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(a) Draw the Lewis structure for hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\) . (b) What is the weakest bond in hydrogen peroxide? (c) Hydrogen peroxide is sold commercially as an aqueous solution in brown bottles to protect it from light. Calculate the longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide.

Short Answer

Expert verified
The Lewis structure of hydrogen peroxide (H2O2) is: H - O - O - H : : : : The weakest bond is the O-O bond. To break it, the longest wavelength of light with sufficient energy required is approximately 202 nm.

Step by step solution

01

(a) Lewis Structure for Hydrogen Peroxide (H2O2)

H2O2 has a total of 12 valence electrons: 1 electron from each of the 2 hydrogen atoms and 6 electrons from each of the 2 oxygen atoms. The Lewis structure can be drawn as follows: 1. Connect the two oxygen atoms with a single bond (O-O) using 2 electrons. Now, each oxygen atom has 5 electrons around it. 2. Connect each hydrogen atom to a different oxygen atom using a single bond (H-O) using 2 more electrons for each bond. Now, each oxygen atom is connected to a hydrogen atom and has 6 electrons around it, while the hydrogen atoms have 2 electrons each. 3. Add lone pairs to both oxygen atoms to satisfy their octet needs. Each oxygen atom should have 2 lone pairs, using the remaining 4 valence electrons. The Lewis structure for hydrogen peroxide is: H - O - O - H : : : :
02

(b) Weakest Bond in Hydrogen Peroxide

In hydrogen peroxide, there are two types of bonds: O-O (oxygen-oxygen) and O-H (oxygen-hydrogen). The O-O bond is weaker than the O-H bond due to the larger size of the oxygen atoms and less effective overlap of their atomic orbitals resulting in lower bond dissociation energy. Therefore, the weakest bond in hydrogen peroxide is the O-O bond.
03

(c) Calculate the Longest Wavelength of Light to Break the Weakest Bond

To find the longest wavelength of light needed to break the O-O bond in hydrogen peroxide, we will use Planck's equation: \(E = h \cdot c / \lambda\) Where E is the energy required to break the bond, h is Planck's constant \((6.626 \times 10^{-34} Js)\), c is the speed of light \((2.998 \times 10^8 m/s)\), and \( \lambda \) is the wavelength of light. The bond dissociation energy of O-O bond in hydrogen peroxide is approximately 142 kcal/mol or 594 kJ/mol. To find the energy in joules per photon, we need to convert the energy into joules per photon. \(E_{photon} = 594,000 J/mol \times (1 mol/ 6.022 \times 10^{23} photons)\) = 9.869 x 10^{-19} J/photon Now, we plug the energy into the Planck's equation and solve for the wavelength: \( \lambda = h \cdot c / E_{photon}\) \( \lambda = \frac{(6.626 \times 10^{-34} Js)(2.998 \times 10^8 m/s)}{9.869 x 10^{-19} J/photon}\) \( \lambda \approx 2.02 \times 10^{-7}\, m = 202 \,nm\) The longest wavelength of light that has sufficient energy to break the weakest bond in hydrogen peroxide is approximately 202 nm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structure of H2O2
Understanding the Lewis structure of hydrogen peroxide (H2O2) is crucial for students who are delving into the world of molecular chemistry. The Lewis structure is a valuable tool that depicts the arrangement of atoms within a molecule and shows how they are bonded together.

The total count of valence electrons for H2O2 is determined by adding the electrons from hydrogen atoms to those from oxygen atoms. Each hydrogen atom contributes one electron, while each oxygen atom brings six. Now, the bonds are formed: each oxygen atom is connected to a hydrogen atom with a single bond, and the oxygen atoms themselves are connected by another single bond. After the bonds are set, leftover electrons are placed as lone pairs around the oxygen atoms to complete their octet, satisfying the rule that elements, except hydrogen, tend to fill their outer shell with eight electrons for stability.

