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Can you use an approach similar to Hess's law to calculate the change in internal energy, \(\Delta E,\) for an overall reaction by summing the \(\Delta E\) values of individual reactions that add up to give the desired overall reaction?

Short Answer

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Yes, you can use an approach similar to Hess's law to calculate the change in internal energy (\(\Delta E\)) for an overall reaction by summing the \(\Delta E\) values of individual reactions that add up to give the desired overall reaction. This is because both internal energy and enthalpy are state functions and path-independent, allowing their changes to be additive in a manner analogous to Hess's law for enthalpy.

Step by step solution

01

Understand the relationship between internal energy and enthalpy

The relationship between internal energy (\(E\)) and enthalpy (\(H\)) is given by the following equation: \[H = E + PV,\] where \(P\) is pressure, and \(V\) is volume. Both internal energy and enthalpy are state functions, which means their values depend on the initial and final states of the system and not on the path taken to reach those states.
02

Investigate the behavior of internal energy and enthalpy changes under path independence

Internal energy (\(\Delta E\)) is path-independent, and its value depends on the initial and final states of the system. During a reaction, the internal energy can undergo changes due to heat and work exchanges with the surroundings. Similarly, the change in enthalpy (\(\Delta H\)) is also path-independent. Under constant pressure, the change in enthalpy is equal to the heat exchange between the system and its surroundings. Because both internal energy and enthalpy are path-independent, their changes remain constant, regardless of the intermediate steps taken in a reaction. If a reaction occurs in multiple steps, the sum of the changes in internal energy or enthalpy of each step will result in the same change in internal energy or enthalpy for the overall reaction. Therefore, the additive nature of \(\Delta H\) described in Hess's law also applies to \(\Delta E\).
03

Conclude whether Hess's law-like approach is applicable to internal energy

In summary, since both internal energy (\(\Delta E\)) and enthalpy (\(\Delta H\)) are state functions and path-independent, an approach similar to Hess's law can be used to calculate the change in internal energy for an overall reaction by summing the \(\Delta E\) values of individual reactions that add up to give the desired overall reaction.

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Most popular questions from this chapter

Complete combustion of 1 mol of acetone \(\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}\right)\) liberates \(1790 \mathrm{kJ} :\) $$\begin{aligned} \mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(l)+4 \mathrm{O}_{2}(g) \longrightarrow & 3 \mathrm{CO}_{2}(g)+3 \mathrm{H}_{2} \mathrm{O}(l) \\ & \quad \quad \quad \quad \quad \quad \quad \Delta H^{\circ}=-1790 \mathrm{kJ} \end{aligned}$$ Using this information together with the standard enthalpies of formation of \(\mathrm{O}_{2}(g), \mathrm{CO}_{2}(g),\) and \(\mathrm{H}_{2} \mathrm{O}(l)\) from Appendix \(\mathrm{C},\) calculate the standard enthalpy of formation of acetone.

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