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Which of the following statements about effective nuclear charge for the outermost valence electron of an atom is incorrect? (i) The effective nuclear charge can be thought of as the true nuclear charge minus a screening constant due to the other electrons in the atom. (ii) Effective nuclear charge increases going left to right across a row of the periodic table. (iii) Valence electrons screen the nuclear charge more effectively than do core electrons. (iv) The effective nuclear charge shows a sudden decrease when we go from the end of one row to the beginning of the next row of the periodic table. (v) The change in effective nuclear charge going down a column of the periodic table is generally less than that going across a row of the periodic table.

Short Answer

Expert verified
Statement (iii) is incorrect, as core electrons, not valence electrons, screen the nuclear charge more effectively due to their closer proximity to the nucleus.

Step by step solution

01

Statement (i)

The effective nuclear charge can be thought of as the true nuclear charge minus a screening constant due to the other electrons in the atom. This statement is correct, as the effective nuclear charge is the net positive charge experienced by the valence electrons from the nucleus, after accounting for the shielding/screening effect of the inner core electrons.
02

Statement (ii)

Effective nuclear charge increases going left to right across a row of the periodic table. This statement is also correct. As we move left to right across a period, the number of protons in the nucleus increases, which in turn increases the nuclear charge. The increase in nuclear charge outweighs the shielding effect of increasing electrons, leading to a higher effective nuclear charge on the valence electrons.
03

Statement (iii)

Valence electrons screen the nuclear charge more effectively than do core electrons. This statement is incorrect. Core electrons (those closer to the nucleus) are generally more effective at shielding the nuclear charge, as they are located between the valence electrons and the nucleus. Valence electrons do not shield the nuclear charge as effectively as the core electrons because they are further from the nucleus and don't fully block the attraction between the nucleus and the valence electrons.
04

Statement (iv)

The effective nuclear charge shows a sudden decrease when we go from the end of one row to the beginning of the next row of the periodic table. This statement is correct. Going from the end of one period to the beginning of the next one, there is an addition of a new energy level (shell). This causes a noticeable shielding effect, indicating a sudden decrease in effective nuclear charge experienced by the valence electrons even though the number of protons has increased.
05

Statement (v)

The change in effective nuclear charge going down a column of the periodic table is generally less than that going across a row of the periodic table. This statement is correct. As we move down a column (group), the number of energy levels (shells) increases, which adds more shielding electrons. This increase in shielding outweighs the increase in nuclear charge, so there is a smaller change in effective nuclear charge when going down a column than when going across a row in the periodic table.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Shielding Effect
The shielding effect is a fundamental concept in atomic physics, referring to the reduction in the effective nuclear charge on the electron cloud due to the repulsion from electrons in lower energy levels. Imagine the nucleus of an atom as a powerful magnet and each electron as a mini shield, with core electrons acting as stronger shields than valence electrons.

Core electrons, being closer to the nucleus, shield valence electrons from the full effect of the nuclear charge. As you might picture, the inner-layered electrons intercept some of the 'magnetic pull' from the nucleus before it reaches the outermost electrons. It's like trying to hear someone across a crowded room; the more people (core electrons) between you, the less clearly you hear (less nuclear pull felt).

When considering the shielding effect, it's essential to remember that valence electrons, which are in the highest energy level, do not significantly shield each other from the nuclear charge.
Periodic Trends
Periodic trends are patterns observed within elements on the periodic table, which help predict an element's properties. Among these is atomic radius, ionization energy, electronegativity, and the topic at hand, effective nuclear charge.

As we move across a period (left to right) on the periodic table, the effective nuclear charge experienced by valence electrons increases. This is because while additional electrons are being added to the same energy level, the nucleus gains more protons, enhancing its pull on the electrons. Even as electrons 'shield' each other, the growing number of protons has a more robust ability to draw the outer electrons inwards, decreasing the atomic radius and increasing attraction in the atom.

Going Down a Group

Conversely, when descending down a group (top to bottom), each element acquires a new electron shell. This additional shell increases the distance from the nucleus and adds more shielding electrons, which almost dampens the effect of adding more protons. The result? There is less change in effective nuclear charge down a column compared to across a row. This helps explain why atoms generally get larger as you go down a group on the table.
Valence Electrons
Valence electrons are the electrons in the outermost shell of an atom. They are extremely important because they dictate how an atom will interact with others to form chemical bonds. If atomic behavior at parties were to be considered, valence electrons would be the social butterflies—they make the connections.

These electrons are also subjected to the effective nuclear charge, which influences their energy and reactivity. The fewer valence electrons compared to the available spaces in an atom's outer shell, the more reactive the atom tends to be.

Role in Chemical Bonding

For example, atoms strive for a full valence shell, often leading to the transfer or sharing of valence electrons to achieve stability, thus forming ionic or covalent bonds respectively. Understanding both the shielding effect and how it influences the effective nuclear charge helps provide insight into the atomic radius, ionization energy, and overall reactivity of an element based on its position on the periodic table.

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Most popular questions from this chapter

Write an equation for the second electron affinity of chlorine. Would you predict a positive or a negative energy value for this process? Is it possible to directly measure the second electron affinity of chlorine?

If the electron affinity for an element is a negative number, does it mean that the anion of the element is more stable than the neutral atom? Explain.

Detailed calculations show that the value of \(Z_{\text { eff }}\) for the outermost electrons in Si and Cl atoms is \(4.29+\) and \(6.12+\) , respectively.(a) What value do you estimate for \(Z\) eff experienced by the outermost electron in both Si and Cl by assuming core electrons contribute 1.00 and valence electrons contribute 0.00 to the screening constant? (b) What values do you estimate for \(Z_{\text { eff }}\) using Slater's rules? (c) Which approach gives a more accurate estimate of \(Z_{\text { eff? }} ?(\mathbf{d})\) Which method of approximation more accurately accounts for the steady increase in \(Z_{\text { eff }}\) that occurs upon moving left to right across a period? (e) Predict \(Z_{\text { eff }}\) for a valence electron in \(\mathrm{P}\) , phosphorus, based on the calculations for Si and Cl.

Mercury in the environment can exist in oxidation states 0, +1, and +2. One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury’s 4\(f\) orbitals at 105 eV, from an X-ray source that provided 1253.6 \(\mathrm{eV}\) of energy \(\left(1 \mathrm{ev}=1.602 \times 10^{-19} \mathrm{J}\right)\) The oxygen on the mineral surface gave emitted electron energies at \(531 \mathrm{eV},\) corresponding to the 1 \(\mathrm{s}\) orbital of oxygen. Overall the researchers concluded that oxidation states were \(+2\) for \(\mathrm{Hg}\) and \(-2\) for \(\mathrm{O}\) (a) Calculate the wavelength of the X rays used in this experiment. (b) Compare the energies of the 4f electrons in mercury and the 1s electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground- state electron configurations for \(\mathrm{Hg}^{2+}\) and \(\mathrm{O}^{2-} ;\) which electrons are the valence electrons in each case?

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Cesium is added to water. (b) Strontium is added to water. (c) Sodium reacts with oxygen. (d) Calcium reacts with iodine.

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