The structure of borazine, \(\mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6},\) is
a six-membered ring of alternating \(\mathrm{B}\) and \(\mathrm{N}\) atoms. There
is one \(\mathrm{H}\) atom bonded
to each \(\mathrm{B}\) and to each \(\mathrm{N}\) atom. The molecule is planar.
(a) Write a Lewis structure for borazine in which the formal charge on every
atom is zero. (b) Write a Lewis structure for borazine in which the octet rule
is satisfied for every atom. (c) What are the formal charges on the atoms in
the Lewis structure from part (b)? Given the electronegativities of
\(\mathrm{B}\) and \(\mathrm{N},\) do the formal charges seem favorable or
unfavorable? (d)Do either of the Lewis structures in parts (a) and (b) have
multiple resonance structures? (e) What are the hybridizations at the B and N
atoms in the Lewis structures from parts (a) and (b)? Would you expect the
molecule to be planar for both Lewis structures?
(f) The six \(B-N\) bonds in the borazine molecule are all identical in length
at 1.44 A. Typical values for the bond lengths of \(\mathrm{B}-\mathrm{N}\)
single and double bonds are 1.51 \(\mathrm{A}\) and \(1.31 \mathrm{A},\)
respectively. Does the value of the \(\mathrm{B}-\mathrm{N}\) bond
length seem to favor one Lewis structure over the other? (g) How many
electrons are in the \(\pi\) system of borazine?