It is important to note that the shapes of molecules can also influence the distribution of electrons, and learners should keep in mind that three-dimensional geometries can affect electron pair orientations. By effectively mastering the Lewis structure, students can predict molecular properties like shape, reactivity, and polarity.
Bond Dissociation Energy
Grasping the concept of bond dissociation energy helps to understand the stability of different bonds within a molecule. In hydrogen peroxide, there are two types of bonds: O-H and O-O. The O-O bond is considered the weaker link compared to the more robust O-H bond.

This difference in stability is explained by bond dissociation energy, which is the amount of energy needed to break a bond between two atoms in a molecule. For the O-O bond in hydrogen peroxide, a lower bond dissociation energy implies that it takes less energy to break this bond as compared to breaking the O-H bond. The concept of bond dissociation energy not only gives insights into the chemical reactivity of molecules but also influences how substances are stored. For instance, hydrogen peroxide is kept in dark containers to prevent light-induced breakdown of the fragile O-O bond due to its lower bond dissociation energy.

Students must comprehend that bond stability is a key factor in determining molecular behavior and reactivity, which can be invaluable in predicting reactions and designing new compounds in chemistry.
Wavelength Calculation to Break Chemical Bonds
The interplay between the energy of light and chemical bonds is a fascinating aspect in chemistry, particularly when discussing how light can induce bond cleavage. To understand which light can break a bond, one must learn to calculate the wavelength of light required using the conceptual framework of energy quantization.

To break a chemical bond, the light must provide an amount of energy that meets or exceeds the bond dissociation energy. By using Planck's equation, we can relate the energy of a photon (the smallest unit of light) to its wavelength. The calculation involves Planck's constant and the speed of light to determine that longest wavelength of light capable of breaking the bond. Students can better understand the electromagnetic spectrum and how different wavelengths correspond to different energies. In the case of hydrogen peroxide, the wavelength calculated at approximately 202 nm falls within the ultraviolet range, indicating that UV light is energetic enough to break the O-O bond.

This understanding is not just theoretical but has practical implications in various fields including chemistry, physics, and materials science. Knowing how to calculate wavelengths for bond breakage can aid students in designing experiments and understanding how substances interact with light.

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Most popular questions from this chapter

Consider the formate ion, \(\mathrm{HCO}_{2}^{-},\) which is the anion formed when formic acid loses an \(\mathrm{H}^{+}\) ton. The \(\mathrm{H}\) and the two O atoms are bonded to the central \(\mathrm{C}\) atom. (a) Draw the best Lewis structure(s) for this ion. (b) Are resonance structures needed to describe the structure? (c) Would you predict that the \(\mathrm{C}-\mathrm{O}\) bond lengths in the formate ion would be longer or shorter relative to those in \(\mathrm{CO}_{2} ?\)

Ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl},\) is a very soluble salt in water. (a) Draw the Lewis structures of the ammonium and chloride ions. (b) Is there an \(\mathrm{N}-\) Cl bond in solid ammonium chloride? (c) If you dissolve 14 gof ammonium chloride in 500.0 \(\mathrm{mL}\) of water, what is the molar concentration of the solution? (d) How many grams of silver nitrate do you need to add to the solution in part (c) to precipitate all of the chloride as silver chloride?

(a) Using Lewis symbols, diagram the reaction between magnesium and oxygen atoms to give the ionic substance MgO. (b) How many electrons are transferred? (c) Which atom loses electrons in the reaction?

Draw the Lewis structures for each of the following molecules or ions. Identify instances where the octet rule is not obeyed; state which atom in each compound does not follow the octet rule; and state how many electrons surround these atoms: (a) \(\mathrm{NO},(\mathbf{b}) \mathrm{BF}_{3},(\mathbf{c}) \mathrm{ICl}_{2}^{-},(\mathbf{d}) \mathrm{OPBr}_{3}(\) the \(\mathrm{P}\) is the central atom), (e) XeF.

Predict the chemical formula of the ionic compound formed between the following pairs of elements: (a) Al and F, (b) K and \(S,(\mathbf{c}) \mathrm{Y}\) and \(\mathrm{O},(\mathbf{d}) \mathrm{Mg}\) and \(\mathrm{N} .\)

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