force exerted by gravity on that mass. However, often in everyday language and even in scientific contexts, 'weight' can be used to mean 'mass', especially when gravity is assumed to be constant, as is the case on the surface of the Earth.

In the final steps of the solution, we compared the mass of three different items after they were all converted to the same unit (kilograms). This comparison is straightforward once the conversions are made: you line up the numbers and see which is greatest and which is smallest. The 5-kg bag of sugar is the heaviest at 5 kg, and, conversely, the 5-lb bag of potatoes is the lightest at approximately 2.27 kg.

Comparing mass or weight can be useful in many real-world situations, such as shipping, where costs may be based on weight, or cooking, where recipe ingredients must be measured precisely. Understanding how to compare weights after converting different units is an essential skill in these contexts.

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Most popular questions from this chapter

(a) To identify a liquid substance, a student determined its density. Using a graduated cylinder, she measured out a 45-mL sample of the substance. She then measured the mass of the sample, finding that it weighed \(38.5 \mathrm{~g}\). She knew that the substance had to be either isopropyl alcohol (density \(0.785 \mathrm{~g} / \mathrm{mL}\) ) or toluene (density \(0.866 / \mathrm{mL}\) ). What are the calculated density and the probable identity of the substance? (b) An experiment requires \(45.0 \mathrm{~g}\) of ethylene glycol, a liquid whose density is \(1.114 \mathrm{~g} / \mathrm{mL}\). Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume of the liquid should he use? (c) A cubic piece of metal measures \(5.00 \mathrm{~cm}\) on each edge. If the metal is nickel, whose density is \(8.90 \mathrm{~g} / \mathrm{cm}^{3}\), what is the mass of the cube?

What is meant by the terms composition and structure when referring to matter?

Perform the following conversions: (a) \(0.076 \mathrm{~L}\) to \(\mathrm{mL}\), (b) \(5.0 \times 10^{-8} \mathrm{~m}\) to \(\mathrm{nm}\), (c) \(6.88 \times 10^{5} \mathrm{~ns}\) to \(\mathrm{s}\), (d) \(0.50 \mathrm{lb}\) to \(\mathrm{g}\), (e) \(1.55 \mathrm{~kg} / \mathrm{m}^{3}\) to \(\mathrm{g} / \mathrm{L}\), (f) \(5.850 \mathrm{gal} / \mathrm{hr}\) to \(\mathrm{L} / \mathrm{s}\).

The Morgan silver dollar has a mass of \(26.73\) g. By law, it was required to contain \(90 \%\) silver, with the remainder being copper. (a) When the coin was minted in the late \(1800 \mathrm{~s}\), silver was worth \(\$ 1.18\) per troy ounce (31.1 g). At this price, what is the value of the silver in the silver dollar? (b) Today, silver sells for about \(\$ 13.25\) per troy ounce. How many Morgan silver dollars are required to obtain \(\$ 25.00\) worth of pure silver?

Gold can be hammered into extremely thin sheets called gold leaf. If a 200-mg piece of gold (density \(=19.32 \mathrm{~g} / \mathrm{cm}^{3}\) ) is hammered into a sheet measuring \(2.4 \times 1.0 \mathrm{ft}\), what is the average thickness of the sheet in meters? How might the thickness be expressed without exponential notation, using an appropriate metric prefix?

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